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The Na emission line from 4Sv 34Py occurs at a wavelength of 11,383 A Calculate the ratio of sodium atoms in the 4s excited states to the number in the 3p excited s...

Question

The Na emission line from 4Sv 34Py occurs at a wavelength of 11,383 A Calculate the ratio of sodium atoms in the 4s excited states to the number in the 3p excited states in an ICP source at 6000 K 0.12 B. 0.04 C. 0.36 D. 0.24 E. 0.01

The Na emission line from 4Sv 34Py occurs at a wavelength of 11,383 A Calculate the ratio of sodium atoms in the 4s excited states to the number in the 3p excited states in an ICP source at 6000 K 0.12 B. 0.04 C. 0.36 D. 0.24 E. 0.01



Answers

The wavelength of light from the spectral emission line of sodium is $589 \mathrm{~nm}$. Find the kinetic energy at which (a) an electron, and (b) a neutron, would have the same de Broglie wavelength.

Given in the question. A bright so liam. Mission line whose prevalent is why 87.5618 nanometer. We have to find out the items. Energy level difference. We will use you. The formula related the violent and the energy level difference which is at sea by linda Subsequuting the value as edges. The plant constant equal to 6.626. Independent Power -34 June/s. C. Is the speed of light equals three into 10 power eight m per second and lambda as given number 5 87.5618 nanometer equals 25 87.561 eight. include under the power -9 m substituting all these values, we will have the energy differences 0.03383 into 10. to the power -17. We know that one electron world is equals to 1.6 and under the power -19 jewels. Using this conversion factor, The Dell E. Comes out to be 2.1143 electron holes. Nearly it would be 2.11 Electron volts. This is our final answer.

As we all know that daily is equal to at sea by Linda. Also, we know that the transition between five D and three p state can be given by, so just look at it carefully daily equal to e five d e five d minus. E three p So from both express and I can write the value edge at sea by Linda equal to e five d minus E three p Simplifying it further I can write the value of e five The Equal to at sea by Linda Plus three p e t e p. Now I will just put the value in this ex prison so I can id the Expressen edge 1240 e p n m Bye food 99 and plus 2.1 year or four e b So on solving I get four points 59 e p. As the energy of the fifth, the estate

The bomber. Siri's looks that the transitions in a hydrogen atom that are in the visible light range if we have visible light given off with the wavelength of 4 10 nanometers weaken. See, looking at the electromagnetic spectrum, this corresponds to the color violet, and we can identify which transition it represents on the diagram of the bomber. Siri's by using the equation, one over Lambda equals R times one over and F squared minus one over and I squared. Where lambda is the way of life in meters are is a constant called the Rydberg Constant in a sequel to 1.974 times. Tend to the seven meters to the minus one, and F is our final energy state, and an eye is the initial. So these two will be whole numbers, representing where the electron is transitioning from. We change our wavelength from nanometers two meters. This is equivalent to 4.10 times 10 to the minus seven meters equals the constant value. The final state in the bomber Siri's for all transitions is an equals two. This is 1/2 squared Linus, one over an I squared. So we're just solving for the initial transition state. So dividing one divided by 4 10 times 10 to the minus seven and then dividing, then answer by one times 1.974 times 10 to the seven is this 2.2 to 25 This 1/4, minus one over end square or minus one over end squared equals negative 0.277 and solving for n squared and squared equals 36. So an equal six. So our initial energy levels unequal six are final. His n equals two, and the color of the wave length corresponds to violet.

Hello students. So in this question the wavelength of the characteristic exit of careful line is 0.32 angry stone in high doesn't like element. Okay the wavelength of the capital line by the same element will be We have to data mine So from the mostly slow we can right here that one by lambda alpha is equals to chair minus be holy spirit molecular by art. And the energy that is one by end finally square minus one by an initial square. Okay so one by this is supposed lambda. Okay simply so one by lambda alpha that is fully careful line we can write that there minus B market square marker B R and one by one one square minus one by two is square. And for the capital line we can write that one by lambda vita will be coached to germaneness B and this holy square and are and this is one by one square minus one by three square. Okay now we can take the ratio of these two so we will obtain that one by lambda alpha. Where we won by lambda beta is equal to the one minus one by four divided by one minus one by nine. So we can write that lambda vita. They were the lambda alpha. Lambda alpha is given Okay and which is equal to 0.32 and this is equals two. After solving it we will obtain that this is 27 Developing 32. So Linda Vita from here after solving is 0.27 angry storm. Okay so from the given options option B is the correct answer for this problem. Okay, thank you.


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