For this question. What we have is we've taken a single DNA strand and of course, we have multiple copies of it, and we've broken it down into sort of randomized fragments between each of our different strands. So here we have six different strands each which could make up a singular section of it original DNA strand. So where I like to start from this is to start from a small strand where we can easily relate it to others. So if we look for very significant or unique feature in this first strand, we can see that there are three A's in a row. So if we find three days in a row in one of our other sequences, it's likely that would be a similar or contain this whole sequence as part of that strength. So at number two, you can see we have these three A's, and if you travel your way back, you can see that this fragment portion is similar to this strand. So here we just have this strand located right here in fragment number two. So from there we have the rest of the original DNA sequence, so we just need to look to make sure we don't have any additional DNA nucleotides on either the five prime or three prime ends of the strands. So again, if we look for the Triple A, we can see that we still have this see from the original first Strand, and we're going to have the rest of Fragment three able to be found in fragment, too. That fragment. For if we look through here, we can see that there are no Triple A's. However, you can see that there's a triple C here, which is pretty unique, which relates to the triple C found in Strand two. So here, fragment for is just this beginning portion of fragment and Strand two. So we can't grab any nucleotides from either three or four as long as we make sure to include that C from Fragment one. If we move on to five, we can see the Triple A at the very end, and it's going to continue on the five prime end until it reaches this similar strand at the beginning of Strand tube. So we don't have any new nucleotides from five either. However, if we look at six, we can see there are very different unique features here. There's a triple T, which is not found in any of the other strands. So we need to find where this strand is located in Strand number two, which contains the majority of our d N A sequence. So if we look at the very end of Strand six, we see this G c a a t. But you'll also find at the very beginning of Strand number two so you'll see this G c a a t. So here's Strand six is the nucleotides that are going to be found before strand number two. So here we just need to include this new portion of nucleotides two Strand number two, and we have our whole DNA sequence. So if we combine all those strands together and their correct sequencing of one another, we're going to get our final strand or a continuous strand of a T T. T, which you'll find in Strand number six and then you can write in strain number two a. C C T C A T a C C C T A g to t A. And then you just have to include the final see nucleotide that you can find in strand number one or some of the other strands. So here this would be the nucleotide sequence for the full strand that each of these fragments originated from, and that should complete the question.