Okay, we're giving a position effect er and the first thing we're going to do is find velocity. So to do that, we're going to take a derivative of all of our components. So think of that I component as a 16 minus t squared. All raised to the one half power be a little bit easier to do chain rule like that. So our Vot Will equal a 1/2 16 minus t square. Then we go down a power to a negative one half and then we multiply by the drift of the inside. That negative to T. That's all of our I component. RJ component will be a two T and RK component will be a one. So I'm going to clean that up the two's cancel out. So I have a negative T in the numerator and then I put that 16 minus t squared in the bottom so I can write it as a positive exponents of a hat and then I just continued to write my other components. Okay, the next thing we're going to do is we are going to find acceleration. So we are going to take the derivative of velocity to do that. Now I'm going to go over here to the side and I am going to write my negative T. And then I'm going to read that 16 minus t square to the negative one half. So I can use product rule. So with product, will you do to keep drip plus trip? Keep so if you write your derivatives right underneath each other, you can kind of do a criss cross um since we've already taken the derivative of that um 16 minus T square. Now we're just going down to a negative three halves power. So you can see again your two's cancel out. You have a negatives cancel out actually we have three negatives so we still have a negative, make sure to get that there. Yes. Let's just check. 1, 2, three. So we do still have a negative on that one and then we have a one over the t minus t squared all to the half power. So that whole piece there is my eye component. You could do common denominators if you would like. Um you can multiply both top and bottom by a half power. And so I'm just showing you how to do that. If that if you do do that, you're going to have two of the t squares minus the 16 and then you'll be over that common denominator of 16 minus t squared all to the three house power. So R. I. P. S was the more complex. R J P s just became that nice to J. And then RK piece um did you know, taking the derivative of one? It went away. Okay, so the last thing to do is for us to find our speed. So for speed, that is the magnitude of velocity. So if we go back up to our velocity vector, we can consider um that we are going to have to square each of our parts, some of them together and take the square root. So we'll have a t squared over a 16 minus t. Square. Now will be to the first power because we squared it plus a four t squared and then plus form.