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DEmawaxa E Wo JW 1 1 BW 3 E ba 2 01 2 6azi E 3 animallhider E 1 Dne n E 1 Elem J PHB Naa KM W1...

Question

DEmawaxa E Wo JW 1 1 BW 3 E ba 2 01 2 6azi E 3 animallhider E 1 Dne n E 1 Elem J PHB Naa KM W1

D Emawaxa E Wo JW 1 1 BW 3 E ba 2 01 2 6azi E 3 animallhider E 1 Dne n E 1 Elem J PHB Naa KM W 1



Answers

$\lim _{x \rightarrow 1} \frac{(1-x)\left(1-x^{2}\right) \ldots\left(1-x^{2 n}\right)}{\left[(1-x)\left(1-x^{2}\right) \ldots\left(1-x^{n}\right)\right]^{2}}=$ (A) $n !$ (B) $\frac{(2 n) !}{n !}$ (C) $\frac{(2 n) !}{(n !)^{2}}$ (D) None of these

They were multiplying matrices, E and F. Together here. Eight times F. We know this will give us a two by two matrix as a result. So. Top right element row one, column 11 times three plus three times negative one. Get zero there. Okay. Top right. Row one column to one times three was three times negative one. This is another zero there. Okay. Moving our way through. It just takes a bit of practice. These guys working through all the elements, say it to yourself in your head or out loud. If you want. Row one column, try road to column one. Two times three plus six times negative one. Okay, It's gonna give us another zero there. I guess. I think we're getting zero matrix out here, but we'll check with the last element Road to college too. Two times 36 times negative one. Another zero out there. Okay, so our result here is again zero metrics.

In this problem he had X is And AHC 03. It has molecule er wait, it has a molecular wait it's equal to 84. So according to the option, option B is correct here, option D is correct answer for this problem Here. The compound exit any HC three. It has a molecular weight. Mhm. Of 50 food. I hope you understand the answer.

Hello. We have the number 77 in its limit and tends to infinity. And on the limit we need to find out limit and approaches to infinity. The question is one x 1 into three plus one by three and to five And so on one by 1 to 3 plus one by three and to five bless one by To win a -1 into 20 plus one. Okay, so you can say that this term that is let us suppose T n is one x 2 in -1 in two 2 1 Plus one. Okay if you open it up it will become and also even will be equal to one by two miles 1 one in 23. Okay. 1231 minus 5125 So this could be done as one by two two Plus 1: -1. One by To end -1 minus one by 20 plus one. So this will be one x 2, one by one -1 x three. The two will be equal to one x 2 one by three -1 x five and so on. So if we add it up if suppose the some aid S. N. If we add we'll be getting one by 21 minus one by three plus one by three minus one by five. Up to. It will be last term in this case will be equal to one by To end -1 -1 by two and plus one. So we can easily upset that all things will get cancelled out bust only one and 21 plus one will demand as it is as in will be one by two one and minus went by 20 plus one. One by two. This will be to win. That's when minus one by 20 plus one. These two will get cancelled out. So Sn will be won by two two and by 21 plus one. This deal will get cancelled out so as in will be and by 20 plus one and if and approaches to will apply and limit and approaches to infinity so limit and approaches to infinity. This will be limit and a process infinity. And by and we take common two plus one by end. So these two will get cancelled out. This will be won by to placido one by two, so one by two is the correct answer. An option number. C is the correct one. I think if

To solve the problem which has intends to infinity of 1/1 time street. That's one of the three tens fighters, So until one or two in minus one times to win this one, let us assume this submission to be equal into a soft essence. That means we need to find the limit as intends to infinity of submission. Sn who's anything tom ti N is equivalent to 1/2 in minus one times to win this one, which is equivalent to one or two times to win plus one minus to end minus one over to win minus one times two and plus one which is equivalent to this is within two. So we can see that any thermal submission is maneuver to win minus one half of one who were doing minus one minus one word. Wind plus one is the any time. Now, let us assume this in the tone to be equation one like this, take different values of when that is 123 and so on. And put these values in the formula 40 in which is equal to one by two times of 1/2 in minus one minus one over to win plus one substituting these values of N. In the submission. That any time of the submission will obtain the value of the one to be equal to one by two times off, one minus one by three. The value of it will be willing to one by two times one by three minus one by five. Value 53 will be equivalent to one by two times of one by five minus one by seven. And this will continue until the end of term. That is a P. And term is equal to 1/2 times one way to win my next one. My name's went over to and plus one. So adding these stones that is finding the submission of these stones and Sin. We'll get the value of essen to be human into one by two times one minus one over to win plus one. Or we can see that the limit as intends to infinity of essen. Is he willing to LTD intends to infinity of one by two times one minus one word to win plus one, which is equal into one by two. So we can see that the correct option is options. See that is the limit of the given submission is one day two or half.


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