All right. So for this problem, we have Ah, we were laser. Be so we already know that the laser, the laser beam has power Pequot. So there's the party. The power is that 2 50? Meaning what? And we also know the time for this These air been I mean for this post is uh ah. The total time is, uh, 1.5 made its second some part. I want to find out the energy for this pulse, so ah, we know that the energy equal power of times time. Right? So this gives the total energy of his pulse. So it's simply to 50 minute walked times 1.5. Wait a second. And this gives you Ah, 0.3 75. Many Joe's okay, in part B. Ah, we want to Ah, let me see. I want to find out the pressure induced by this. Ah, by this pulse. So you know, textbook, you can find the relation between the pressure of the laser beam and the intensity of the team. So the relation is Ah, the pressure. Radiation pressure equal. I oversee. So we're eyes. The intense intensity off this beam and C is the speed of light, so Ah, the intent. The intensity is defined as Ah, pee over s We're peas. The pressure, which is Ah, are peas. The power which is the one we found over here. And the S is the ah effected area off this Ah, of this laser beam. Because in this problem, we're considering situation that to the PM is ah fully absorbed by this Ah, normal surface. So this is the relation and the develop a c So Ah, we already know that the P is the 2 50 You know what? So the area is ah pi r squared right? Because it's it's just a circle circle area pi r squared and the rabbi sees sees the speed of light which is a constant. So the ari's not directly given the problem. But we already know the diameter d. So you can utilize the diamond her and ah, because our the radius equal d over too, right? So I can find out the radius of this beam and just plug in the number and they would see that it finally from the final result for this Ah ah, Radiation pressure is 4.8 minute Posca and in part, see Parsi. So suppose the laser beam enters into the human eye. We want to find out to the I basically want to find out that the frequency and the speed and the ah, the way blinds off the lights inside the eye. So Ah, we already know the reflection. The refraction factor inside the eye is that 1.34 So it'sjust idea case. So given this information ah, we also know that we've lands off this light Ihsaa So ah, this web lenses the weapons in the vacuum. Okay, so let's say this is a Lambda V V labels the vacuum So this is eight ton nano meters and ah, the speed of light. I mean, the speed of this beam is just the speed of light, which is a constant c. So let's see, this is the CVI, okay? It's also the labels, the vacuum, which is the three times 10 to the 10th meters per second and the frequency ihsaa Ah, the falcons. That can be calculated by this two variables. So the frequencies a c v three c v. Do you buy London? Be so just to use this to values and come in the character of this pregnancy. And the better you can tell us. Ah, three point 74 times turned to the 14th. I'm sorry. Just remove it. Times turned to the 14th hurts. Okay, so remember this our the situation in the vacuum because we want to find out the information. It's not the eye. So we need to do some more calculations because we're writing. Though the reflection factor is ah 1.34. So, basically, if the if the beam enter the eye the the frequency, we will remain unchanged. So their frequency if I simply equal to f b Okay, so it's the one that we found over here. 3.74 times 10 to the 14th herds. Remember? Ah ah for the electric magnetic wave. If it enters from one interior to the other material the frequency we're not We're not change. Okay, so you're the frequency would not change the change. Variables will be the wee plays and the speed. So basically the speed. Sorry. It's not to see the anymore. It's Ah. See, I see. I So the speed will be Ah, smaller. It actually a quote CV divide by in. Okay. Any of the reflection factor over here. And you consider that this study was Ah, Let me see. Two point. Ah, Hey, I think this I think I've done wrong calculation. Ah, but you can You can figure out this number. Okay, I think Michael Clayton, my number. He's wrong. But two CV here is simply three times 10 to the eighth and a is right here. And you could just use your calculator and do this one simple calculation. So this is the speed of light speed off lightly in there in the night. And the wavelengths Lunda I also it is also shrink tw so this becomes lumber V over, over in so long. Davey is right here. Ah, it's 802 millimeters and a CZ right here so we can find out this. Ah ah, We've lensing I which is the 604 Yeah, I believe this is right. Nine meters. So there's a parsi so far apart, D Let's see. Ah, we want to find out Ah, the maximum value for the electric field and magnetic field for this electromagnetic wave. So basically Ah, there's a relational textbook. Ah, and claiming that the intensity off the beam equal half Absolutely not. Times C times e. Max squid. Okay, so absolutely is the electric constant in the vacuum and the seas, the speed, the lights also in the vacuum. And e max is the one that we were gonna find out, which is the maximum, which is the magnitude of the Electra feud. So the intensity is the one that we have. Ah, we have figure out in the previous part. Let's see. Ah, intensity. Intensity. Is this one p over s. So this is the intensity. Okay, p or ass. So you can see that. Ah ah, All the variables are known in this equation. We already know intensity. We know this constant and we know this constant so we can figure out the value of the off this imax and you can just to solve this equation easily. And to see that imax equal Ah, 30.3 curable per meter. Okay. And the relation between the magnitude off the electric field and magnetic field in the electromagnetic wave. This Ah, you next equal. See, time's be Max. So C is also the speed of light in the vacuum and be Maxie's. The magnitude of the magnetic. A wave. So you came to IndyMac's equal. You next over seat. All right. And this gives you one No. One. Ah, micro Tessa. Okay, so, yeah, that's all.