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Suppun (Inat Ju vi M (uiL JIIUMMLS DU% Ulntl-Utucr puulaa dkcrieatines L"t-neunu Quui ~Ino Shun' thneul) Ur?1 Ur) 06'0r' Jwwlne Olr) nudl M'...

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Suppun (Inat Ju vi M (uiL JIIUMMLS DU% Ulntl-Utucr puulaa dkcrieatines L"t-neunu Quui ~Ino Shun' thneul) Ur?1 Ur) 06'0r' Jwwlne Olr) nudl M' ) arv func%t kMla which Juu -lwoukl dAetmin .Stantiwv:Cni notsuudTnutth Houn i We F of #alta -(tu "quutaus UId sok to fiuduhd(0t) uc (ha { Squtc esonu In (") to hndWu

Suppun (Inat Ju vi M (uiL JIIUMMLS DU% Ulntl-Utucr puulaa dkcrieatines L"t-neunu Quui ~Ino Shun' thne ul) Ur? 1 Ur) 06' 0r' Jw wlne Olr) nudl M' ) arv func%t kMla which Juu -lwoukl dAetmin . Stantiwv: Cni nots uud Tnutth Houn i We F of #alta - (tu "quutaus UId sok to fiud uhd (0t) uc (ha { Squtc esonu In (") to hnd Wu



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licre the ycllow and orangc precipirares arc, rcspectively (a) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{-}$ (b) $\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}, \mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}$ (c) $\mathrm{Na}_{2} \mathrm{CrO}_{4}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$ (d) $\mathrm{Na}_{2} \mathrm{Cr}_{2} \mathrm{O}_{2}, \mathrm{~K}_{2} \mathrm{CrO}_{4}$

Okay, so now we have this vector in the complex space and we need to first found the country kate, the real part, imaginary part and then the norm of this vector. So they congregate. We only need to change the sign of those numbers that for the imaginary part of the factory, In this case we have six that remained the same one. And here we change it to -4. I. And the last component will be six plus two. I. Okay, so that's the country gate. Then the real part will be the terms that uh doesn't um have the imaginary number the eye. So those that are just the numbers in this case six, 16 And the imaginary parts, those that are multiplied by I. So in this case is 0 -4 and two. The last thing that we need to do is calculate the norm. So in this case is equal to the square root of the dot product of you with its congregate. Okay, these results into the square roots of through six plus one. Last 16 han Plus 36 plus four. This result into the square root of 93.


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