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Nork Duein 4 nolattempt" lettProblem 12.35 Practice Unansiveted whether Homawork that e determines " ofan atom equal 'sharing to is the property = &#...

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Nork Duein 4 nolattempt" lettProblem 12.35 Practice Unansiveted whether Homawork that e determines " ofan atom equal 'sharing to is the property = 'ranges [ from another atom interaction ! with its of electrons: transfer complete and: submit your insvrer Type electronegativity Submitattempts left 2 UnansweredResubmitAnswered

Nork Duein 4 nol attempt" lett Problem 12.35 Practice Unansiveted whether Homawork that e determines " ofan atom equal 'sharing to is the property = 'ranges [ from another atom interaction ! with its of electrons: transfer complete and: submit your insvrer Type electronegativity Submit attempts left 2 Unanswered Resubmit Answered



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Determine the electronegativity difference, the probable bond type, and the more-electronegative atom with respect to bonds formed between the following pairs of atoms. (Hint: See Sample Problem A.)
a. $\mathrm{H}$ and $\mathrm{I}$
b. $\mathrm{S}$ and $\mathrm{O}$
c. $\mathrm{K}$ and $\mathrm{Br}$
d. $\mathrm{Si}$ and $\mathrm{Cl}$
e. $\mathrm{K}$ and $\mathrm{Cl}$
f. $\mathrm{Se}$ and $\mathrm{S}$
g.$\mathrm{C}$ and $\mathrm{H}$

Question Number six wants you to name three pairs of atoms with ionic bonds. So I'm assuming that they want you to identify two atoms, such as sodium and chlorine, that when they come together, they form an ionic bond. Typically, Ionic bonds are formed between metals and non metals because they result in a large electro negativity difference. In this case, we have chlorine with an electro negativity value of 3.16 and the sodium within electro negativity value of 0.93 So the difference in electoral negativity than is 2.23 If we have something like lithium fluoride, lithium is a metal. Fluoride is a non metal, so when they come together, they will result in a high electro negativity difference. And an ionic bond. Florin, according to your table on page 2 27 has an electro negativity value of 3.98 and lithium has an electron negativity value of zero point 98 So this difference is quite high. We're looking at an electro negativity difference of three very ionic compound. Maybe another one we could look at would be potassium bromide. This also is known to form an ionic compound. The bromide has an electro negativity of 2.96 and the potassium has an electric negativity of 0.82 So we get an electron negativity difference of 2.14 So you'll notice. In all of these examples, your examples might be different. That electro negativity difference is two or greater for these ionic compounds.

Here we are continuing to draw out some lower structures. So firstly phosphorus oxygen, oxygen, oxygen and another oxygen, where they all have three line powers here, apart from one of them has a double bond. And so we have three miners charge. And of course we can have resonance using any three of these formal negative charges. So that means that we've got three different forms of resonance. Well, overall we have three minus charge on the species. Next we've got C N minus. So we've got carbon, we can have a triple bond to the nitrogen where we need a formal negative charge on the carbon to have it with a full lone pair. Next we have also 3 to-. So we have a sofa where the double bond oxygen and then we've got to oxygen's that have minus charges that give us our two minus. And again here you can see that we will have resonance because we have negative charges on the oxygen's. We've got resonance from two different positions that will take place in separate events, and they will have a knock on effect with this double bond. Next we have cielo to minus. So what we have is chlorine, double bond oxygen, single bond oxygen too long pairs on the chlorine. The oxygen with the single bond has a formal negative charge, and here we have resonance that can bounce between the two oxygen's.

The electron negativity is a measure of the ability of an atom in the molecule to draw the bonding electrons towards itself, so we can look at the following equation X is equal to E subtract E a divided by two. So Malkin suggested upon theoretical grounds that the electric negativity of an atom today is given as half of its ionization energy minus the electron affinity. So, for example, the electro negativity of chlorine 1251 Subtract negative 349 divided by two, Gives us 800 kilo joules per mole. So the electron negativity on Pauling scale divide that by 2 30 We get 3.47.

Explanation for the given question. Yeah. We have given assertion and given reason for the given assertions. So here we have to decide and that uh where assertion is correct? Our reason is correct or water correct If assertion is correct, why the reason is wrong. Here we have to recite. Uh so you're given position is in solid state hybridization of brilliant vitamin b E c L two is found to be Sp three. So here exertion is the correct statement, correct statement correct. And we have given reason is as to glory items form to coordinate wants with brilliant atom. We already have two Colin bonds also. So here the reason is also correct voter correct. So here option is the correct answer. If board position and the reason are correct. Mhm And the reason is the correct explanation. Explanation of a assertion.


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