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CircuitsTwo resistances Rjand Rzare connected in series A potential difference V is applied to the free end of R1 relative to the free end of Rz- What is the potent...

Question

CircuitsTwo resistances Rjand Rzare connected in series A potential difference V is applied to the free end of R1 relative to the free end of Rz- What is the potential in the steady state at the point where R1 and Rz arejoined together?VRu/(Ru + Rz) VRz/Ri VR Rz/(Rz + Rz)VRz/(R1 + Rz)

Circuits Two resistances Rjand Rzare connected in series A potential difference V is applied to the free end of R1 relative to the free end of Rz- What is the potential in the steady state at the point where R1 and Rz arejoined together? VRu/(Ru + Rz) VRz/Ri VR Rz/(Rz + Rz) VRz/(R1 + Rz)



Answers

In the circuit shown in $\textbf{Fig. E26.28}$, find (a) the current in each branch and (b) the potential difference $V{_a}{_b}$ of point $a$ relative to point $b$.

This is the given circuit diagram in the kitchen where two capacitors are connected in series and we need to find the vault ease across these capacitors since these capacitors are connected in series. So in serious combination, we know that the charge remains the same Charles remains the same on both the capacities. Charge remains the same and charges given by Q equal to c. V. If Q is constant then I can right away is going to be proportional one by C. That means we won't divide. We too will be equal to C to D white C one. Put the values four and 10. We get to buy five. Let's suppose this is a question first and the Walters drop across the capacities and the some of the Walters will be equal to 14. So we want plus put the value of V two from equation first, that is five. We won by two. That is equal to 14. From here we can write we won will be equal to four world And we too will be equal to 10 world. So in the given options option they will be the right option

In this question we have sex resistors connected in this. I know uh in the circuit. So we want to find a potential drop across the resistor and the current flow. Uh huh. The current that flows through initial resistance. Okay so to do part A is to find a potential drop 1st. We need to find Yeah. Equal and resistance. Okay so we have I want an Ar 20 series actually our foreign parallel 56 in parallel. And then so the first thing we can do is to find our tree for. Yeah. So this is one of the five plus 1/5. Right, Take the recipe book of the sun And you get 2.5 homes. And then our front six is equal to 1/2 plus 1/2. And take the recipe book of the Sun. We get one. Okay So the equivalent resistance in the second is 12. That's actually for last 56 Okay so we have five plus 10 plus 2.5 Plus one. Okay this is 18.5 homes. So the current in the circuit is uh we divide by are equivalent and you get 1.8 mps. Okay so with this current we can calculate the potential drop in each our existence. Okay so that'll be one is i. r. one. And so we put 1.08 multiplied by five. You get 5.41 Woods. And then they ought to be too i. R. two is equal to uh 1.08 times 10. 10.8. What's Then the v. 3? It goes to the altar before is equal to i. r. And this is 2.7 zero words. Then they had to be five. Is equal to without a v. six. Okay. Is equal to i. r. This is equal to 1.08. What's Okay? So here are the answers for party. The next uh we want to find a current through each resistor. Okay? So since we have found uh the total current in the circuit so and I won To be equal to I two. Okay, it's with 1.08 mps. The tree is to go to iphone because they have the same resistance. Similarly, I five and I six. Okay, They are going to be half or 1.08. NPR. So is your point 541? Okay. So these are the answers for part B. And that's all for this question.

Hi the given problem, there are various resistors mind in mixed grouping. First of all here, this is our one which is in series with our tool than two resistors are in parallel with each other and this parallel combination is in series with R. One and R. Two. The upper one, R. Three, the lower one R. Four and then one more parallel combination of two resistors. And this parallel accommodation also is in series with the other one apartments are five, lower one R six, and finally a source of faulty mm circuit is closed. This old age applied is having a value 20.0 volts. The values of resistance is our win is equal to 5.0 own R two is then wind needle arm, R. B. S. Again 5.0 home R. Four. Like 100 home R five 2.0 on and finally our six. This is also to find zero's your own. Now in the first part of the problem, after finding the equivalent resistance of this combination, we have to find potential drops across each and every resistance. So first of all, there are two parallel combination. First of all, these are three with our for and R five R six net resistance is are assumed to be if we consider terminal terminals here, this is A B. See and the mid one He and finally this is E. So the resistance of this parallel combination will be named as our city. And here this last one will be named as R E. No as our three and our four are in parallel and having identical resistor each having a value of five. Warm. Therefore their net combination parral combination. RCD will be given by 5.0 by two. Oh, since this is 2.5 little. Um similarly as our five and our six are in parallel and they are also having identical resistor each having same value of 2100 home. So they're parallel accommodation will come out to be R. E. He's going to 2.0 home divided by two. Which comes out to be 1.0 Finally yes R. One R. Two, R. C. D. And R. D. All four are in series. So finally this are one part two. Our city and R. B. All are in series. Therefore equally violent resistance of this. This combination will be our one plus R. Two plus our city plus R. E. Means lacking in unknown values. Here this is 5.0 plus 10.0. Yes 2.5 plus 1.0 boom. And here it comes south to be 18.5 mm equivalent resistance. So using arms law, current passing through this city's combination be given by I is equal to be by equally violent resistance means this is 20.0 hold divided by 18.5 home, which comes out to be 1.8 NPR The current passing through this cities run so are using on slow again. The potential drop taking place across our one. This is we even across our two cause this is V two and as R three and R four are in parallel and in parallel potentially be insane. Oh that would be the three and finally that would be five. So to find all these values or even this will be I into our one. Yes. This is 1.8 multiplied by five which comes out to be 5.4 war. Just answer then what we do this is I into our two means 1.8 into 10 and it comes out to be 10.8 world second answer then. Or we treat and before us these are in parallel. Both of them will be equal and will be given by I into our cd. The equivalent resistance of barrel accommodation. So this is 1.0 yet again and our city was 2.5 oh here it comes out to be 2.7 gold or metreon before and finally we five will be equal to visits again as they are in parallel and that will be given by the product of current. With the equivalent resistance of this parallel combination are the E Yes, this is 1.8 multiplied by 1.0 So this is 1.8 old. All these are the answers for the first part of this problem, potential drop across on the there's the stars. No, in the second part of the problem we have to find current passing through all the resistors as current remains the same in series. So as urban and art are in cities, so Ivan will be equal to itunes and that will be equal to total circuit current means 1.8 I'm here. This is restaurants, then I three and I four as the two resistors are identical, the net current entering into them. If you look into the circuit as the two resistors are identical, the current entering into them will be divided into two equal parts and so we can say I three will be equal to I four and that will be equal to for 1.8 is entering into this parallel combination. So each one will be 0.54 and here similarly in the next parallel combination. Again, there are two identical resistors. In parallel, the current will divide again into two equal parts 1.8 divided by two NPR means this is also 0.5, or these are the answers for the second part. The problem. Thank you.

Of same E M F E. And different internal resistance. R one and R two are connected in series So the net E M F Net E M F E zero. We can write AS E plus E. That is going to be too easy. And equivalent resistance are equivalent will be equal to the three resistors. R one R two and R in syria's combination so are equivalent will be equal to R one plus R two plus are so the current I will be equal to E zero divide are equal and we can write it as two. E divide our one plus R two plus our let's suppose this is equation one. Now in the cushion it is given that but our potential difference Across cell of internal resistance R 20 that means we is equal to E minus I R two. That is given as zero. The potential difference across the Terminal of the sale having resistance R two is given zero institution. And for this condition we need to find the value of our so put the value of I from the equation first we get e minus the E is denoted as here, wow E minus I R I can I can be written as two E. Or to divide R one plus R two plus. Our that is equal to zero. So from here if you solve this we get R one Plus R two -2. R two Plus R is equal to zero. So this implies R is equal to R two Our one option. B is the correct answer


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