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Question

IheDeAuex ( Atrdtd [ox tbiescienList mcasures the standard enthalpy change for thc :followang ! Tcctozi beMU cole) I,O() C0.(p) H,(e)Bascd on dhis valuc and thc stindud ctthalpues of fottiation for (he othct substances_ KEnld cathalpy of foquuatlon of H;OXl) uUU tolKncltulnnurtUncddiditiairdtauHbia

IheDe Auex ( Atrdtd [ox tbie scienList mcasures the standard enthalpy change for thc :followang ! Tcctozi beMU cole) I,O() C0.(p) H,(e) Bascd on dhis valuc and thc stindud ctthalpues of fottiation for (he othct substances_ KEnld cathalpy of foquuatlon of H;OXl) u UU tol Kncltulnnurt Uncddiditiairdtau Hbia



Answers

Use the following themochemical equations to calculate the standard enthalpy change of formation of $\mathrm{HNO}_{3}(0)$ \[ \begin{aligned} \mathrm{H}_{2} \mathrm{O}_{2}\left(\mathrm{D}+2 \mathrm{NO}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{HNO}_{2}()\right.& \Delta_{4} H^{\circ} &=-226.8 \mathrm{kJ} \mathrm{mol}^{-1} \\ \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{O}_{2}(\mathrm{g}) \rightarrow 2 \mathrm{NO}_{2}(\mathrm{g}) & \Delta_{\mathrm{r}} H^{\circ} &=+66.4 \mathrm{kJ} \mathrm{mol}^{-1} \\ \mathrm{H}_{2}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \rightarrow \mathrm{H}_{2} \mathrm{O}_{2}(\mathrm{o}) & \Delta_{\mathrm{r}} \mathrm{H}^{\mathrm{e}} &=-187.8 \mathrm{kJ} \mathrm{mol}^{-1} \end{aligned} \] (Section $13.1)$

It's calculate the end to be of the following reactions. So we have p 406 solid to P four solid and 302 gas. So we're gonna flip it around. Therefore, adult age is 16. 40 0.1 killer jewels will inverse a sign on that. And then we will have our seconds. Um, reaction here before on five. To gas goes to P 40 10 solid Delta H here is negative. 29 40.1 Killer. Jules, we're gonna add these two together. P four will counsel that's so simplified it to. And I get P four 06 solid plus two to gas, which will produce P 410 solid Delta h here. By adding these two together, this will yield 1000 negative, 1000 300 killed jewels, and there's the Delta H or the given reaction

In this problem, we are given the in therapy change for a vapor rising water which is given every here. What is the Gibbs energy change for this process? The Gibbs energy change would be zero. This is because in a phase transition like water vapour rising, both of these phases will co exist at the same time and equilibrium. So the difference in the Gibbs free Energy is zero.

So I find it helpful to start by writing the equation I'm looking for. And then I'm going to take the equations they've given me and see if I can get them to add up to that equation that I want. Mm So the first equation has P406 in it. But it's a product. So I need to reverse that reaction Because I need p. on the reactant side. So I'm just gonna write that reaction backwards. But when I do that I have to take the delta H value Which was negative 16 40.1 Killer Jewels. And I have to change its sign. So now it will be positive. And then the second equation is written just as I need it. It has a p. four And 502 Which will give me the P4010 which I need on the right side. So that value for delta age I'm not going to change. And I'm just gonna write it just as it was given. So if I can show that these two equations add up to what I'm looking for, which I can so I'm going to read it three of those and I have to so that's the equation I'm looking for. Then I can also add the delta H. Is delta H. Is simply Those to add it up. So negative 1300, The 3rd 1300 killer jewels

Given that a plus B produced to see has Delta H equal to 600 killed jewels per mole and that to see plus DE to produce two e has adult each of 210 kill a Jules per mole. Let's determine the entropy change for each of the following for a four e Yeah, Thio foresee plus two d So we take to see Plus de put this to e Yeah, and we double that Delta each year is equal to two times 210 kill a Jules per mole, so this would be equal to four c plus two d is gonna be equal four e So Delta H here is equal to 420. Kill a Jules per mole and we're gonna flip this around. So four e produces foresee, and two D and Delta H years equals a negative 420 kill jewels per mole. So there is our answer for part a for part B a plus B plus de will produce two e and we need the entropy for this. So we know that a plus B to produce to see entropy here's equal to 600 killed jewels per mole and then to see plus de will produce two e. Delta H here is equal to 210 killer jewels per mole To see what council we would get a plus B plus D Do you produce to E and the Delta H share works out. Thio 810 Kill a Jules per mole. There's an answer for part B for C, we have see to produce one half a plus, one half be so if I take E plus B to produce to see and a half of this So the Delta H Year is equal to a half of that's 600 kill a Jules per mole. This is equal to half a plus a half B. Going to see Delta H here is equal to 300 killer jewels per mole. If we flip this around, see producer half a plus a half B. Delta H is equal to negative 300 kill a Jules per mole and there's our answer For part C for D, we have to see plus two e to produce to a plus to be plus de Okay, so this would yield right a plus B to produce to see we're gonna double this. So Delta H here is equal to two times 600 killer jewels per mole. So to a plus, to be to foresee Delta H years equals 1200 killer jewels promote and then we'll flip it around. Four c produced two A and two b Delta H year and sequel. The negative 1200 killer jewels per mole. And then we'll bring in to see Plus, de it would be equal Thio to e and we're gonna subtract. Well, Delta H here is equal to 2 10 killer jewels per mole and we're going to subtract thes so this would give us two C minus. D would produce to a plus to be minus two e delta H here would be equal to minus 14 10 killer jewels per mole. And then, if we rearrange here, this would be a to C plus two e would produce to a plus two B plus d. Delta H here is equal to minus 14 10 kill jewels. Permal. And here's our answer for part de and for E, we're going to determine the entropy change. E will produce a half a plus a half B plus a half de so starting from a plus B to produce to see Delta, each there to call the 600 killer jewels per mole and then to see plus DE to produce two e. Delta H here is equal to 10. Kill a Jules per mole. It's combined these together two seats for council we get a plus B plus D would be to e Delta eight shares equal to 810 killed jewels per mole. And if we take this and take half of this, we would get a half a plus a half B plus a half D on that would produce E. I thought the H here would be 405 killer jewels per mole. And then, if we flip this around, E would be producing half a plus a half B plus a half E and Delta H here would be negative 405 killer jewels per mole. There would be your answer for Part E. Yeah,


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