4

At 10:17 a.m., YOU pass a police car at 55mph that is stopped on the freeway: You pass a second police car at 55mph at 10.53 a.m., which is located 39 miles from th...

Question

At 10:17 a.m., YOU pass a police car at 55mph that is stopped on the freeway: You pass a second police car at 55mph at 10.53 a.m., which is located 39 miles from the first police car: If the speed limit is 6Omph, can the police cite you for speeding?Find your average velocity from the 10:17 a.m. to 10.53 p.m.mph Round value above to 2 decimal places_By the MVT, since the average velocity over the interval was Morethan the postedspeed limit of 6Omph the police Cansite you for speeding:

At 10:17 a.m., YOU pass a police car at 55mph that is stopped on the freeway: You pass a second police car at 55mph at 10.53 a.m., which is located 39 miles from the first police car: If the speed limit is 6Omph, can the police cite you for speeding? Find your average velocity from the 10:17 a.m. to 10.53 p.m. mph Round value above to 2 decimal places_ By the MVT, since the average velocity over the interval was More than the posted speed limit of 6Omph the police Can site you for speeding:



Answers

At 10:17 a.m., you pass a police car at 55 mph that is stopped on the freeway. You pass a second police car at 55 mph at 10:53 a.m., which is located 39 mi from the first police car. If the speed limit is 60 mph, can the police cite you for speeding?

Well from the given beat frequency, we can find out the frequency reflected big toe. An observed by, uh, the re dollar. Then we have don't have Delta is equal to, uh, if not minus. Ah, Sorry. Its source frequency address and f is minus f Not here. Delta is the beat frequency actresses the frequency of the Radio Micro where emitted by the radar and if not, is the finally frequency observed by the radar. And let's find out if not, well, delta after he's, uh, 3000 to mine 100 on, then we have f s, which is 33 point fuller. Multiply by 10 to the power nine minus f not right. And therefore, if not, if not, it's equal to, um three point. Ah, Treaty three on here. 9999 uh, 61 Multiply by 10 to the power than hers. Uh, 10 hearts. All right? No, we have are a 33.4 a month apply by 10 to the power nine minus, if not, is equal to minus 3900 And in this case, we get, if not, is equal to 3.34 Our tree buying train foreign 0000 39 Multiply by 10 to the power 10 hers damn horse. And this mentally depends whether the car was approaching the police radar or whether it was receiving away from the police. Ah, radar. But if the driver was approaching the police radar than the final frequency observed by the police, radar would be creator. And if the driver was receiving away from the police regard and the final observed frequency would be smaller than NATO, the frequency off the immediate source where well, in in either case, both frequencies would result the radar to detect the same beat frequency. And in both cases the guard would have the same relative lost e but with opposite signs. And knowing this, we would stick toe either of the two frequencies to try to find the relative the lost two of the guard Ah, say that the card is approaching the police radar and the Doppler seek regions are used to find the observed frequency. But in the given case in this problem, we're actually, uh, have aware that reflected big from the guard to the radar, which means that this will have experience Doppler in fact twice where the first time The very expedience doctor, in fact, is when it is approached. We need approached the car where the frequency by with the radio benefits the Sechrest off the car is not the same. Is there off the microwave frequency emitted by the radar? But since the God is moving and approaching the radar as this would experience a Doppler, in fact, and here the detected frequency F D is a call to everything to one bliss redivided by See and here efforts physical to F d. Right. And therefore we can write, if not, is equal to efforting to one place we divided by C right? And let's solve for me uh, we is equal to ah screen Rudolph, if not divided by if not divided by f is minus one multiply by sea and plugging the values we musical too. Ah squared Rudolph A 33 point four 0000 39 divided by 33.4 minus one. Multiply by three, Multiply by 10 to the bomber eight and this uses 17 point 515 meter up for a second. And since this is uh a 29 meter per second speeds on then This driver was not speeding. The driver was not speeding is his speed walls 18 meter per second?

So based off the table, segmented petitions of five. So, for example, we have 66 to 70 and remarks that that corresponds to 3717 cars. So there's no way for us to tell which cars are going at 70 MPH. Because although it's extremely unlikely, it could be possible that off the 66 to 70 statistic zero of the cars were going 70 and that all 3713 for example, could be going at 66 MPH. And because of that reasoning, it's impossible to tell impossible to tell which motorists were going 70 MPH.

In the second size, we're gonna talk about the relativistic. Not perfect. Consider that we have a light source. That's a meeting light at a frequency F zero and we have an observer that's moving with respect to the light source with a speed V, this observer sees the light with the frequency F that's equal to have zero divided at times. I'm sorry. Square root off. See those reminders We divided by C minus surplus V, where the upper sign should be used when the two objects are approaching each other and the minus sign when the two objects are receding. Okay, so, uh, we can make an approximation when view overseas much smaller than one. That is when the relative velocity between the two objects is very small and the approximations has a deficit which has zero times one plus or minus. We oversee where the sign convention convention remains the same. The upper sign is when they are approaching the minus sign when they are receiving eso. What we have in our problem is ah road. You're traveling through a road where the speed limit V L is equal to 29 m per second, which is equivalent to 65 MPH. And you have You are stopped by a police officer who says that you were speeding. The police officer measures your speed using a raider gun that works with the frequency F zero off 33.4 gigahertz. And he pointed the radar gun towards you and saw a beat frequency. Um, 39,000 Hertz. Okay. And now it's nice to stop the second just to remember that the beat frequency is the difference between the observed frequency by the radar gun and the emitted frequency. Yeah, and our goal is to find whether or not you were speeding. That is, if you were above the speed limit. Okay, so I've noticed that in our case, VL oversee is 29 divided by three times into the eighth. So this is much smaller than one. So we're safe using the low speed approximation. And the set up is as follows set up before a problem. Here we have a radar gun. Yeah, and the radar gun emits waves. You had a frequency F zero. The waves hit the car. I'm gonna hear the car a little differently. Um, they hit the car, which I'm considering that the car move is moving towards the reader. Good. Okay. Yeah. The car sees this thes waves shifted because the car is moving towards the radar gun to your frequency. F D and F D is equal to have zero times one plus v develop. I see. Okay, now the car reflects the waves and the car will reflect the wave at the frequency F D. No notice that according to the car, the radar gun is moving towards the car, meaning that the radar gun will observe a final frequency F o which is equal to F. D. Sam's one plus view oversee. So I noticed that in the end, I've always equal to F d N F. D s one at zero times one plus you ever see times one plus you receipt. So this is F zero times one plus two viewers see must be squared over C squared and the last term we can be canceled because V overseas much more than one. So we shouldn't really take into account quadratic terms. So in the end, have always equal to have zero times one plus two viewers see another said the beat frequency is equal to f o magnitude of O minus F zero. Okay, so this is equal to F. Oh, that's a zero times one plus two viewer C minus F zero. So this is to f zero v oversee. Yeah. Okay, So our goal is to find V to see whether or not you were speeding. So v is equal to the beat frequency times the speed of light divided by two times of zero. So, using the information that we have, you know that the beat frequency is through 3900 hertz and we have two divided by two times F zero, which is 33.4 gigahertz, 33.4 times into the nine thirds times. See? And C is 10 3 times 10 to the eighth meters for a second. Okay. And this is equal to 17. Okay. 0.5 m per second. Notice that this is smaller than the limit, which is 29 m per second, meaning that you were not speeding. This concludes their exercise


Similar Solved Questions

2 answers
Caleulate the flux of the vector field F(z,y.=) = (3ry?,re? across the surface $ (that is find SSs F.as) where S is the solid bounded by the cylinder y? + = ] and the planes ? ~1 and I = 2- (Hint:Use Divergence Theorem) .
Caleulate the flux of the vector field F(z,y.=) = (3ry?,re? across the surface $ (that is find SSs F.as) where S is the solid bounded by the cylinder y? + = ] and the planes ? ~1 and I = 2- (Hint:Use Divergence Theorem) ....
5 answers
MemeLilinett 4 24CchCTCCH CMcH; 43 ~CNCFLCh 4x"xC ChCh Ch C CCHLA0i04 Hi_ Cuch,Pape $ o4 17
Meme Lilinett 4 24 CchCTCCH CMcH; 43 ~CNCFLCh 4x "x C Ch Ch Ch C CCHLA 0i04 Hi_ Cuch, Pape $ o4 17...
5 answers
If V =u =then the length of the projection of along:SI312/2 E. none of theseV6/23V6 /2D. 242/38. Which of the following is a description of the orthogonal complementis the set of vectors that are orthogonal toNote:upds = $of S:5l = spansB. 51 cunds =A_ upds = -S
If V = u = then the length of the projection of along :SI 312/2 E. none of these V6/2 3V6 /2 D. 242/3 8. Which of the following is a description of the orthogonal complement is the set of vectors that are orthogonal to Note: upds = $ of S: 5l = spans B. 51 cunds = A_ upds = -S...
5 answers
341 ltrRA3lo y' + p(x)y = rlx), 1 Rewoed 2
341 ltrRA3lo y' + p(x)y = rlx), 1 Rewoed 2...
5 answers
Application Dasha took out loan of SSOO in oeder to buy the #1 selling book in the world, Math, What is it Good For?" by Smart E_ Pants She plans to pay back this loanin 30 months. The loan will collect simple interest at 6.5% per year: How much will Dasha have t0 pay back at the end of this time? What is the accumulated interest? [3 marks]
Application Dasha took out loan of SSOO in oeder to buy the #1 selling book in the world, Math, What is it Good For?" by Smart E_ Pants She plans to pay back this loanin 30 months. The loan will collect simple interest at 6.5% per year: How much will Dasha have t0 pay back at the end of this ...
5 answers
Shown here is the phase diagram for compound X The triple point of X is -25_ 'C at 0.50 atm and the critical point is 22 %C and 21.3 atm. Describe the initial phase and the phase changes that will occur if we start at position A on the phase diagram and decrease the temperature t0 -28.2 %C while holding the pressure constant Explain your reasoning:Temperature
Shown here is the phase diagram for compound X The triple point of X is -25_ 'C at 0.50 atm and the critical point is 22 %C and 21.3 atm. Describe the initial phase and the phase changes that will occur if we start at position A on the phase diagram and decrease the temperature t0 -28.2 %C whil...
5 answers
Draw the expanded structure for the following molecules: a) 4-methyl heptane b) 2,3-dimethyl pentane c) 2-ethyl-3-hexened) a molecule with an aldehyde
Draw the expanded structure for the following molecules: a) 4-methyl heptane b) 2,3-dimethyl pentane c) 2-ethyl-3-hexene d) a molecule with an aldehyde...
5 answers
QUESTION 10Prob: 2 On planct X, spaccship, flying from city city B In straight Jine - with constant spccd V = 0.8660 mcasurcs Its time of flight to be ts Thc tlme mcasurcd for thc samc flight by stationary observer On the ground (on X) is [& 12.0ms: (You can assume the ground to be flat and neglect the physical dimensions of the spaceship ) [P] What is the distance (in Units of Jon) berwveen the cities and 35 measured by the person On the ground?
QUESTION 10 Prob: 2 On planct X, spaccship, flying from city city B In straight Jine - with constant spccd V = 0.8660 mcasurcs Its time of flight to be ts Thc tlme mcasurcd for thc samc flight by stationary observer On the ground (on X) is [& 12.0ms: (You can assume the ground to be flat and neg...
6 answers
What cell-cycle events will be affected in a cell that produces mutated (non-functional) cohesin protein?
What cell-cycle events will be affected in a cell that produces mutated (non-functional) cohesin protein?...
4 answers
The solubilityof Ag2CO3 ismeasured and found tobe 3.41×10-2 g/L. Use thisinformation to calculate a Ksp valuefor silver carbonate.Ksp =
The solubility of Ag2CO3 is measured and found to be 3.41×10-2 g/L. Use this information to calculate a Ksp value for silver carbonate. Ksp =...
5 answers
Given the unique equation of state below, calculate: (OP/8V)v and (8P/OT)v a kBT a is a constant P = V2
Given the unique equation of state below, calculate: (OP/8V)v and (8P/OT)v a kBT a is a constant P = V2...
5 answers
The sides of a square is 5 cm. long. A second square isinscribed by joining the midpoints of the sides of the secondsquare and so on. FInd the sum of the areas (cm^2) of the inscribedsquares thus formed.
The sides of a square is 5 cm. long. A second square is inscribed by joining the midpoints of the sides of the second square and so on. FInd the sum of the areas (cm^2) of the inscribed squares thus formed....
5 answers
[2 marks] Use the binomial series formula to find the coefficient of xn for n > 1, in the Maclaurin series of(1 +x)1s(16 11 16 (A) 5" n!(Sn -(~lY-14. 9 . 14 (Sn (4Y5.410 15 (B) (C) 5" n! 5n nl (-1y4 14 (Sn - (-15.10.15 (Sn-5) (16 11 . 16 (D) sn-1nl 5"-1 nl 5" nl (-lY-14_ 9 . 14 (Sn-42 (4-l6 . '11 *16 (Sn - 4) (G) (H) 5" nl 5n-1 nl(n-52(Sn - 4)
[2 marks] Use the binomial series formula to find the coefficient of xn for n > 1, in the Maclaurin series of (1 +x)1s (16 11 16 (A) 5" n! (Sn - (~lY-14. 9 . 14 (Sn (4Y5.410 15 (B) (C) 5" n! 5n nl (-1y4 14 (Sn - (-15.10.15 (Sn-5) (16 11 . 16 (D) sn-1nl 5"-1 nl 5" nl (-lY-14_ 9...

-- 0.075865--