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5 Consider il the type 32 H the what value? normally isehe ? exhibited? mode? distributed population and answer the following:...

Question

5 Consider il the type 32 H the what value? normally isehe ? exhibited? mode? distributed population and answer the following:

5 Consider il the type 32 H the what value? normally isehe ? exhibited? mode? distributed population and answer the following:



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Precisely what is meant by the statement that a population is normally distributed?Precisely what is meant by the statement that a population is normally distributed?

In question Number nine were given five values in the population. It does. Population is five. The values are to 13, 4, 10 and six and were asked to calculate a few things first, the sum of the square. Um, some of the squares of the differences mean so basically, we're gonna take the summation of all of the values minus the mean and square that do that for all of these values. So in order to do this, we need to know. I mean, eso to calculate the mean we're gonna add those phase together to buy by five. We get 35 divided by five and the mean is seven. So we do that. We'll play these in as to minus seven squared plus 13 minus seven square. Do this for all the values. Four minus seven squared plus 10 minus seven squared plus six months. Seven squared. This produces 25 plus 36 plus nine plus nine plus one, and we get 80. We also asked to calculate the variance and then the standard deviation. So the variance in this case is the value that we just found 80 divided by in because this is the population. We don't have to subtract by one. Uh, that's 80 divided about five and we get 16 standard deviation. In this case, standard deviation is the same thing as the square root of the variance. So we know the variances. 16 Take the square root of that. We get a standard deviation of four.

Hello students. And this question we have given this data and we are also given that more of this data is given to be 22. Okay, now we need to find the value of Y. Okay, so for uh this data for this is a group data. Okay, so for that first of all we need the formula of more. Okay, The formula of mode is given by L plus f minus F. One divided by two. F minus f one minus f. Two. Multiplied by edge. Okay, so for all these values, F F one, F two, H and L. For these values. Masterful. The leader model class. Okay. Model class is nothing but the class with the highest frequency. Okay, so if you look here we are given that X&Y are less than 10. Okay, so our model class will be 20-30. Okay, because 10 is the highest frequency. So model class, Model class is 20-30. Okay, so for that the value of l comes out over 20. Right? The value of f comes out to be 10. That is a frequency. Then everyone is the frequency of lower class which will become eight. Okay. And F two will be the frequency of upper class which will be X. Okay. And the edge is the interval intervals 10? Okay. So here we have all the values. So if I put it to the formula of mod mod is given already given 2 22 22 is it was true 20 plus 10 minus eight, divided by 20 minus eight minus X. And 2 10. Okay, so that's it. Now we can find um X easily. So from here to is equal to 20 divided by 12 -1. Okay, so from here X comes out of it too late now for finding a relation of X rayed by. We are given that there are 30 children's. Okay? So some of the frequency comes out of the 30, Right? So Some of the frequency that is five, let's eat plus 10 less X. Plus. Why? These all add up to 30? Okay, So X plus Y comes out to be seven. Now the value of X is already too, so the value of Y comes out to be five. Okay, that's it. Thank you.

Welcome back to another video here we have in the left column all our values that are kevin. And then what I do is I just do an x minus The average wishes five and then we take the absolute value of what that was. Next thing we have to do is rank these numbers from smallest to largest. So that means we're gonna start ourselves strong with number one And then we go to two and two. But this would be two and three so we average them out to be 2.5. I remember now if this is 23 so now we're at four and five So that makes it 4.5, Mhm. So 45, next one is six and then seven and eight. And then over here we're just gonna copy down these values whichever ones were negative so that's gonna be negative and that's gonna be negative 2.5, 4.5. And then all we have to do is just add up all these values. So we're just gonna add up even the negative ones. So eight plus 2.5 plus seven plus six plus .5 Plus 1 -2.5 -4.5. And I get 22 and actually I misread that we're not supposed to add these ones up. So pretty much just add up these ones. And instead of 22, what we get is 29. So then we have to look in the back of the book here uh to find out what are critical value is. So we have a sample size of 12345678, sample size of eight and a significance level of 10%. Getting us a critical value a critical value of 28. Um and 29 is greater than 28. Therefore we can reject the null hypothesis. Um Which was that The average is five in favor of the alternative. The average is greater than five


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