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What mass of A/3+ is present in 57X 1015, formula units of Al203?...

Question

What mass of A/3+ is present in 57X 1015, formula units of Al203?

What mass of A/3+ is present in 57X 1015, formula units of Al203?



Answers

What is the mass of $4.91 \times 10^{21}$ platinum atoms?

I'm the mass in kilograms. If it is equal to you 18.99 8404. You so we know that one atomic unit is equal to 1.66 05 Into the -27 kilograms. So the math in kilograms are when we multiply these two together ramon supplying by something that has five significant figures. So our answers should have five significant figures, 31 point 547 10 to the negative 27 kilograms.

No problem. 20 and chapter study to this problem. Ask us. Calculate the math 60 koban in cancer therapy and it had a charity over 5000. A cure it. You know that if I was out in the Curie Eco's five SOS in the Times 3.7 times tend to the 10 speak you Security coasting case per second. That is for calculation of the number off Koban 60. And we also know that activity is defined as the mess over the Moola mess. Oh Colbert call about times the number attempts of the other Godel number and times Look two over is half lifetime. The former Wikipedia we know that is half lifetime is 5.271 four years so we can use a lick. Calculates the math off the 60 call about the eco's Okay, the activity ating is give it a number is 1.485 times 10 to the 14 speak you okay, so mass is eco's 1.85 times 10 to the fourteens and sometimes a small amassed 6 60 times the half time fire upon 2714 years. You want your eggs? 365 days Any one day there is 24 hours and when I was is so 3600 seconds and over long to look too. Terms of a gag rule number explained. Or 22 times 10 to the 23. Yes, and this will give us the mess we plug in the numbers in a calculator. Ricky. What we get? A result or 4.42 grams?

So we're looking for the massive coop right? That has 10 g of copper. So we could say 10 g of copper is equal to some unknown amount of coop. Right? And thats proportionately equal to the percent composition. Which is going to be two times the massive one copper atoms, 63.55 mhm copper divided by the total mass of coop. Right? Which is the molar mass one 43.9 g. So then we have 10 times 143.9 is going to be 4 30.9. It was two times six. Well, let's just simplify it. Two times 63.55 1 27.1 X. So then X is going to be 1430.9 divided by 127.1 or 11 point three g. Of course. Right.

So we're trying to find the mass of 4.35 times 10 to the minus two moles of zinc chloride. You're gonna need appear in a periodic table for this because you're gonna need to calculate the molar mass of zinc chloride that's over on the right of the screen. There. I've got the molar masses for zinc and chlorine, and you know the right formula for zinc chloride. So it's the massive one zinc and to chlorine, and that's 136.28 grams per mole. And then it's simply a matter of doing the math, and you get 5.93 grams of zinc chloride.


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