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Giving test t0 # gruup Of students, tbe grades end Bender arerieed belowTobalMaleFemaleTotalIf one student i5 chosen at randomFind the probability that the student ...

Question

Giving test t0 # gruup Of students, tbe grades end Bender arerieed belowTobalMaleFemaleTotalIf one student i5 chosen at randomFind the probability that the student WAs NOT female that got

Giving test t0 # gruup Of students, tbe grades end Bender are rieed below Tobal Male Female Total If one student i5 chosen at random Find the probability that the student WAs NOT female that got



Answers

This problem requires that you first obtain the gender and handedness of each student in your class. Subsequently, determine the probability that a randomly selected student in your class is a. female. b. left-handed. c. female and left-handed. d. neither female nor left-handed.

In question 14 says the math conference has an attendance of 4950 people, 2110 are college professors. Just put CP and 2575 are female of the college professors 960 or female. So we know that there's 960 female college professors found the probability that air randomly selected Yeah, attendee is female or a college professor. So the probability of female or a college professor. So the probability of female or a college professor in this case would be the probability of female plus the probability of a college professor. And we have to subtract the overlap where that happens at the same time. But we're given all of those things here. Uh, the female would be 25 75 out of 4000, 150. We know that there's 21 10 college professors out of the total, and we know that 960 of those cause professors are female. So we're gonna take that 960 out because they have already been counted, um, in both situations, so they're double counted right now, so the denominator stays the same through the process. We just need to add together the enumerators 25 75 plus 21 10. We're gonna subtract the 9. 60 and we get 37. 25. We can reduce this 21 49 over 1 98. Or we can, Right? This is a decimal, which is point 753 and we can even turn this into a percentage. Approximately 75.3%.

Hello, everyone and welcome were given this probability question. And let's write down what we know. We know that 1254 people. So it's total is equal to want to 54 We know that they were total women were 672 and of which, uh, 124 went on to grad school. So, grad women, what is equal toe? 124 then for men we have There are, um, 582 graduates. Oh, yes. 582 of which 198 went on to grad school. Yeah, So we want to calculate a few probabilities. Number one. We have to calculate the probability off. Female, male and female did not attend graduate high school. So quite a B and C. So the probability that they randomly select a female is the total number of females divided by the total number off graduates, which, as we should have a peer, is 1254. So we're essentially just doing 6. 72/12 54 which is 0.54 next for male. Um it is going to be the same thing. So how many males were there? How many men were there? 582. And how many total were there 12. 54. Therefore, this is equal 2.46 and we can confirm that this is correct, because when you add up these two probabilities, it adds up to 1.0, which is how should be in this case. So we can confirm that those air correct. Next, we want to see, um what are the probabilities that the person is female and did not attend graduate high school? Well, how many females did not attend Graduate High school? 670 to minus 124 which is equal to 548. Okay, so it will just be 548 divided by the total number of people which is equal to Oh, no, absolutely. Refresh the page. Well, im four party we had 548 divided by 12. 54 which is approximately equal to 0.44. So are the answers are 0.54 point 46 44. So thank you for watching. And I hope this helped

Okay, so it's a right out given information that we're told. We're told that will write f for freshmen and s for sophomore or told that there's 18 freshman in 15 sophomore and we'll write M for male. Out of of the 18 freshman, 10 out of 18 are males, and out of the 15 sophomores, eight out of 15 are males. And now the question for part A is. What's the probability that we have a freshman or a female? So in total, there's denominator of 33 33 possible options, adding up the number of freshman and sophomore and 18 of them could be freshmen. That's including male and female. And now we just need to find the number of females that are sophomore. And that would be 15 minus eight. That seven. So seven plus 18 It is your answer for port A. Because you're adding in all freshmen and then just saw floors that are female. And now, for be for question, be were asked to find the probability that we get a sophomore or a male, as opposed to a freshman or a female. So again, we know the denominators 33 and the number off sophomores is 15 and the number of males that are freshmen is 10. So simply by coincidence you're going to get the same answer. But of course, it's for different reasons, and that is how you do this.

In a pre calculus class, there are 18 freshman Mhm and 15 sophomores. of the 18 freshman, 10 are male and they are female, And of the 15 sophomores, eight are male And seven are female. The probability that a randomly selected student is a freshman or female is 18 plus seven Over 18 plus 15, Which equals 25 over 33. Yeah, And the probability that a randomly selected student is a sophomore or mail is 15 plus 10 Over 15 plus 18, Which equals 25/33.


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