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Check My MertCManncra[ part Kenseng, comntn space-heater fucL 61 mixture nf hydrecrbons whose Acrage formuh i CuEzc (a) Detemine the balnced cquition; the simplatrh...

Question

Check My MertCManncra[ part Kenseng, comntn space-heater fucL 61 mixture nf hydrecrbons whose Acrage formuh i CuEzc (a) Detemine the balnced cquition; the simplatrhole_number coeficients for the complcic combustion of kcrosenc t0 gE6. Indude payical suates of ech mactant and product() IfAE? FLSO * 10"EJ (or the combustion equation Ttten part (2), determine AH KeroscneEJlmol(c) Calculate the heat produced by the combustion of 0.64 gal of kerosene (d of kerosene 0.749 gmL)(d) How nm ol Lerosc

Check My Mert CM anncra[ part Kenseng, comntn space-heater fucL 61 mixture nf hydrecrbons whose Acrage formuh i CuEzc (a) Detemine the balnced cquition; the simplatrhole_number coeficients for the complcic combustion of kcrosenc t0 gE6. Indude payical suates of ech mactant and product () IfAE? FLSO * 10"EJ (or the combustion equation Ttten part (2), determine AH Keroscne EJlmol (c) Calculate the heat produced by the combustion of 0.64 gal of kerosene (d of kerosene 0.749 gmL) (d) How nm ol Leroscne must bc burncd for Eeroscnt fracd {Sllons to produce ],073 Btu (1 Btu ' 1.035 gallons Pre; 20 : 30



Answers

Kerosene, a common space-heater fuel, is a mixture of hydrocarbons whose "average" formula is $\mathrm{C}_{12} \mathrm{H}_{26}$
(a) Write a balanced equation, using the simplest whole-number coefficients, for the complete combustion of kerosene to gases.
(b) If $\Delta H_{\mathrm{rxn}}^{\circ}=-1.50 \times 10^{4} \mathrm{kJ}$ for the combustion equation as written in part (a), determine $\Delta H_{\mathrm{f}}^{\circ}$ of kerosene.
(c) Calculate the heat released by combustion of 0.50 gal of kerosene $(d \text { of kerosene }=0.749 \mathrm{g} / \mathrm{mL})$ .
(d) How many gallons of kerosene must be burned for a kerosene furnace to produce $1250 . \mathrm{Btu}(1 \mathrm{Btu}=1.055 \mathrm{kJ}) ?$

For part A. Let's rate the reaction for the combustion of one mole of C eight h 18 liquid combustion. We'll react with oxygen to produce carbon dioxide and water. So here is our balanced combustion reaction for one mole of C eight, age 18. Using this, let's calculate the Delta H Town of Formation for C eight age 18 to 34 Try mouth upended. Well, first, calculate the I want to be a formation for the reactant, since which is equal to the therapy of formation of the C eight h 18 plus 25 over to on the p A formation of the oxygen gas. Got the H, not formation of the reactant since stick with the Delta H Non information. This is an unknown C H H 18 liquid plus 25 over to the top you information of +020 Therefore, the personal information of the reactant since is equal to the Delta h not information of we see it h 18 liquid. Let's now look at the products the delta each not information of the products is equal. Thio eight times Delta h not information of co two gas plus nine times a Delta h not a formation of H +20 Guess this is equal to eat. Times negative 3 93 5 killer jewels plus nine times negative to 41.8 Killer Joel's This will give us negative 5324.2 killer jewels for the Delta h not information of the products. The Delta h not of the reaction is equal to you. The delta each not formation of the products minus two Delta h not formation of the reactant. Let's fill in our values here. The question gives us the delegation. Information of the entire reaction is negative. 5000 and 64.9. Killer jewels of the confirmation of the products is negative. 5324.2 killer jewels minus Delta Nation. Information of the reactions we saw was equal to negative Delta H not formation of the C H 8 18. Therefore, solving this equation they have to be information for the C H. Each 18 is equal to negative. 259 3 Killah jewels

In this equation were asked to write some thermal chemical equations and play has this law for 234 tri metal plantain, which is, see what's wrong problem. See eight H 18. Also here C eight H 18. And our next page it'll be C eight H 18. So our thermo chemical equation. And actually I just noticed I'm just supposed to write a balanced chemical, not a thermal chemical equation for that one. So this is for combustion. So for combustion we have our fuel and all congestions have his reactant, oxygen. And for complete combustion our products are carbon dioxide and steve. Okay, now this has to be balanced. And when I look C eight H 18 up, I get my delta heat of formation is negative 5064.9 kg jewels. That's just a number. I looked up at the table. I have to keep my one right here. I don't like to put one's in equations, but in order to do that, that means that this is going to be 25/2 and I believe I got an eight and a nine. So there's my balanced chemical equation. This doesn't look very good. I'll make this look a little better. There we go then. Second, the formation of C eight age 18 from its products which are carbon or from its elements. Don't forget we have to include that. So there's a balanced chemical equation for part B. And for the last part were asked to use has this law to write a balance? And what are we doing here? Use has a sought to find delta H. Of the reaction, which of course is the summation of the products product delta H. Is minus the summation of the reactant delta H. S. So we can just look these up first, the products and I like to put in brackets first. So my products, my products are CO two politico to appear. And if we go back to our balanced chemical equation, I'm gonna go back here for a moment. We had for CO 28 nine and one for this. Remember that our delta H. Uh for this is zero because it's an element and in standard states. So there we have our heats of reaction and we are going to take eight times. I'm looking this value up on that appendix C. 3 93 0.5. Now all these are killer jewels but I'm going to leave it out for the sake of I'll just put it down here real little and we're going to add to that nine times for steam. It was negative to 41.8. Again, killer jewels. And from this we're going to subtract and remember their waters are oxygen is zero. So it's gonna be one. I'll put the one in there. A negative 506 49 Killer jewels plus zero. Okay, good enough. Do the math on here. And I got negative 2 59.3 killer jewels. Problem solved.

First the given volume is converted into mass. Mars is equals two volume into density. The given but you miss one letter to convert it into a minute later multiplied they do 1000 ml up one one. They do. And if I buy given density is 0.69 grandpa. Me the leader. Therefore this equals two 6 90. Graham moral myself. C eight 8 18. Yes equals two 18 to atomic mass of carbon is 12.0 107 graham farmer. Yes, 18 into atomic mass of 5000 is 1.0079 room for more equals two 114. Why to to 78 grandpa. Most Therefore mama's of C 88 18 is 114.2278 trample more. No number of moles is supposed to must up one more. Armas he goes to Moss is 6 90 g and moral mass is 114 12 78 Yeah. Buy more. Well stop six point. Do you know for what? Therefore the entropy change is Few years equals two. And into enter field the direction. Standard interview the reaction so and and and re business number of moles and that are is not represents tender entropy of the reaction. The number of more is 6.04 more into senator entropy of the reaction is given that is 109 two. He knows you. Uh huh. Two more. This is close to strategy. Why? Sorry. 3.3 and two tend to the ball fall. You know sure that given reaction is extra thermal. Hence the entropy things value should be negative therefore. Yeah. N therapy chains value is yes it was too minus three point. See into 10 to the power for you know do

In this equation. Were asked to write some thermal chemical equations and play has this law for 234 tri metal plantain, which is see what's wrong problem. See eight H 18. Also here C eight H 18. And our next page it'll be C eight H 18. So our thermo chemical equation. And actually I just noticed I'm just supposed to write a balanced chemical, Not a thermal chemical equation for that one. So this is for combustion. So for combustion we have our fuel and all congestions have his reactant, oxygen. And for complete combustion our products are carbon dioxide and steve. Okay, now this has to be balanced. And when I look C eight H 18 up I get my delta heat of formation is negative 5064.9 kg jewels. That's just a number. I looked up at the table. I have to keep my one right here. I don't like to put one's in equations but in order to do that, that means that this is going to be 25/2 And I believe I got an eight and a nine. So there's my balanced chemical equation. This doesn't look very good. I'll make this look a little better. There we go. Then second, the formation of C8 age 18 from its products which are carbon or from its elements. Don't forget we have to include that. So there's a balanced chemical equation for part B. And for the last part were asked to use has this law to write a balance. And what are we doing here use has a sought to find delta H. Of the reaction, which of course is the summation of the products product Delta H. Is minus the summation of the reactant Delta H. S. So we can just look these up first. The products and I like to put in brackets first. So my products, my products are CO two politico to appear. And if we go back to our balanced chemical equation, I'm gonna go back here for a moment. We had for co 28 nine and one for this. Remember that our Delta H. Uh for this is zero because it's an element and in standard states, so there we have our heats of reaction and we are going to take eight times. I'm looking this value up on that appendix. C 3 93 .5. Now all these are killer jewels but I'm going to leave it out for the sake of I'll just put it down here real little and we're going to add to that nine Times for steam. It was negative to 41.8. Again, killer jewels. And from this we're going to subtract and remember their waters are oxygen is zero. So it's gonna be one, I'll put the one in there. A negative 506 49 killer jewels plus zero. Okay, good enough, do the math on here. And I got -2 59.3 Killer Jewels. Problem solved


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