Okay. See the problem three times for a variance of it. So you have a she with positive charges on it, And then you have, ah, charge to spend it on a string somehow. Ah, uh, I guess this is a good model for, like, pith balls, which I've seen in lab him anyway. And then, you know that this angle is 30 degrees, and then the goal is to get the charge density on the plates goes question mark, I'll go ahead and start it by writing out what's given. So, um, the masses. Um, so it's one milligram, and so I need to convert that to kilograms. And so that's one times 10 to the minus six in the charge is I think it's two ton of Muncie. Let me double check two point. Oh, times 10 to the minus six. Okay, that's also one point. Oh, um, I can write it. Okay, great. So do this. You want to just do a free body diagram on the so you have the weight down, which I'm gonna do no force of gravity. You have attention force. So call that have some tea, and then you have the repulsive electric force was gonna double check the signs of all these? Yes, positive. She and positive charge. And then the charge isn't moving. And so you know about the total for us zero. So, um, so then, yeah, you can say that the forces in either direction balance each other, so I'm gonna label this angle is 60 degrees that this one's 30 because you could make a 30 60 90 triangle. So in the ex direction, that means that the force from the electric field has to be balanced by the horizontal component of the tension forced. So that's f t cose 60. And then for why, you know that the, um, the vertical tension for us has to be balanced by gravity. So you can say f g equals f t times this sign of 60. And, um, basically, you have you two things you don't have are the electric force and the tension. But you can do some algebra to get the, uh, the eliminate tension because the problem doesn't ask about tension, though it is an unknown. And if you do that substitution, then hopefully you got what I got, which is f g over tan 60 equals f e. And then again, I used that they use is Trig. So signed 60 over CO 60 is 10 60. So now we it's time to plug in the gravitational force and the electric force in terms of, uh, the things that were given. So I'll go ahead and do that. And, um, after years, MGs lives mg over tan 60 equals a sigma over to Absalon night. So that's the electric forests. And then our excuse me, the electric field and then forces charged times. Um, Times Field. And so So you got that. And so algebraic Lee isolating sigma. I'll do that on the next page. It's probably not necessary. It feels more complete, though, if I do so it's to Absalon, not mg. I feel like I'm cutting out all the trig and you need help with that. Um then it's probably like, I don't know, this is a bit more basic than than all the trig, but yeah, it feels a lot more complete to write this out this way on DDE. Um, so if I plug in everything So, um JIA JIA's nine pointy If, uh, probably didn't forget that somehow it's a memorable number, I think. Um, yes. When I put that into my calculator, I got five point. Looks like a six 5.0. It was like a lag here. 5.0 times. 10 to the minus nine Newton per pool. Meter squared. I'm just gonna double check the calculation. Okay. Great. It looks good to me.