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(b(a} For Consider E} all each the 2 aplaling choice set line of 4) and 2 and R3 N 9 with 5 In 2 % ahc , (1. Ti for J a,2d which IZA You COmhination It(h; the 1(2 ...

Question

(b(a} For Consider E} all each the 2 aplaling choice set line of 4) and 2 and R3 N 9 with 5 In 2 % ahc , (1. Ti for J a,2d which IZA You COmhination It(h; the 1(2 ] 4 set Iline 14) 11,,2)} 2 5 of points part 7 Ald 2 of V2 [i the express "form the (3,2,a) point +t(b, (I,y,2) 7

(b (a} For Consider E} all each the 2 aplaling choice set line of 4) and 2 and R3 N 9 with 5 In 2 % ahc , (1. Ti for J a,2d which IZA You COmhination It(h; the 1(2 ] 4 set Iline 14) 11,,2)} 2 5 of points part 7 Ald 2 of V2 [i the express "form the (3,2,a) point +t(b, (I,y,2) 7



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Point at a distance $14 / 5$ from the line Column 1 (a) $3 x+4 y+7=0$ (b) $4 x-3 y+3=0$ (c) $3 x-4 y+19=0$ (d) $4 x+3 y+9=0$Column 2 (p) $(1,2)$ (q) $(1,1)$ (r) $(2,-1)$ (s) $(-3,-3)$

And this problem let us draw the line element and L. This is the point one comma two And 1:02. The midpoint of X comma 01 zero comma Why this line is really And the pope in nuclear by sector to this. You're doing something like this. These lines perpendicular. This is hello. So for line L slope equal stupid minus Y by X. Also since 1:02 is the midpoint. You can see that Express zero x 2 has to be equal to one. And why plus zero x 2 has to be equal to two. Yeah, I'll be good. Why X. S equal to do And why is equal to 4? And the slope we get as -2. And the equation of the line and what's written as why buy food just expired. Two is equal to one using the interceptions and written like this. Well we get like this The works equals to four. Similarly for nine L 1 slope will be such that the multiplication of stuff with the L. Is -1. So this is equal to half. And the equation which slope has this in passing through one common to Why AM -1 equals to have So this is why am I understood equals to have x minus one and passes through minus two comma one which makes this one by two express to As it passes through -2 for my one. And this becomes two minus X equals to four, solving these two equations together. We get X equals to four x 5 And why equals two 25 5. So the point of intersection of the two lines. This is not the point of intersection somewhere, right? All by favor. Somewhere here. That's.

Hello and welcome. We're looking at chapter 12 Section two. Problem 20 on this problem were given two points to coordinates. Rest a form, a vector of those two points, but it needs to be in standard unit vector form. So, uh, that will look like V equals view one eye plus the two J plus the three K. Now, remember, I Is it a unit vector? It's the unit. Vector 100 Jay is similar, except it has a one on the Why coordinate and Kay Isa Unit Vector as well. I jane care the three unit vectors. A standard unit vector is sorry. Um, since the 001 okay is like ze court. So the first steps we need to find a vector, uh, make a vector out of these two points A and B. So the easiest way to do that is to use component form into terminal Maya's initials. We subject the terminal X value most initial X value and so on. For each record, this will be terminal mass initial negative, one minus one. So, be is the terminal. It's the second letter that makes it terminal is the first letter that makes the initial uh Then we do terminal minus initial for the why or minus zero and then five minus three. Dizzy. The third component. Simplifying this. We get negative too. Or two. Now, this is a component form it asked us for to put it in this form, this standard unit vector form all we have to do eyes look at the the first component second component in third component They listed as V one V to be three and the problem could think of them as the X, Y and Z. They just go with the corresponding unit vector. So you just multiply negative to buy I for by J and then to buy K. Now it's worth remembering that if you expanded I J and K into their unit vector forms and then did the scaler multiplication and added those three vectors together, it would lead you right back to the component form. So we were asked to take these two points A and B find the final vector a B and right in this standard unit vector form, the one I will speak to J plus the three K. That is exactly what we found here.

Give me the points. Q. Nor we want to find Victor QR So we'll take the two from the R minus the three from the queue and the six minus and negative four giving us a vector. Negative 1 10 And we want to express this an AI plus BJ form. So I and J are you defectors? I is the vector 10 j is 01 Okay, we're gonna take negative one times the in effect, er 10 plus the 10 times Uniph Actors, You were one. And since 10 is I could say that's negative One eye. And Steve Irwin is Jay. We could say that is 10 j and that gives us negative I plus 10 j.


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