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E=3h 4 PatagraphBLCCDC AaBbCcDc AaBbC( AaBbCcr Noimal Aab INo Spac Heading Heading 2Sye70 When is the Overall (ree reaction energy change AG in & exerganic)? reacton inost Kkely be negative (meaning tnat the When products have lower potential . energy and lower enitropy than reactants When " products bave highet potentia CIeTg} and oxei entropy than reactants When - products haie higher potentia enegy and higher entropy than reactants When products have lower potential energy and highe

E=3h 4 Patagraph BLCCDC AaBbCcDc AaBbC( AaBbCcr Noimal Aab INo Spac Heading Heading 2 Sye 70 When is the Overall (ree reaction energy change AG in & exerganic)? reacton inost Kkely be negative (meaning tnat the When products have lower potential . energy and lower enitropy than reactants When " products bave highet potentia CIeTg} and oxei entropy than reactants When - products haie higher potentia enegy and higher entropy than reactants When products have lower potential energy and higher entopy than reactanls Which stalement most accuratol , explains why ATP hydrolysis highly exergonic? Energy released uhen phosphale groun added; ATE conlains the carhohydrale ribose which stores Lge Ofchemical Cecet There Farge IncrnS Fenul cnctry Dccuus4 cnzic repulsion edurced There large drop potcntal Keneny pecmu - chaIPC menwgron Fedunid 0o



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Another step in the metabolism of glucose, which occurs after the formation of glucose 6 -phosphate, is the conversion of fructose 6 -phosphate to fructose 1,6 -bisphosphate ("bis" means two): $$ \begin{aligned} \text { Fructose } 6 \text { -phosphate }(\mathrm{aq})+\mathrm{H}_{2} \mathrm{PO}_{4}^{-}(\mathrm{aq}) & \longrightarrow \\ & \text { fructose } 1,6 \text { -bisphosphate(aq) }+\mathrm{H}_{2} \mathrm{O}(\ell)+\mathrm{H}^{+}(\text {aq }) \end{aligned} $$ (a) This reaction has a Gibbs free energy change of $+16.7 \mathrm{~kJ} / \mathrm{mol}$ of fructose 6 -phosphate. Is it endergonic or exergonic? (b) Write the equation for the formation of $1 \mathrm{~mol}$ ADP from ATP, for which $\Delta_{\mathrm{r}} G^{\circ}=-30.5 \mathrm{~kJ} / \mathrm{mol}$ (c) Couple these two reactions to get an exergonic process; write its overall chemical equation, and calculate the Gibbs free energy change.

All right. So for part A, we are given the equation for the hydraulics is of 80 p. You're given that it's Delta G is 30.5 killer jewels. So, as always, we're gonna use our equation here. Delta G equals r T lnk, and we're just gonna plug in values again. Always know that our, um is 8.34 uh, or 8.314 Excuse me, Jules, perk on mole. And because this is in jewels, we need to change our delta G into jewels. So whoops. By multiplying by 1000 to get Jules, you could get 30,000 500 she waas So now let's just plug that into our equation. So 30,000 untraded. Joerres equals negative. 8.314 times 200 groups. Oh, my mouse is not working today Times 298 Kelvin Um, times l N K. So if you multiply these together and then divide this by that value and then you could take e to whatever number you get, you will find K. So if you want to take a minute and do those calculations, you should get a K of 1.38 times tend to the fifth. Perfect. All right, So the next part asks us to find the Delta G of reaction for the, um, metabolism of glucose. So we're given the reaction and we're going to use this formula products minus reactions. I think it's always helpful to write out kind of a little skeleton, and then you can just plug in values where you need to go. So the products we have we're gonna need the Delta G of CO two plus the Delta G of H 20 minus the Delta G of 02 plus the delta G of glucose. Remember, whenever their coefficients in the reaction, you need to put them in this equation as well. So you're gonna have six times the Delta G of C 02 plus six times the delta G of H 20 and six times the Delta G of 02 It's very important to remember that so you can find the Delta Gee of reactions, most likely in your textbook. You can also google them, but I have provided them right here. So from here it's just a plug and truck. So you're going to put this value here will substitute these values there, that value there and this value there. And that should come out to be a delta G of reaction. Um, who? 1000 879. Kill Ege loves Great. Moving on to see, um, it's asking you for how maney molecules of 80 p could be produced by metabolism of one mole of glucose. So the best way to think about this is you want to get, um, one mole of 80 p, or I should just say we want to have let me go back here. Sorry. On moles of 80 p come over moles of glucose. And we can use this Do this using our delta trees. So we know our Delta G for 80 p given in the problem is naked 30.5. So if we multiply that by our Delta G um, uh, what the Delta G We just calculated for the metabolism of glucose right up here knowing that we need to cancel out this killer jewels on the bottom. So we're gonna put 280 earth. Excuse me. 2879. Kill it. Jules. Up here, huh? One mole of glucose. This will come out to give you 94.4 moors, 80 p for every one glucose. So problems like these, it's always best to think about what you already know. So we knew we knew the two Delta G's and then look at the units to see what you can cancel out in order to get the units that you want your final answer to be in. All right. So d the percent yield again, this is super easy. So we're going to use or formula here actual over theoretical times 100%. So the actual is what we actually get in real life. So they give this to us. They say that it is 36 so we can say 36 let me see. They put, yeah, 36 months. So 36 malls in the theoretical is what we just calculated using our Delta G's. So we're gonna plug that number in over 94 point four moles times 100%. That is going to give you 38.1%

So here we're continuing on with some some a dynamic work on what we have is a situation a 298 kelvin on. We have the following equation to consider Delta G not is equal to negative rt l on k. We're looking for the K value. So lnk is equal to Delta Jeannot divided by negative rt. So we plug in the values that we got we get Ln k is equal to 12.309 k is equal to the exponent off 12.309 K is equal to 2.22 times 10 to the five. Yeah, so in the second part now we have the metabolism of glucose that is shown any following equation. We have C six h six, age 12 06 My mistake age 12 06 at 602 breaks down to six c 02 at six h, 20 So we're looking at the value of the Gibbs free energy of the reaction. So I doubt that, you know, value is negative. 2875000 jewels per mole. And now we're looking to the time the number of ATP molecules formed. So that is equal to the delta. G metabolism of Bleeker's Divided by Dr G No hydraulic sis off ATP. So on to the next page, we have negative to eight 75 multiplied by 10, 23 jewels. Permal all divided by a negative 30.5 times 10 to the power three Jules Park mall. So you can see our units cancel nicely there. And so what we get? There's units, councils, We have a unit Lis Valley. We can already tell. We get 94.26 and we can just call that 94 by rounding down. Therefore, we just have 94 units of ATP molecule for every molecule arc, Lucas.

Yes, sir. Well, in the direction Often aside, going sign a off fatty asses. It is first denial denial ated by the hydra license off tp to produce asylum. Denial it. So this how can the drawer Memphis The second reaction in the displacement off the had a displacement off the and United Group Pinto Point, Sime uh, today, Children, You showing us this? The fact that the delivery, um, constant with this reaction is about about one about one suggest the the energy level are equal. This means that the starting materials Mattias said you could be into your A s itch. So it must week as high energy must be as high energy as the intermediate a Silas did on and the product are on the product. This suggested the asylum and in knowledge on a cell C o A is high. I am energy. Just like entity. In fact, this thes are activated. Is dirt off us for a lister for Asyl degenerate? And do you, Esther for a cell c? Okay, because these are high energy Esther's. The energy from the hydra license off Tapie is is scrapping the intimidate on product instead of being with us. This allows the reaction to reversible

Hey, against the industry problem. 30. The first problem is what is the ratio off? Constitution off. Why do concentration if excite equilibrium? We know that the issue off Constitution why to concentration off eggs Is that going to the equilibrium constant? It is according to the delivery and constant. Now we know the relationship between equilibrium constant and they stand a tree. Energy changes this one. The standard free energy change is given as 20 killer June hormone. The guest constant we know is 8.31 jewels. Carmen Kelvin The temperature given here is 25. Reduce tensions that's converted toe Calvinists killed by adding to 73 which is to 98 Children. Therefore the product off on de es. From here we get 2478 June formal or we can write 2.478 Kill a Jew or more. We just divided by 1000 to get to from June 2 villages. Therefore, long equilibrium is negative. $20 willpower more divided by 2.47 in in June. My mom, which gives us negative eight points in your seven off the equilibrium constant is is it takes exponential negative 8.7 From here we get 3.12 20 point, but an inverse fall, as they billed from constant, therefore the ratio. Why to eggs Patrick Librium is 3.12 And to provide an Universe four. Okay, the next problem. Then again, ask us to calculate the ratio of why to eggs in certain conditions and given they just do that one. So from this direction from this reaction that you want, the over reaction can be found there. Excess convert into why, where the free energy changes 20 killer jewels far more and ADP has had realized do NT p and the feelings changes. Negative 30.5. Can I jump from one? Therefore, the overall reaction. One reaction that free energy changes 20 minus 70.5 eligible per month on negative 10.5 No, we can welcome your equilibrium. Constant. Okay, Bolivia Means is going to receive concentration off, um products a d. P. Pm divided by the product off rectums. It is given that 80 p a. D p and p i. What's the group? They're having one Mueller concentration. Therefore, we can on it. All these and we can just write equilibrium. Constant is the genital concentration off? Why do whatever concentration off X again? We need to find out what is the concentration off? What is the Librium constant? Now? It could be from constant. Is is going to free energy change Divided by rt have free energy changes. Negative 10 one fine killing and the product off gas constituent temporal visionaries 2.478 can usually problem. Therefore they live in constant is exponential 4.237 which gives us 69.1. Therefore, the issue off y two eggs is 69 point Yeah, and finally, the last question is again we need to complete the ratio of why two x for the ADP coupled reaction in the well off A, D, B and B and P Are those found in the rat? Mm My old sites letters through this calculation. So can we need to calculate what is thumb petition for drinks? The Constitution? Why do the concentration of fix? This is under among the standard condition from 1% and in this condition, way can We don't want the values for TB NDB. And what's with the group we know Kate Equilibrium is again concentration off X concentration off Why Multiple angry concentration off NDP Want to clamber Concentration of forceful group developed by concentration off eggs concentration or a D. P or concentration off? Why to concentration off eggs can be found by this equation. No, all these values air given and we can insult these values. Okay, Equilibrium is 16 and 21. Mother. The concentration off DPS 8105 Milly Moaner Let's scan body to monitor by adding by multiplying ah to an anniversary constitutional FBI is 8.5 minimal er, it's converted. Tamala and concentration of ADP is $0.93 million. Next come body to another, then we get 0.5562 55 divided by 0.0 000 749 From here we did 74301 from 05 which is the ratio white works. We can just trying to 7.4 months. When I went into the ground for as the machine off


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