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Jestion 18 0f 18whether thc teacton first-order; sccond-order; or third-order overall Classify each rale law basedSecond-orderThird-orderFirst-order#Mol#io]'Th...

Question

Jestion 18 0f 18whether thc teacton first-order; sccond-order; or third-order overall Classify each rale law basedSecond-orderThird-orderFirst-order#Mol#io]'Thte 6Ao ] [Brz]InIc = #roljo]Cnte 0snk#Noj?

Jestion 18 0f 18 whether thc teacton first-order; sccond-order; or third-order overall Classify each rale law based Second-order Third-order First-order #Mol #io]' Thte 6Ao ] [Brz] InIc = #roljo] Cnte 0snk #Noj?



Answers

Determine the number of moles (of molecules or formula units) in each sample.
\begin{equation}\begin{array}{ll}{\text { a. } 55.98 \mathrm{gCF}_{2} \mathrm{Cl}_{2}} & {\text { b. } 23.6 \mathrm{kg} \mathrm{Fe}\left(\mathrm{NO}_{3}\right)_{2}} \\ {\text { c. } 0.1187 \mathrm{g} \mathrm{C}_{8} \mathrm{H}_{18}} & {\text { d. } 195 \mathrm{kg} \mathrm{CaO}}\end{array}\end{equation}

Oh, but is solution. You smaller must to convert grams in two moles. So we have 55 0.98 g. See if you see it too into one more. See if do seal two divided by 1 20 point 91 tree fire Graham See, if you see into is equal to did um Adam Kinzinger So we have value 0.4 630 See if see if do c l two Morsi of Lucille do solution for Barbie But be if one word we have to convert when were killing ground instagram into grams Then use Moller muss to convert grams in two moles So we have 23 point sees kilograms off I even no trade Hold dries into 1000 grow if he in a tree hold rice divided by one kg Palffy you know three whole Joyce in Do we have one more? I didn if he in the three hole grace divided by 1 79.854 gram If e in a tree hold race is equal to do 1 31 Well, if e in a tree hold race But see use Moller muss Been word groom's into Mourners. So we have 0.118 c one gram. See it? It's a dean. One more. See it it. 18 divided very one went for going to to 78 Graham. See it? Edge 18 is he will do 1.0 tree nine multiplied. Didn't raised to the power Ministry more. I see it. It's 18 solution for body, then word kilograms into grounds. Then use Moller mice to convert to convert grams into malls So we give 1 95 kilograms See all into those ingrown see all divided by one kg See it all Calcium oxide Indio One more, See all divided bike You've just explained, you know, say 17 for Graham. See, it all is equal to three point for a multiplied raised to the power free No kinship Bauxite

In this question, they want us to complete the table for the reaction to X plus Y. Goes to products. They tell us that it's first order in both X. And Y. So we know that the rate expression therefore should be rate equals K. Times X. Times why? Mhm. Yeah. To complete this then we simply plug in what's given to find what is it? So for a you have that The rate which is not given. So the rate is what we're looking for equals K. Which is 1.89 here times X. Mhm. Time to die. Yeah. Well then find out that for this particular case the rate should be zero point 0756. You do the same thing for for the rest of them. So for B we get to the rate of 0.159 should equal K 0.884 Times X 0.600 Time. Is why? And we find that why should be 0.2 998 Mhm. For C. It's the same thing. So the rate of 0.479 equals K. Of 13.4 times X, which is unknown times Y, which is 0.25 And we find that X should be zero 0143. Finally, for D, we have at the rate of 0.00112, he calls the unknown K. Time is the concentration of X times the concentration of why We get the unknown K should be 0.008 zero.

So for this question we need to look at the following certain interactions and all these interactions uh do not occur. And we need to work out why which conservation was broken. Well for this one we can see that charge and barrel number absolutely fine. But when we look at the electron lepton and the Meuron lepton numbers the electron naptime we have one going to zero is sort of not going to one. And for the new one, little numbers we have one going to zero. Therefore both both are not and served part B. We have a neutral going to proton pass an electron plus a um electron neutrino. And here if we look at the electron lepton number we have zero going to zero plus one Plus one. So we have zero going to to which is obviously there for not and served and everything else about this is fine because obviously you have Are charges. zero. On this side are proton is plus charger electron is minus charge. So everything else is fine barrow number and arrange this is all fine part C. We have a sigma particle going to a proton plus a pie on. Well the first thing we should look at here is charge where we have zero goes to 1-plus 0. So charges not conserved. But also if we look a strangeness this is charged. We look at strangeness. Strangeness of a lambda. Naught is -1. It has one strange clock in it And on this side it's zero. So strangeness is also not conserved. So if this was a strong interaction or an electro majesty interaction, then this would also stop it from doing from the interaction working. And for party we have a proton going to an electron and a uh ion and the charge is fine and the leapt on. Uh So the barrier number here, Doug and barry on. You have one going to zero bus zero but therefore not conserved. But also if we have a look at the electron leapt on, We see that zero goes to -10. Therefore not concerned because obviously E plus is the anti Is the anti electron. The Positron which has an electron electron number of -1. And finally from part E we have um our see particle X. I. Is the X. I particle. Um and it has a rock formation of up strange, strange. And then it goes to a neutron and a pie. Not. So we can see the barrier number is absolutely fine. The barrier number here is one and here is one. Um the there are no Lepton. So we don't need to worry about that, the charges absolutely fine. But when it comes to the strangeness here we have -2 and here we have zero. So therefore the strangeness is not conserved or our last part E.

Hello students in discussion we have to find the number of degree of freedom of the molecules in a gas. So for the part a had the constant pressure cps given as 29. You'll per mole kelvin. Okay, so CP It is equal to gamma. Are they were being comma -1 which is equals to 29. So gamma molecular B R. Which is 8.314. The verb gamma minus when it is equal to 29. So after solving gamma is often as 1.4. So degree of freedom. It is equal to to develop a gamma minus one so to develop a 1.4 minus one. So we get from here, degree of freedom it is equals two five. Okay so this is the answer for the part eight. No for the part B We have a process PT it is equal to a constant and the sea, it is equal to 29 tool per bull calving. Okay, so for this process we can write that from the ideal situation after combining the square by V. This will be constant. So we can right after differentiating to DT by t minus D. B Y Vi it is equal to zero. So hence we can write that. See more popular deity. It is equal to C V. D T plus pressure P D V. Okay, so we can write that from here that this is equal to see mercury DDT. It is cv molecular DT plus pressure from the ideal situation can be written as artie by the more popular B D B. So DB by V. From here, this can be written as two times of ctbt. So Seymour player validity. This is equals two. CV DT plus two. Uh This artie divided by volume V. Molecular B D T DVB T. Okay, so after solving we will obtain that C. V. It is equal to c minus two. Are so see which is 29. So 29 divided by 8.3 more players are, this can be rearranged in the term of art minus two are so CV from here is 12.4 divided by 8.3 more players are so CV from here is equal to three by two. R and C B is equal to three by two. Are Then degree of freedom. It is equal to three. This is a mono atomic. Okay. And the previous one was diatonic because of degree of freedom, that was equal to five. Okay, thank you.


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