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Group has fewct than 1Q0 elements and subgroups of orders I0 and 3 What F the ordcr 0f G?...

Question

Group has fewct than 1Q0 elements and subgroups of orders I0 and 3 What F the ordcr 0f G?

group has fewct than 1Q0 elements and subgroups of orders I0 and 3 What F the ordcr 0f G?



Answers

Which atom has the largest radius of Ga, In and Sn

Yeah we have five statements where we want to select the correct answer for each number one. The solution said to the absolute value of the equation of the absolute value equation, that's the value of two, X minus three equals five. In part two we have the function Y equals absolute body of X. We know that it is reflected over the X axis and then shifted by two units left and four units up. You want to know the new question of the function? Part three We solve this system of equations for X and Y x minus three Y equals five X. The three white was negative one 44 We want to know what is the slope of the line perpendicular to the line four X plus eight Y five. And number five is what is the equation of the line through the 50.5 and 16 So let's start with R. A number one story. Mhm. The line the solution said to the absolute value equation, the value of two X minus three equal five. So we know that the absolute value of a quantity is equal to a positive number. Then we have two options. Yeah. The first one is that the expression sadly after value is actually equal to the number to the on the right or the the number inside the value is equal to negative. The number of these are the two possibilities. In each case the value will be five. And so each of these equations can be solved to find the two values that are solutions to the absolute value. Immigration. So the first one is two, X equals eight five plus three. And here to X equal three minus five is negative two. So X equal four in this first case or here X equals negative two over to his negative one. So two possible solutions are four or negative one. If we see the options here. Yeah, we have a is for it is not that the is negative ones, not that he is negative one and one. Not that C is five and 85. Not that's always be four and 91. Even though, as I put it here or we can say that when the right solution said we include both numbers so we can say and the case, she said numbers they had to one and the number four. So the correct answer is B. It is here, option B. So let's go to next problems number two and it is the function absolute value of X pass Australia. So there are some transformations of the first transformation is is reflected over the X axis. We know that the function as the values like this. When we reflect over the X axis, we'll get that and this is simply a change of sign to all the images of the function that is. Each value is now the same value but negative. So we know that this first transformation gives the function minus absolute value of X. Mhm. Second transformation is we're going to shift the graph two units left. And that means that now the graph is remember the new one was there and now we have this is the graph we are going to transform then then you want to shifted to the left will be something like this. We have here the negative to here we have to see you. And that means that the new graph at negative to get to be zero before it happened at you. Now it gets happen at negative two. So they knew function is minus absolute value of x minus two. Sorry blast you. Because in that case if we evaluate that at negative two, we get zero which is the result we respect when the graph has been shifted to units left and and that happened to all the images that is the argument is add to in order to shave the graph two units left, so we have that and the third transformation is achieved four units up. Yeah, it means that all the images are going to be translated upwards uh for units so go in, let me do something here to clarify for a little bit more. Is the access here? Okay, so now again, we have the access here. We had the last function we had with this something like this at negative two here. And now this graph had to be shifted up four units. So it means that now the vertex these very vertex here can be at the height of four. So we are simply adding for to all the images of the previous graph. That is why is now negative absolute value of excellence two plus four. Yeah. So this is the last uh equation we get when we do in this order, those transformations reflecting over the X axis, shifting up two units, shifting shifting left two units and she's shifting up four units. So if we see the mm options in this question we get e number be reaction be. So his options D in the second question Shendi is why it was negative absolute value affects the super. Just like that. We go to the third equation. The third question you solve the system of equation x minus three Y. What's five? An expert three Y equals anti one. And in this case if we have served that the term in why both equations identical but with different signs. When with some our district aggressions. Side by side we'll get any question with only the variable X. So summing up the left side of this equation plus the left side of this equation. We get two X. Because negative three Y plus three Y cancel out. And this is going to be equal to the sum of the right side of the first equation plus the right side of the second equation. That is four plus negative one, which is four minus one, she's four. And so X is equal to two. Knowing the value of X is easy to find the value of why using any of these equations. So from here we use for example the first equation. And we get to replacing the value of X here which is to minus three Y equals five. And so three Y equals passing through it to the right and five to the left get 93 so Y equals negative one. And we have been the solution only one solution of this system of linear equations and it's the point X equal to and five people 91. And if we see the options, we have option C. Now to the fourth question, what is this slow of line perpendicular to the line? Four X plus eight? White was five. So we got to remember that the liners were particular to all. The line has a slope negative one of ram. Where am he is too slow of one lot. One off the two perpendicular lines. That means if we know the slope of one line, the slope of the preclinical line to eat is negative one of room. Uh huh. Or put in another way. The product is to the slope of two perpendicular lines between negative one. So the other thing we got to remember is that if we have the equation of the line, the slope of that line can be observed in the equation if we solve for why? So for X plus eight white was five, means that for eight Y. Calls five minus four eggs. And why then is five minus four X over eight, which is 5/8 minus for over eight eggs. And we can reduce this question by dividing both terms by four. And we get Michael's 5/8 minus one half X. So this means that the slope of the line whose equation is for eggs plus four eight Y. Was five, yes, negative one half. Let's call it them. So the slope of the line perpendicular to this line here. Yeah. Is as we saw above, we get to put the slope of the line we know in this formula here, so we get negative one over M which is negative one over negative one house, which was the value we found here. The slope of this line is happy one half. So we put it in here, we get a positive result and one of one half is too. This is the answer. And then the option, if we see the list of options, okay, we see the option. The court option is D Where the value is too. Mhm. And now the last equation. Number four. Number five. Number 5 30. Yeah. Number five is what is the equation of line passing through points 05 And it takes instead of calculating that, calculate India's low and then using the equation right, in the equation of um of the line is in the slow right. It is sufficient to evil Wait for each of the equations we have there 0.5 and 16 Because if a line buses through those points, both points must satisfy depression of the line. I mean for example the equation Y equals X plus six zero here, which corresponds to the eggs at this point. Forget why why for six. And then the 60.1 this 0.0 if I won't be on the line because for example, zero, we must have why it was five. So this line is not the line passing through those these two points and that we can do for each of the aggressions. Given of course this is a practical way of solving the problem. If we to the calculations quickly, don't do those calculations quickly. Then we get to go through the process of calculating the slope of the line and then the equation, for example, in this case if we do that, the slope of the line passing through 05 and 16 yes am equal the difference of the second coordinates in any other. I will do this minus this, that is six minus five. And if we did that order with the same order in the denominator which consists of the difference of the X coordinate, that is one minus six minus serious. Sorry. So six minus five on the numerator and one minus zero on the denominator. And we get 1/1 which is one. So the slope is one. As we use any of those of the two points given to write the equation. It will be the same result. We used the first one because we have a serum, it's convenient. So we got y minus five equals slow, which is one times x minus syrup. So the question is why minus five equals X. Because we got here x minus Sirius X times one in six. And so Y equals X plus five. And that the solution of the problem here and the option which give us the great answer is option D. And these are 25 answers to the set of problems given in the statement. The first line. I couldn't read the functions. That's why I didn't solve the first spark which says if X and y f m G our reverses of each other, then I don't I cannot see the formulas here. That's why I didn't answer that power. But we have the other five questions and served over here.

Hi there. To answer this question, we need to know a little bit about the periodic trend for atomic radi I. So I am going to try to sketch a quick outline of the periodic table here so that we can discuss the trend. All right, so pretend that's the main body of the periodic table. The trend for atomic radi I says that it increases as we go down a group. And this is because we are adding an extra energy level as we move down each period within the group. So as we add an additional energy level, the radius of the atom increases. So atomic radio increases as we move down. We also know that move in across a period. The atomic radi I decreases. This is because the energy level remains constant moving across. But as you move each box across, you add another proton to the nucleus. So the nuclear charge keeps increasing as you move across. And of course that positively charged nucleus attracts the outermost electrons and the more positive charge you have, the closer it pulls those outermost electrons inward. So as you move across the period, the atomic radio decreases. What that effectively means is that we find the atom with the largest atomic radi I in the bottom left corner. So based upon the location of other elements on the periodic table, we can arrange them in terms of increasing atomic radio I. Which is what we want to do here. So we are given three elements, we are given sodium and magnesium which are side by side here. So we have N. A. We have M. G. And then we also have E. Which is above magnesium. So the one that is closest to the bottom left corner is going to be the largest. So that would be the sodium. The one that has the smallest radius of these. Three is going to be furthest away and that's going to be the brilliant. So arranging these in terms of increasing atomic radius, we would have beryllium, then we would have magnesium and then we would have sodium of these three, brilliant is the smallest radius and sodium is the largest. And we determine that entirely by the periodic trend and just the location of these atoms on the periodic table. All right, thank you so much for asking your question. I hope you found this helpful.

And this problem we have to write down the electronic configuration us the four elements number one. We have to write the electronic configuration for the boron and the electronic configuration far germanium and the electronic configuration for the element named technology um and finally the electronic configuration of delirium. So here we observe that the electronic configuration for this poor on that will be H E To S to be one for the germanium. Because if we observe the atomic number of for many um it is 32. So we select a way to accommodate 32 electrons. So for that, the noble gas argon Already contains 32 18 electrons. So we will be looking out the way for only arranging 14 other electrons. So it's electronic configuration will be a R 3 to 10 for us to for P two. And when we talk about technology um its economic number is let's look for the atomic number of technology um has 43. So here 32 electrons will be already arranged. And the noble gas krypton and the remaining electrons will be Accommodated in 45 and five years to So this will be the electronic configuration of the Canadian. And finally we talk about salary um in this case the atomic number of Hillary um is 52. So it's electronic configuration will include krypton and along with that we will be looking for 16 more electrons to accommodate and that will be accommodated in 40. Our beetle, Certain electrons goes in the 40 orbital and two electron goes in five s orbital and four electrons which are remaining Goes on to five p orbital. So these are the electronic configurations based on the electronic configuration, after noble gas.

Hi there. In this question you are asked for the largest radius between the elements gallium indian or 10. So to answer this question, you need to think about the trend for atomic radi I. Mhm. Um Atomic radi I. Okay. Yeah increases down a group. Remember groups are the vertical columns on the periodic table. So as you go down a group, the atomic radio gets larger. That is because you're adding more energy levels, more electron shells. So the atom size is going to get larger as you keep adding an additional energy level or an additional shell moving down each group going across a period. Atomic radi I is going to decrease and across the period. Mhm. Mr. Yeah, because of course the horizontal rows. So it's going to decrease as you go across the period. So tom brady I increases down a group, it decreases across the period. So let's think about what that means. Where are we going to find the largest radi I. So here is a rough sketch of a periodic table. If radi I is increasing, going down a group and decreasing going across the period than the largest atomic radi I should be in the lower left corner and the smallest is going to be in the upper right corner. Based upon that trend. Yeah. So now let's place our three elements that we're looking at and the gallium is going to be right there. The indium is under the gallium and the 10 is off to the right. So as we think about this trend, Radio I increases as you go down. So that means indium is going to have a larger radi I than gallium. Both indium and tin will have a larger radio than gallium. So gallium is out and it decreases as you go across the period. So that means the indium is going to have a larger atomic radi I than the tin. So the one with the largest atomic radi I, is the India. Another way to think about this is of these three. Think about which one is closest to the bottom left of the periodic table. Whichever element is closest to that bottom left. Where is the where it's the largest, Then that element will have the largest atomic radio. All right, thank you so much for watching. I hope this was helpful.


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