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Answers

A chemist decomposes samples of several compounds; the masses of their constituent elements are listed. Calculate the empirical formula for each compound. a. $1.651 \mathrm{~g} \mathrm{Ag}, 0.1224 \mathrm{~g} \mathrm{O}$ b. $0.672 \mathrm{~g} \mathrm{Co}, 0.569 \mathrm{~g} \mathrm{As}, 0.486 \mathrm{~g} \mathrm{O}$ c. $1.443 \mathrm{~g} \mathrm{Se}, 5.841 \mathrm{~g} \mathrm{Br}$

As we know that blue color of copper sulfate blue, good lad of corporal sulfate solution of copper self aid solution does not Faith does not states in access of ammonia in access of ammonia. It will remain blue in color. So here all the other statement are correct, but his statement B is incorrect, therefore, according to the option. Therefore, for the option A. See the are correct.

In this problem, I'm writing the reaction. Just look at it carefully. Any energy for at be your ford four H two will react to form any and at four at people for plus four as to and and ME energy for add bill for will react to form and the beauty plus an STD plus as to So according to the option. In this problem option. See each correct. Was there not that we have any Beauty which reacts with metallic oxide to give colored or to post fails.

For this question. Here we are, too. Calculate the empirical formula for each compound For a we're starting with 1.651 grams uh, silver, and we have point 12 to 4 grams of oxygen. It's convert two moles, 17.9 grams per moles, molar amounts of silver. This would give me zero point zero 15 30 moles and 16.0 grams per mole for oxygen. Ford, about 16 would give me 0.7650 moles. We're going to divide by the least 0.7650 to give me one there. And this works out to exactly two here. So empirical formula would be e g to go for part. Hey, for be we have 0.672 grams of kobold 0.569 grams of arsenic and 0.486 grams of oxygen. Convert all of these two moles. Well, the massive Cobalts is 58.9 grams per mole. This would give me through 0.0 11 Formals. Arsenic has a molder mouths of 74.9 16 by nine 0.0 seven by seven moles and oxygen. 16 grams per mole. This would be 0.0 304 moles divide by the least, which is 3.757 This works out to 1.5. This works out to four. We're going to need to multiply this by two to give me 32 and eight. Therefore, my empirical formula here would be C o three A s, 208 And for part C, we have 1.443 grams of selenium and 5.841 grams of Rumi. Let's convert two moles. Cellini has a molar mass of 79 grants for moon Rooming has a more mass, uh, 79.9 grabs from old. This would give me zero point 0183 moles and my 0.8 for one. Depart by 79.9 yields 0.731 Moles going to divide by 0.183 This would give me four. So my empirical formula here would work out to be ah s e b r four

Good day in this question, we will know the empirical formula of the given compounds. So we are given masses of each element present in the compound. So in order to know the empirical formula, we will need to know the most of each element present. Give and we will have to solve it. You see, moses equal to mass our mother mass of each element. So for the first one we have more egg are silvery, is equal to mass of a smaller mask. There must is 1.651. It comes in the given and the mother must of Silver is one or 7.87g per month, Solving this will give us .01553 malls. Next for mold. Oh, we have bus over moller bus .12-4g in the given is a massive oxygen buy did by moller Maas. Well give us .00765 most. Therefore the lowest number of moles is the oh, so we will divide all the moles to the smallest number of modes. Too nosy ratio. So for egg it was 10153 moles Divided by by 00765 moles will give us to. And for all, yes, 100765 months, Divided by .00765 moles Equals one. Using this ratio that we get, we will know the empirical formula. Therefore, empirical formula is equal to a G two oh next. We will do the same for the next questions. So for letter B we have more C. O. Must our mother mass. We have fine 672 g Divided by 58.93 g per mole will give us Why 011 for Mold. Next is a mole. S Most of our mother mosque. We have .569g, Divided by 74.92 g per mole. Well give us By 00759 more. Well. And for all, we have more oxygen. We have em over mother mas .486g divided by 16 g per mole equals Why 030375 More. Now dividing each by the smallest number of moles we have. We have very easily A. S. So See Oh it was 10 114 divided by .00759. It will give us one point fire A. s. .00759 100759. It was one and all. Why zero 30375 divided by By 00759 will give us four. Now we have a half Number, the 1.5. So we need to multiply it by two to give us a whole number. So We will have three do and eight. Therefore the empirical formula formula is equal to see it all three a. s. two oh. Lastly we have Well let me see mol s key. It was must spur mauler must 1.443g is a mass of us. He divided by mother must 78.96 g per mole is equal 2.01828. More and more br so much of her mother must With a given mass of 5.8 where one grows Divided by 79.9 g per mole. Well give us Y 0731 moon. Now solving for theory issue we have .018- eight, divided by .018- eight. Since the smallest Number of modes east by 01 8- eight is equal to one. And for br sequel, do 107,310 Divided by .018- eight. You'll give us for. Therefore, the empirical formula is equal to S. E. We are for Thank you.


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