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-/10 pointsAn object of mass 220 grams displaces 65 grams of water (a) What is the volume of water displaced? cm3(b) What is the density of the object? g/cm?...

Question

-/10 pointsAn object of mass 220 grams displaces 65 grams of water (a) What is the volume of water displaced? cm3(b) What is the density of the object? g/cm?

-/10 points An object of mass 220 grams displaces 65 grams of water (a) What is the volume of water displaced? cm3 (b) What is the density of the object? g/cm?



Answers

A 5-mL sample of water has a mass of 5 $\mathrm{g} .$ What is the density of water?

Hi there. This is a density problem. We're being asked to calculate a density for water so we will need the density formula. The density of any substance is defined as the substances mass divided by the volume. For this problem, we are given the mass of this sample of water as five grants and were given the volume his five millimeters. So taking 5 g and dividing by 5 mL five divided by five gives us one. Our units do not cancel notice. We can't cancel grams rebel leaders. So our answer ends up with the units grams per milliliter. And that is our answer. 1 g per mil leader is the density for the sample of water. Thank you so much for watching.

Solving party of this problem. So here I can write volume is equal to side Cube. So just putting the value, I can write 20 centimeter whole cube Which is equal to eight triple zero centimeter cube. So changing it into later, I just multiplied by one letter by 1000 Centimeter Cube which is equal to eight L. as our answer for party. Now for part B I can write mass is equal to the volume multiplication density which can be further return edge eight triple zero centimeter cube multiplication 1000 kg. Permit take you simplifying it for the I can write the experience and age 8000 centimetre Q multiplication one m by 100 centimetre. Hold to multiplication 1000 kg, permitted U un simplification. Finally I get DNC rage eight Kg. So I hope you understand the solution.

Okay, So this question tells you that you have an object with a mass of 7.5 grams that raises the level of water in a graduated cylinder from 25.1 milliliters to a final volume of 30.1 milliliters. Based on this information, what is the density of the subject? So we know that density is defined as the amount of mass that an object has in a specific volume. So in this case, we know that the mass, which is given a 7.5 grams, 7.5 grams over the volume So now we have to figure out what the volume is. So we know that the final volume is equal to 30.1 and we know that the initial volume is 25.1. So we have to subtract it. He used to see this is in millionaires. So 30.1 minus 25.1 milliliters, which equals 7.5 grams over five milliliters. Because the difference in your volume is five millimeters. So then our final density, once we do 7.5 divided by five is going to be equal to 1.5 grams per milliliter. And don't forget your units, because units are going to be very important. So this is our final answer.

So full mass minus mass When it was empty leads to the mass of what? Yeah. Yeah. So first of all, let us take him in the volume, 24 point 81 g one centimeter cube. one g equals 24.81 centimeter cube. And for mass for for water specifically, the the the volume of the water will be 24.81. Middle Alito. Mhm. Therefore, Mass when it was full was 88.42 g. Mass venue empty was 78.91 g. And mass of unknown liquid. Unknown liquid Is 9.51 g. We know that density is equal to mass for unit volume. Let us put in the values so masses 9.51 g volume is 24.81 centimeter cube. And the density turns out to be 0.38331 g per centimeter. Kill. This is the density of unknown liquid.


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