Okay, in this problem, we have an aquarium, and it's with water. And it has, ah, last sides, and their index of refraction is 1.52 So let's write that first given down that and G is equal to 1.52 Let's go ahead and look at the figure while we're at it, and I'll pause the video while I pull it up. Okay, got it. So we have, um, you have glass, and then we have water. We have light entering on. This angle is 43.5 degrees. Let's double check. Yeah, great. And we want to get the angle of the ray when it enters the glass and then the water. So first ones right down the index of reflect fraction of water. So that's N W. And that value is 1.33 So, um, let's find what the angle is when it goes into the glass. So here is the glass, and here's the water. So for that, we want to use Snell's law so we could say and she sign. Beta G is equal to an air. Ah, sign of data in the air. And then this is of course one. So if we want to solve for theta G, we want to divide both sides by N G. And then take the arc sine of both sides. So with that, we can save data G is equal to the ark or the inverse sign of an A, which is one over N g multiplied by the sine of the angle and the air. And that data air is 43.5. Smoke. Go ahead and write that out expressively. Great. So now we have a formula and we have everything we're looking for in the formula. So I just need to plug it into a calculator and so on the do art sign of 1/1 0.52 times of sign of 43.5 degrees and, um, convert that to three is so that is 26.9 degrees, and then we also want the angle in water. So we just found this angle and that angle is right here, a state, a g. And now we want what's going on in water. So, um, we can use the same formula except for we want to use n g sign data G is equal. Teoh and water sign beta off water and we can do the same thing and just solved for science data Water. Um, so it's the same math. So you with different variable names. So you end up with data. W is equal to the inverse sign of N G. Divided by and w times the sign of the, uh, Tom G great. And now I can plug this into a calculator. So one by the by of 1.33 and then the sign of 26.9 degrees, understand a double chocolate and accept a fraction of water. I think I remember it was 1.33 but I want to double check. Yeah, it's 1.33 Great. So for this angle, I get 19.9 degrees. All right, what's I realized? I made a mistake in the calculation, so I needed to be using the index of refraction of glass and water on. I think I was using air and water. So let me revise that copulation. I'm getting the arc sine of 1.52 provided by one point three times with sign of ankle and the glass, which is 26.9. Decree is all right, so with that, I get 31.1 degrees. So all raised this and write that down. Thank you. All right. Okay. And then we want to know what would the angle b if it entered the water directly. So to do that, what we would do is, um, an air sign. Sita in the air is equal to and water sign data in the water. However, we know that on a sign, data A is equal to n g signed David G. And so then we know that that would be the same thing of solving the above equation. And so we would get the same answer. So without doing a calculation, we know that the answer would be the same.