All right. So for part A, we are given the equation for the hydraulics is of 80 p. You're given that it's Delta G is 30.5 killer jewels. So, as always, we're gonna use our equation here. Delta G equals r T lnk, and we're just gonna plug in values again. Always know that our, um is 8.34 uh, or 8.314 Excuse me, Jules, perk on mole. And because this is in jewels, we need to change our delta G into jewels. So whoops. By multiplying by 1000 to get Jules, you could get 30,000 500 she waas So now let's just plug that into our equation. So 30,000 untraded. Joerres equals negative. 8.314 times 200 groups. Oh, my mouse is not working today Times 298 Kelvin Um, times l N K. So if you multiply these together and then divide this by that value and then you could take e to whatever number you get, you will find K. So if you want to take a minute and do those calculations, you should get a K of 1.38 times tend to the fifth. Perfect. All right, So the next part asks us to find the Delta G of reaction for the, um, metabolism of glucose. So we're given the reaction and we're going to use this formula products minus reactions. I think it's always helpful to write out kind of a little skeleton, and then you can just plug in values where you need to go. So the products we have we're gonna need the Delta G of CO two plus the Delta G of H 20 minus the Delta G of 02 plus the delta G of glucose. Remember, whenever their coefficients in the reaction, you need to put them in this equation as well. So you're gonna have six times the Delta G of C 02 plus six times the delta G of H 20 and six times the Delta G of 02 It's very important to remember that so you can find the Delta Gee of reactions, most likely in your textbook. You can also google them, but I have provided them right here. So from here it's just a plug and truck. So you're going to put this value here will substitute these values there, that value there and this value there. And that should come out to be a delta G of reaction. Um, who? 1000 879. Kill Ege loves Great. Moving on to see, um, it's asking you for how maney molecules of 80 p could be produced by metabolism of one mole of glucose. So the best way to think about this is you want to get, um, one mole of 80 p, or I should just say we want to have let me go back here. Sorry. On moles of 80 p come over moles of glucose. And we can use this Do this using our delta trees. So we know our Delta G for 80 p given in the problem is naked 30.5. So if we multiply that by our Delta G um, uh, what the Delta G We just calculated for the metabolism of glucose right up here knowing that we need to cancel out this killer jewels on the bottom. So we're gonna put 280 earth. Excuse me. 2879. Kill it. Jules. Up here, huh? One mole of glucose. This will come out to give you 94.4 moors, 80 p for every one glucose. So problems like these, it's always best to think about what you already know. So we knew we knew the two Delta G's and then look at the units to see what you can cancel out in order to get the units that you want your final answer to be in. All right. So d the percent yield again, this is super easy. So we're going to use or formula here actual over theoretical times 100%. So the actual is what we actually get in real life. So they give this to us. They say that it is 36 so we can say 36 let me see. They put, yeah, 36 months. So 36 malls in the theoretical is what we just calculated using our Delta G's. So we're gonna plug that number in over 94 point four moles times 100%. That is going to give you 38.1%