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Jp yled -L12 4Entlulyt x IO IlI credit you must give the details of your answers: 1.959 CiH#04 (20 points) Guaiacol (2-methoxyphenol, d 1.12 gmL) L.l mL is dissolve...

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Jp yled -L12 4Entlulyt x IO IlI credit you must give the details of your answers: 1.959 CiH#04 (20 points) Guaiacol (2-methoxyphenol, d 1.12 gmL) L.l mL is dissolved in 6 mL 95% ethanol in fume hood, and solution of 0.5 g of crushed NaOH pellets in 2 mL water is added. The mixture is heated under reflux for [0 min. Then_ mixture of 1.0 mL of (4)-3-chloro-[,2-propanediol, (d 4.32 gmL) in 1.0 mL 95% ethanol is added dropwise t0 the phenoxide anion and the reflux is continued for 1.72 g of Euaifene

Jp yled -L12 4Entlulyt x IO IlI credit you must give the details of your answers: 1.959 CiH#04 (20 points) Guaiacol (2-methoxyphenol, d 1.12 gmL) L.l mL is dissolved in 6 mL 95% ethanol in fume hood, and solution of 0.5 g of crushed NaOH pellets in 2 mL water is added. The mixture is heated under reflux for [0 min. Then_ mixture of 1.0 mL of (4)-3-chloro-[,2-propanediol, (d 4.32 gmL) in 1.0 mL 95% ethanol is added dropwise t0 the phenoxide anion and the reflux is continued for 1.72 g of Euaifenesin was obtained from this reaction. Calculate the percent yield of guaifenesin. 02 Naok Ca#l- DzCl CwHm4d Nac| hz ohi L.om 9428' ohi OH Oh HaOh OH OCH; OCH; "och' Gualacol Gualfenesin C1hedz CifiOt =iakglm- 124.145/m



Answers

The reaction between ethyl iodide and hydroxide ion in ethanol $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\right)$ solution, $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}(a l c)+\mathrm{OH}^{-}(a l c) \longrightarrow$ $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}(l)+\mathrm{I}^{-}(a l c),$ has an activation energy of 86.8 $\mathrm{kJ} / \mathrm{mol}$ and a frequency factor of $2.10 \times 10^{11} \mathrm{M}^{-1} \mathrm{s}^{-1}$ (a) Predict the rate constant for the reaction at $35^{\circ} \mathrm{C} .$ (b) A g $\mathrm{KOH}$ in ethanol to form 250.0 $\mathrm{mL}$ of solution. Similarly, 1.453 $\mathrm{g}$ of $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}$ is dissolved in ethanol to form 250.0 $\mathrm{mL}$ of solution. Equal volumes of the two solutions are mixed. Assuming the reaction is first order in each reac-solution of $\mathrm{KOH}$ in ethanol is made up by dissolving 0.335 g KOH in ethanol to form 250.0 $\mathrm{mL}$ of solution. Similarly, 1.453 $\mathrm{g}$ of $\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{I}$ is dissolved in ethanol to form 250.0 $\mathrm{mL}$ of solution. Equal volumes of the two solutions are mixed. Assuming the reaction is first order in each reactant, what is the initial rate at $35^{\circ} \mathrm{C} ?(\mathbf{c})$ Which reagent in the reaction is limiting, assuming the reaction proceeds to completion? Assuming the frequency factor and activation energy do not change as a function of temperature, calculate the rate constant for the reaction at $50^{\circ} \mathrm{C}$ .

Probleble 1 20 Party we know that Ellen K equals two minus E A V I R D plus LNA. Poor 1st or a reaction value of E A. Is given question That is 86 0.8. Kill a jewel Farmall. That is it close to 8.68 into 10 to the power four jewel Permal Temperature is given question that is 35. The results is we need to convert Calvin so we add to 73 that is equals two 300 eight Calvin value up is also given questions There it is 2.01 Into 10 to the power 11 mm universe. Second universe. Okay, so now we put the value in this equation so we can write us. Mhm. Alan Kay calls to minus E. Helio P. Is given. So simply put the values -8.68 into 10 to the power four jewel Farmall divided with 308 Calvin temperature. Multiply by value of them gas constant, that is 8.314 jule Farmall Gallery in plus. Alan a value of is 2.10 into 10. to the power 11 am in horse and second and worse. Now we can write as Allen G equals 2 -33 0.89 68 less 26.07 04. That is equals two minus 7.8 26 port. Now you take anti lock on both sides so we can write us cake was too 3.99 into 10. to the power minus pool I. M. Universe. First the Cannoneers. This answer for party. So this is a value of rate constant at a temperature 35° cells. Yes, no. In part B. We need to calculate rate. So first we need to convert grams of potassium had dogs hydroxide solution into maturity. Sure, We know that Mold 80 calls to wait upon molecular weight. Multiply by one upon volume of solution in leader. So simply put the values given So M equals two. Wait, a potassium hydroxide That is given in Europe in question. 0.33 five grand. Divided by molecular weight of potassium hydroxide. That is 56.1 ground caramel. Multiplied by one upon volume of solution. Leader That is 0.25 zero. Later solution after calculating we get 0.02 three 89 nine. That is approximately equals to 0.0 239 mm potassium hydroxide. No we need to convert Si two S 5 I into its already. So again we use this formula. So we directly put the value. You can wait one 45 three g Graham C2 H five I. So it I'll hide divided by molecular weight is 1 56 0.0 g. It highly light Permal multiply by golimumab solution That is 0.25.0 leaders are pre calculating we get zero point it's 03 seven 2 6. That is approximately calls to 0.0373 M tile highlight. Okay now if equal volumes of two solution are mixed. The initial concentration in the reaction mixture are 0.1194 and potassium hydroxide and 0.1863 M. Of the tile highlight, assuming the reaction First order it react in so we can write as 3 80 calls to Okay into concentration of with heil highlight Multiply by concentration of. Oh it now simply put the values value of concentration of talent light. We already calculated. That is Okay so on value of case also calculating part 1st. Now simply put the values value OK. three 99 into 10. to the power minus poor and universe as universe. Multiply by value, concentration of twilight. Already calculated. That is ah mhm zero point zero 1194 mm. Multiply by concentration of hydroxy. There it is zero point 018 63 AM. After calculating We get red equals two eight point 88 into 10 to the power minus eight and per second. This is an answer for part B. Now in part C since it tiled, highlight and hydroxy reacting one race you want more raise you and it's called volume 12 volumes of solutions are mixed mixed the reactant read the smaller concentration concentration, potassium hydroxide is the limiting reactant reactant. This is explanation for part C. Now in party partly we need to calculate rate constant K temperature PPD results. Yes, so temperature it's called Pretty re Celsius. We need to convert Calvin. So we had to 73 up reading we get 3 23 Calvin. Okay so now we use this formula 45 started. Okay simply for the values show at all activation energy that To his value of given question that is -8 68 into 10. To the power four jewels Permal. The higher the temperature 3 23 Calvin multiply where gas constant That is 8.3 one for jules. Part of the morning. Small salary plus Alan valuable is two point 10 into 10 to the Power 11. But um universe. But as universe. So Ellen K equals two minus 32 0.33 27 plus 26.70 port. After solving We get -6 25 23 Now we take anti log on both sides so we can write us K equals to 1.9, 3 into 10 to the Power -3. Um Universe for a sinner's. So this is a value of K at 50° Sense. Yes, this is our final answer.

In this problem, I can write the reaction at adducts changing into uh, C N. It is not possible. Is not possible in at I'll highlight since since blow job engine, since Claude abandon do not undergo at 10 1 or I sent to reactions. So according to the given option option is is correct answer option aid, correct answer in this problem.

Were given that the molecule of formula for the lyric acid is edge steaks D 46 The oxidation state for oxygen is negative. Toa wife or hydrogen, it is plus one. So let X be the oxidation state for delivery. It is six nice one plus eggs. Last six minus two equals zero. The oxidation for telly room will be plus six, but be the structure offs Olynyk acid on DDE The lyric I said So Oxygen double boon is it's o double bone excision. Which Rachel, you see, I don't wanna know which double one looks here. It's you e which which well, ej which ah nde ritual sulfuric on dhe selic acid Have tetra head restructure beer as the uric acid has octo hit with structure We're already provided with the density on volume off tell a room so mass will be equal to density multiplied with volume equals six 0.24 multiplied with zero point 1619 riches, 1.1 grams. So mourns well, e equals Maas. Divided by the molar mass equals 1.1 Divided by 1 27.6 grams per movie. The mole turned out to be zero point 00 seven 91 We're already provided with the world you moth florin as 2.34 later, along with the pressure on temperature so we can determine the moles off if too weak wills be we divided by Artie substituting in those value 1.6 2.34 do I did buy 0.8 to 1 on DDE 2 98 Kelvin temperature The number off Mortar No Toby 0.101 notes according to psychometric equation one mole off Hillary Um, the arts with three moves off after so zero point Tzeitel Tzeitel 791 morning off delirium reacts with zero point ville tow 373 molds off F, too. So if two but 0.10 more off F two hands deli room will be acting as limiting region on limiting react in story. The number off moves off e f C F six formed will be equal to mold off T E, which is equal to 0.0 791 more. It's a number off more Off T E, which six formed will be equal to 0.0 791 more From this, we can determine the polarity, which is equal to moles divided by volume off solution in leaders substituting in those value. 0.0 791 divided by 0.115 So more clarity turns out to be 0.0 6878 Moving on E. Which six? It's a weak acid. And how would the association Constand equals 7.68 Onda Que es tu equals 11.29 The morality we wallowed in determined Etch Half have a K A value. So for agent, we have Que es equals seven point toe. Multiply 10 days to plan negative for We know that Jeff is a strong acid. Hence the proton coming from H f only on dissociation off g E which six is suppressed by nature. So concentration off each tree. Oh, was it? The line will be equal to under. Okay, with each of you multiplied with polarity. Steal it, Jeff. It will be Underwood seven point to multiply 10 days to plant negative four multiplied with 0.6878 gives out 7.4 10 days to one negative three we know be. It will be negative. Log off the concentration 7.4 10 days to one negative three. It will be equal to 2.15 to 6.

Oh The question is which of the following combination of new cases can be used for the preparation of the 65 ch works Siesta. Okay so we are going to discuss which of the convention? We can get this kind of if you take C six H five C two is reacting with us CS three MG br then what will happen Then we will get 3° al Qaeda. And it's really important From C65 cm watch. Yes. Okay, in the second. Also we can get the second is the same as the first. In the third we cannot get because in the third we will get not then and so on is reacting that any. Then we will get to see 65 years to minus is reacting with us yesterday here are just a minute and then we will get it helps the issue. Yes. Yes. In the 4th reaction C65 C they will move. Yes. He is reacting with a light That we're gonna give C6 that's five ft. Which see if a pack of something you see 1st 2nd and corporations can give you're fired


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