So in this question, we're going to be looking at finding quartile. One court help, too. Quart l three, the mid quartile and the I Q. R for these given data sets for these two given data sets. So here's our first data set, and the numbers are arranged in order from smallest to largest, which is critical when you're finding measures of position. And so we're going to start by looking for court l two quart l two is also known as the media. So 2 2/4 50% right the middle. So we have 123456 numbers, So an equal six. So if I take six and divided by two, that gives me three. That means my median is halfway between the third and the fourth data value. So if I look here, here's my third of my fourth data value on I want what's right in between. So to find quartile, too, I'm going to add 16 and 25 together and divide by two. In other words, I'm gonna find their average, find out what's in the middle of them, and that tells me that I get in the middle there to be 20 point. So there's quartile too. Then I'm gonna separate the data into two halves. The lower half of the upper house so kind of down the middle here and the middle of the lower half is quartile one, and we could just see by looking at it. So the middle number there is poor tell one. On the middle of the ball of the upper did are the hard data values is court L three. So we can just look at those two things on inspection. So quartile one is 12 and court tell three equals 32. All right, so then we've gotta find what's called the mid quartile, and it is essentially the average of the first and the third court trials. And we're given this formula in the problem Q one plus Q three divided by two So we can substitute these two values in. So the mid quartile is going to be 12 plus 32 divided by two. And that gives us 22. And finally we're gonna find the I Q r and the I Q r. Um, is Q three minus Q. One. It's just the difference. The range of the court tiles, so that is equal to 30 to minus 12 which gives us 20. So there we have our five answers moving on then, too. Ah, the numbers and data set B the same. We have seven numbers. So when we have seven numbers, we want to find the median on and we can find the median position. When we have a non number of numbers, we can add one and divide by two. So that means our median is going to be the number that's in the fourth position. So that means this number right here, 94 Hotel two, which is equal to the median, is 94. All right, so then to find court, tell one I'm gonna look for the middle of the lower half of numbers and again it jumps right out at us. We can just look at it and see that the median, um, or the middle of the lower half of numbers is 62 and same procedure for the top half of numbers. We can see them. That court L three is equal to 99. All right, so now we can move on to the mid court tile And that's when we looked at in the last data set there. We're gonna add our foretells together and divide by two. So 99 plus 62 divided by two gives us 80.5. And then our last calculation we need to do is Thea like you are, which is equal to quartile three minus court l one. So we have 99 minus 62 which gives us 37. So 37 80.5 and then we've got our core tell to at 94 quartile one at 62 court l three at 99 okay?