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AleLuHnenrKanlead MaaShALL onaul EGESh"tps /!marshall-bb blac khaard com webapp:/aseesumirnt takeftake Fp?cours Siiply Hune Arc Healhcare nd 5i9n Ir Hame MTLAmIn Snpry HrereporcInsenFonal FanieQuestion 11 0f 25 Moving to another question will save this responseQuestion 11pointsSave AnswerSuppose P(A) = ,35, P(B) 55, P(C) = 10, P(EIA) = .10.P(EIB) =.05 and P(EIC) = What is P(E)? 0625 0375 ,0125 058 055Question 11 0 25 Moving to another question will save this response_Ftk6WnlerlllaFlet(Dzhul

ale Lu Hnenr Kanlead MaaShALL onaul EGES h"tps /!marshall-bb blac khaard com webapp:/aseesumirnt takeftake Fp?cours Siiply Hune Arc Healhcare nd 5i9n Ir Hame MTLAmIn Snpry Hrereporc Insen Fonal Fanie Question 11 0f 25 Moving to another question will save this response Question 11 points Save Answer Suppose P(A) = ,35, P(B) 55, P(C) = 10, P(EIA) = .10.P(EIB) =.05 and P(EIC) = What is P(E)? 0625 0375 ,0125 058 055 Question 11 0 25 Moving to another question will save this response_ Ftk6 Wnlerllla Flet (Dzhulvet deviantani Type here scarch IICF Oral Commu Shod



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Use the following information for Exercises $11-14$. In $\odot$ C, point $T$ is randomly selected so that it does not coincide with points $P$,$Q, R,$ or $S . \overline{S Q}$ is a diameter of $\odot C$. Find the probability that $m \angle P T R=55$ if $m \widehat{P S R}=110$ (figure not copy)

In this problem. We're going to solve this linear equation by clearing decimals or limiting the decimals. And we're going to do that by looking at the decimals 0.12 and 0.15 and decide. Okay, they're both two decimal places long, so we're gonna multiply by 2/10 to clear those death threats to move the death. Wants to the right. Twice. Thistles. 100 by the way. So let's go ahead and multiply every term by ah, 100 Every terms this term, this term and this term over here. So 100 times 1000.12 is 12, 100 times. Q. Would be 100 que and 100 times 1000.15 is 15. So now we have all those decimals cleared, and we can now distribute 12 times five Q, which is 60 Q in 1200 minus one, which is a minus 12. We still have that minus 100 here 100 que and distribute the 15 times seven. This is going to be 35 one Oh, five. There so and then minus. This is gonna ah minus 30 Q. Let's combine the cues on the left side. 60 minus 100 is a negative 40 que were the minus 12 there, and let's get the cues on the left side. Let's add 30 cute of both sides to get it off right side and let's go ahead and cancel it. Here, be a negative. 10. Q. On this side, minus 12 equals one. Oh, five. Now I want to get that negative 10-Q by itself. So let's add 12 toe both sides and up here. Gonna move my threw up here. Now I'm gonna have negative 10-Q equals and one, oh, five plus 12 is going to be one 17. Let's divide by negative 10 on both sides, and we get Q equals, Um, this would be a negative 11.7.

For a prison. If this is the incoming Ray, does the surface normal? That's the surface normal. And that's the final out going grey. If this angry, I won. If this angle this I to we want to find to start with what is this angle? We know that if this angle is a then this angle over here, this angle over here is first your father, we have to figure out that this on that is 90 degree. Both of them are 90 degree that the surface normal. Hence this angle does that angle. He's 180. In this particle er case, A equals 40 degree. Hence, this angle comes out to be 180 minus 40 degree equals 1 40 degree. This comes out because this is a this case face. This is a quadrilateral that some of the four angers are 360 degree. I've got to normal angles, so they're hard 80. So some of the two other angles this 100 aged 80. So that's how I figured out that this angle over here is 100 for it. Really. Now I want to figure out what is this angle. And for that I will use Nasso. I know. Ah, the refraction. At this surface, it is coming from air and one scientist award and one sign I want. So anyone is one sign off I want I want is given to be 25 degrees equal. Do defectively. Inside the prism is 1.75 Sign off. That's call it better. So from here I get better equals. I'm sign. Sign of 25. 1.75 It was 13.97 degrees are 14 degrees. Now We're going to look at the triangle from here, here and here. We know one of them is 140 degree. We have figured out this one. It's 14 degrees. So how much is that one? So that would come out to be 100 a D. Minus that some of the two other angles, which is 140 14 degrees. That is 26 26 degrees. So now you're considering the refraction at this party For the selfish, it is coming from inside the glass 1.75 Is that effective? Index times sign of the incident angle, which we just found out to be 26 degrees equals outside that effective indexes. Juan sign. I do. So this part is 0.767 So from here, we can find I do. It was 50 dearly. Now we know that I want us. I do Equus a tow us Daja. So subsidy. All the values Delta becomes I want given to 25. Thus I do find to be 50 miners a given to be 40 that comes out to be 35 degrees.

So here we know the measure of our GPS is 40 and we're adding a point tion, and we want to know almost the probability that if you add Appointee and so it's not on any of the other points, not the measure of my angle will be 20 degrees. So if I add a point out here anywhere, the measure of angle pts will be 20 degrees because it's the described angle, um, measures half that of the ark. But, um, so that will occur if I have it. T not between, um PNs. But if he is between P and s, then the measure of this inscribed angle would not be equal to, um, 20 degrees. It would be equal to, Let's see, a lot larger than that. Um, would have 360 minus 40 degrees is the arc length. So this would be a 320 degree arc length here, which gives us a, um 1 51 60 degree angle. Okay, So if I happen to land in these 40 degrees, I get a 1 60 could wrangle finally outside that I get my 20 to be angle. I wanted So, um, if I lent anywhere in 360 degrees, minus those 40 degrees so anywhere not in those 42 reason monarch. That will be exactly what I want. So the probability of that is here's my chance over the total possible places. So I get 3 20/3 60 Um, and I could simplify. That's that wants to be 30 to 36 I'm gonna divide by four. So I get eight nights, so my probability of this occurring is eight nights.

So basically here we have to, um, simply write down all of these numbers with basically including all of the zeroes. So for part A, we have 286.6 millimeters which is giving us 286.6 times 10 to the negative third meters. And so this is gonna equal point 2866 meters for a part B, we have 85 micro volts and this is equaling 85 times 10 to the negative sixth volts. Or we can say point a cz zero four. So four zeros. 1231234 Hey, five volts. For part C, we have 760 milligrams. Ah, this is going to give us 760 times 10 to the negative third grams. Rather my apologies 10 times, 760 times 10 to the negative third, uh, rather tensioning third grams. Or we can say for s I units 760 times 10 to the negative, 60 kilograms. And so this is going to equal. We have to 30 So 300.76 kilograms. Given that that last zero is not a significant figure. So our final answer should only have two significant figures. Four part D. We have 60 0.0. So now we have three significant figures. Pico seconds. So this is giving us 60.0 times 10 to the negative 12th seconds, and this will be equal to s. So this will be, um 12123 Uh, four, 5675678 nine, 10. And then 600 seconds. So, unfortunately, just had a ah, put all 10 zeros before the six. And then keep those two significant figures after the six. And then for party, we have 22.5 pharaoh meters. We're sorry from Tau meters. And so this is giving us 22.5 times 10 the teens. So, unfortunately, we have to write down all of these heroes. Ah, that'll be 0.0 12345678123456789 10 11 12. And then 13 2 to 5 meters. And then for F. We have 2.50 giggle volts. And this is giving us 2.5 times 10 to be positive. Ninth volts. And so this is gonna be 2,000,000,500 1,000,000 volts. And that's the end of the solution. Thank you for watching


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