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Identify each of the following half-reactions as either an oxidation half-reaction or reduction half-reaction.half-reactionidentificationSn2t(aq) + 2e" ~Sn(s) ...

Question

Identify each of the following half-reactions as either an oxidation half-reaction or reduction half-reaction.half-reactionidentificationSn2t(aq) + 2e" ~Sn(s) Al(s) ~AF+ t(aq) + 3e"Write balanced equation for the overall redox reaction. Use smallest possible integer coefficients

Identify each of the following half-reactions as either an oxidation half-reaction or reduction half-reaction. half-reaction identification Sn2t(aq) + 2e" ~Sn(s) Al(s) ~AF+ t(aq) + 3e" Write balanced equation for the overall redox reaction. Use smallest possible integer coefficients



Answers

Classify each of the following half-equations as oxidation or reduction and balance. (a) (basic) $\quad \mathrm{ClO}^{-}(a q) \longrightarrow \mathrm{Cl}^{-}(a q)$ (b) (acidic) $\quad \mathrm{NO}_{3}^{-}(a q) \longrightarrow \mathrm{NO}(g)$ (c) (basic) $\mathrm{Ni}^{2+}(a q) \longrightarrow \mathrm{Ni}_{2} \mathrm{O}_{3}(s)$ (d) (acidic) $\quad \mathrm{Mn}^{2+}(a q) \longrightarrow \mathrm{MnO}_{2}(s)$

Answer for part A. We have a reaction in in il three bliss three electrons here. Oxidation number off oxidation. Number off. Alimony in a n change from zero to plus three. Loose off electron is oxidation. And hence here in this redox reaction, alimony, um, is in dogs off reaction and ammonium is oxidized. In the process is oxidation Unser for part B, the Iraq Redox off reaction is copper plus two. The less one electron copper class. When here in this reaction in this help reaction. Okay, oxidation number off. Copper change from plus two to plus one gain off electron. So it is a reduction. I'm hands. Yeah, copper is reduced in the process is reduction.

So we want to determine whether these reactions are oxidation, have reactions or reduction have reactions so helpful mnemonic. To remember this. Yes, oil rick, which stands for oxidation, is losing electrons, reduction is gaining electrons. If we're gaining electrons then electrons will be in our reactant. And if we're losing electrons they'll be products. So looking at our first example, we are losing electrons. Therefore this is oxidation. In our second example, we are gaining electrons, so this is a reduction.

Looking to balance out some Redox reactions. So with a Redox reaction that's broken down into an oxidation reaction and a reduction reaction. So within the oxidation reaction, we have the loss of electrons within a species and the reduction reaction we have The gain of electrons within a species so you can see, are those to come together in a relationship to form our redox reaction. So we're balancing out some equations here so fastly we have to a out in the solid state at three. We are, too, because we need six bro means in the liquid state, and that gives us to a L. We are three in the solid state. In the next example, we have C n solid states sink to H C L 04 Equus gives us see and Cielo for two in the acquis phase at age two in the gaseous phase, so that is balanced. Next we have part C. So we have three sodium in the solid state ad. Prosperous in the solid state gives us an A three p in the solid state. Next we have part D. So we have ch four in the gaze estate methane at four cl two in a gaseous state gives us c c l four So carbon tetrachloride in the liquid state at h C L. In the gaseous phase, we have full hcl. Next we have part E. So we have See you in the solid states Got copper up to a G and oh, three nucleus gives us see you and oh 32 in the bakery is phase at two a. G in the solid phase for our balanced equations.

In problem 16. Identify each off the following half reaction as either an oxidation half reaction or reduction, half reaction. So this question is taken from the topic Oxidation reduction, a Redox reaction and these two equations that is given in the question. And we also write a balance equation for the overall Redox reaction. So as we can see that in the first equation, one electron is lost and in the second equation, toe electrons is gained. So if we say this is the first equation and this is the second location, Okay, so in order to find the oxidation half reaction or addiction half reaction, so for us to follow, we can define the oxidation. So oxidation means laws off electrons, so laws off electrons is known as the oxidation. Or we can also define oxidation increase in oxidation number, so increase in oxidation number is also known as theocracy addition and reduction. We can define as the gain all flipped ones, so gain off electrons is known as reduction, or we can say their decrees in oxidation number. Okay, so that means oxidation and reduction are opposite to each other. Okay, so in the first case, as we can see that. So in the first equation, we can see that one electron is lost in this equation. And in the second occassion, two electrons are gained in this equation. So that means we can say that Equation one. So the equation one or the first equation is the oxidation half reaction. So the first equation is the oxidation half reaction. Because when electron is lost in this case, and also increasing observation number and equation toe or second equation is through the reduction half reaction. So this is the question that is asked and also writer balance equation for the overall Redox reaction. Okay, so we can explain it again so we can see that this f u two plus toe every three place plus electrons. So this equation is known as oxidation half reaction, and we can see that the oxidation number is plus oxidation number in the left side off the equation is plus two and in the right side plus three. So that mean increasing oxidation number also. So that is why this equation is known as theocracy addition, half reaction. And in the second case, that is so. This equation is known as the reduction half reaction. Because here, two electrons are gained in this equation, and the oxidation number in the left side is left side of chlorine zero and in the right side is minus one. So that means here we can see that decrees in the oxidation number. So that is why this is known as the reduction half reaction. So here all h r represents the oxidation half reaction, and our h r represents the reduction half reaction. Okay, so right. A balance situation for the overall redox reaction. So we can see that the electrons are not balance in this equation. So what we can do is in orderto right the overall balanced equation. For the overall Redox reaction, we can multiply equation one by two. So multiply equation one by two and add both the equations. Okay, So if we multiply equation one wife too. We get toe every two plus no form to Effy Tripolis plus two electrons. And the second vacation is C l two plus two electrons that conform to see l minus. Okay, Now we can see that the electrons are cancel out each other. So we just add these two equations so the overall equation balanced equation for the the dog's reaction is this. Okay, so this equation is the overall balanced equation, so we can see that this is a balanced equation for the overall Redox reaction.


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