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KameDalClassfront again and observe the chanee reaches constant tempertune Kraph value and then wait windor additional 20-30 Hhn ehermomcter Window (You can click s...

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KameDalClassfront again and observe the chanee reaches constant tempertune Kraph value and then wait windor additional 20-30 Hhn ehermomcter Window (You can click scconds Cllck _ Stop on the clock on tho wall labeled Accclernte Jceclcrtethetm the laboratory ) data link will appear the Lab Book cllck ' Iink 5 Icon and record the Data Table below thee remperature before adding the _ and thc highest temperaturc after addlng the = (Remember that the water wIll begin doin afer reaching the equil

Kame Dal Class front again and observe the chanee reaches constant tempertune Kraph value and then wait windor additional 20-30 Hhn ehermomcter Window (You can click scconds Cllck _ Stop on the clock on tho wall labeled Accclernte Jceclcrtethetm the laboratory ) data link will appear the Lab Book cllck ' Iink 5 Icon and record the Data Table below thee remperature before adding the _ and thc highest temperaturc after addlng the = (Remember that the water wIll begin doin afer reaching the equilibrium temperature) Repeat the experiment with the ollonIne samples: Stalnless Steel, Copper, Sllver; Gold: Click the red disposal bucket= clear the lab Click on the Stockroom enter. Double-click the Dewar Hllormcter move it to the Stockroom counter; Click thc metal sample cabinet Open the bottom dNiret (the samples alphabetically arranged) by clicking = It, select the Steel by double-clicking andzoom out Double-click on the Pctu dish with the selected sample t0 move it to the Stockroom comnir Return laboratory: Hoit the Petri dish with the sample the spotlight next to the balance: Click on the Balarice area coom ano makcsure the balance has been tared, Move the metal sample the balance pan nd record the mass the Data Table: Return laboratory: Double click the calorimeter Moua into position in the laboratory Click the oven open the door: Move the meral sample from the balance pan the oven and click to close the oven door: Click above rens placc severltimcs the front of thc oven change the temperature 200*C. Fill the 100 graduated cylinder with water by holding it under the tap until Eecurms thecounter and then poM into the calorimeter: Turn on the stirrer: " on thethermometer.Click on the Graph 'and_ Save buttons; Movc your metal sample from the aven to the calorimeter. Follow the procedures used with A obtain the equilibrium temperature. Recordall ofyour observations the Data Table: Stainless Steel Mass of metal (g) 6, 9boq Volume of water (mL) 2 5 Mass of water (g) 163.1/ Inldal temperature of water (FC) 20 Initial temperature ofmetal (*C) 19. 07 Max temperature of water metal (C) 27.27 Specific Heat (Vg"C) 29,12 22.820f 25 [63.71 20 29.12 27.27 19.07



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An ice calorimeter, shown below, can be used to measure the amount of heat released or absorbed by a reaction that is carried out at a constant temperature of $0 .{ }^{\circ} \mathrm{C}$. If heat is transferred from the system to the bath, some of the ice melts. A given mass of liquid water has a smaller volume than the same mass of ice, so the total volume of the ice and water mixture decreases. Measuring the volume decrease using the scale at the left indicates the amount of heat released by the reacting system. As long as some ice remains in the bath, the temperature remains at $0 .{ }^{\circ} \mathrm{C}$. In Example $15-2$ we saw that the reaction $\mathrm{CuSO}_{4}(\mathrm{aq})+2 \mathrm{NaOH}(\mathrm{aq}) \longrightarrow \mathrm{Cu}(\mathrm{OH})_{2}(\mathrm{~s})+\mathrm{Na}_{2} \mathrm{SO}_{4}(\mathrm{aq})$ releases $846 \mathrm{~J}$ of heat at constant temperature and pressure when $50.0 \mathrm{~mL}$ of $0.400 \mathrm{M} \mathrm{CuSO}_{4}$ solution and $50.0 \mathrm{~mL}$ of $0.600 \mathrm{M} \mathrm{NaOH}$ solution are allowed to react. (Because no gases are involved in the reaction, the volume change of the reaction mixture is negligible.) Calculate the change in volume of the ice and water mixture that would be observed if we carried out the same experiment in an ice calorimeter. The density of $\mathrm{H}_{2} \mathrm{O}(\ell)$ at $0 .{ }^{\circ} \mathrm{C}$ is $0.99987$ $\mathrm{g} / \mathrm{mL}$ and that of ice is $0.917 \mathrm{~g} / \mathrm{mL} .$ The heat of fusion of ice at $0^{\circ} \mathrm{C}$ is $334 \mathrm{~J} / \mathrm{g}$.

Hi friends has given the driver in the first part the fundamental frequency. Mm. For equality of spending babes on the road. Okay. Fixed at World Bank is be upon to it. And the speed is given by by your own rules. So I have 100 nights one upon to a young small, less upon 10 street. Yeah, yeah, yeah. The length of the road can be written. It's we burn upon to Afghan. Why? And you know upon density l'Union substitute the value fundamental frequency is 95.5 Lourdes. Okay, um, tomorrow lots of l a medium is 6.9. Turn to the poverty and then she is 2700. So it's lands to be 27000.265 m. Mm. No. Be part mhm. Yeah. Fuck. Titanium. Rod. Mm hmm. To have fun to and to 95.5 10 to leave power tree for titanium. Not young. Small assist. 1.2 in 2, 10 to the power 11. And density is 40. 500. So it is to be one. Do not move 5 m. They're so thanks for watching

Hi. Agreement. This is the problem based on changing and profit of the object here it is given. Yeah, the Androphy increasing the first object. Their temperature increase from T one to Kato is given by that change. Any and traffic. Yeah, mhm in the first object. If temperature increases from T one to t um, when she even blown up to your point even. Mm hmm. Yeah. Change in. Yeah. And traffic. Mhm in second object and temperature dick rages. Problem? Yeah. T two leaders. Okay, Yeah. The as two will be m two c two lawn of leaders upon Tito for the so total and profit change. Yeah. Mhm, right? Yeah. Did as the school today to Jasmine last day to escape. Yeah. Mm. Once even you're not t upon demon bless. And to see to law no teachers upon Cato. Yeah. Yeah. If the she'd given by the second object. What? Mhm. Mhm. Oh, yeah. Is equal to mhm. Mhm. He'd received by the first object. Yeah. Mhm, Yeah, Yeah. According to contribution of energy. Uh huh. That is Cuban escort to minus Cuba and once even Do you mind history, but uh huh. Yeah, yeah, yeah mhm. That is a month even t minus Stephen s curto. I'm to Sibu. Mhm. Keep in mind this fetus. Mm hmm. Wait. Now be part. We have a Muncie with T minus 2 to 1. His car to M to Cito, to my spirits. So two to minus students. We would get a months even. Do u minus, Stephen. A bump. And to Zito if you removed. Therefore, total efficiency change data, as is for two, um, months even learn of to your point t one plus mm. To see, to loan off. Do you disappoint you? Mm. Yes. Mhm. Um, months even loan off upon tiaras. Stephen. Sorry. Yeah. Plus m two. C two. Yeah. No, no. Two to minus and once even. Do you mind to Stephen? Yeah. Oh, come on. Have a prosciutto upon Taito. Yeah. Yeah. So data as its cultural I'm months even Lana, do you upon to even unless I am to see too No, no one minus I am months even. Mm. And to see Duke, he upon two. To minus t When? Upon to for maximum. Uh huh. For maximum deputized. Uh huh. D upon duty of data as must be deal differentiating the ever be questioned with respect to t you will get. And when she even upon keep lists m two c two into I am man. She even divided by MPC two button. Okay. Minus one upon people. Mhm. Mm. Divided by one minus and once even. Yeah into tea party. Must be zero. So on solving it you will get these curtains Table. What? Yeah, seafood. If t is less than two years, then it is possible to approach each other. Yeah, in that. In this process. Yeah, that total and trophy of the system. Yeah, You Yeah, right. But keep on encouraging. Yeah, the final state of the system. Mhm. Yeah, baby. Mm. Bench, for which no further and profit change is possible. Yeah, What a bitch. No further. And trophy change. Yeah, each possible. Yeah. Yeah. Ben. Teacher, two teachers. No. Yeah. Changing and trophies Pacifica, but Mm hmm. Yeah. Later. Mhm. And yes. Act. Please call torpedoes. Data as its maximum. Mm. That's it. Thanks for watching it.

This problem have a lot of things to do on the calculator. And first of all, I'm going to put my data into a table rather than into coordinate system. I'm putting this data enlist one. And this is time 05 10 15 2025 you should do the same. And then in list, too. I put in the temperatures, the actual temperatures, and then we will transform them in a second. And this is the 78 the 66 the 57.5. Wow, 51.2, 46.3 and 42.5. And in part, A. They want us to transform those and have this be 21 degrees less than what this is to take away the the room temperature. So what? The differences between the room temperature and so you can put that into your list three and have it do the calculation of list to minus 21 then fill in this list and I'll put in the first view. I'm not going to put them all in, and then they ask you to grab some things and you can go ahead and grab that But they tell you that the model is if we look at the linear regression, it's actually they do an exponential regression. They don't have You do it. But they tell you that the equation comes out to be this for part B. You're supposed to grab this data and see that it has an ascent tote and grab this data and see that it has an asthma tojust shifted. So I'm not going to do any of the graphic. I'm gonna leave that for you. I'll look at the algebra and then they ask you to solve for T. And so when you add 21 you'll end up having this and you definitely That's a four. You definitely do not want to add these This multiplication override. You can even put the 21 at the end too. So you're not tempted. Alright, now, part C. We're doing something and doing a transformation. They ask you to take the log of the natural log of the T minus 21 so you would want to take the natural log of your list three. And when you take the natural log of the list three, I'll put the first few elements down, but let me get back to my spreadsheet on my calculator. So up here and list four you should be putting in for list. Four. You should be taking the natural log of list three of this of that list, and so we have to get second in that. And when we do that first element and I'm only going to break down the first couple four point oh four, this comes three point 8067 and so on. Now they ask you to find a linear relationship, and you'll want to do Lynn Wreg between list one this value and list four. And when you do the linear regression between those, you're finding a value for this equation. And when you hit linear regression between these two, you're getting an A and A B, and you should get an A value of negative 20.388 And for the B value, I believe it's about four point oh one, and then they ask you to solve for T. Well, we know that we're in base E, so we would have t minus 21 I'm not going to do tons of simplifying here we equal e to the power of negative 210.388 x plus 4.1 and there's some and this is all in the exponent position. And then I can solve 40 by adding 21 to both sides. So I'm just going to change this and go plus 21. And again, there's some exponents, uh, theorems that I can use in order to break this up and have a coefficient out here in front. And so there are lots of things I can do to manipulate. I'm not going to go through that. Then, on Part D, they asked us to do one more transformation. Let me go back up here and they want to look at what happens if we get irrational equation. So we need to go into list five and we need to take list five to be the reciprocal of this of List. Five should be one divided by list three. And when you take one divided by one divided by list. Three. That first element is 0.151754 The next one is 10.222 and again, I'm not going to write them all down. And now you want to impart d All right, that right below here you want to find a linear regression between list one and list five? Yeah, And when you do, you're going to find a relationship between this and you'll get an A and A B. And when you do that, you should get 0.1157 x and then plus 0.166 Now, how can I solve for T? Well, I can reciprocate both sides, so basically take each side to the negative one power. And when I do that, I get t minus 21 equals and this becomes one over 10.1157 x plus 0.166 and then I can finish up by adding 21 to both sides. So I'm just going to scratch this off here and add on 21 and then you can grab those models to see which one is the most appropriate

So this question is basically about using a game console to here a pastry that is on a plate So we have pastry just a plate way. Have the respective initial temperatures temperature four degrees. The capacity for the pastry itself. This 3 kg juice k g particular Celsius. That's what deplete. So 0.9 juice and the mess mess off pastry is 3.16 Christmas will deplete 2.24 So we're given that the game console game console itself starts off here temperature at 45 degrees Celsius and he he capacity is and on the this is what we want to find. Also given its mess she 2.2 point 1 kg. So how do we find the high capacity? Well, we know the final temperature off the entire system that is including the pastry and a plate as well as the game console. The final temperature TM is 38.3 degrees Celsius. So assuming that we do not lose any of the energy to the surroundings, all right. He was just transferred over from the console toe the pastry and plate. You can first find how much energy is being transferred eso energy transfer will be a multi of energy required to heat up the plate pastry to 38.3 degrees SMC Delta team Delta is the same for both. It is just 3.3 minus four, just 34.3 the masses and he capacity will be the respective values. This is for the history, then for the plates itself is I'm still going too far. So this is the total amount of energy this transfer and this must be also the amount of energy that was lost from our console. So we quit this value to emcee Delta T for the console as well. So we're consulting message 2.1 See, is an unknown Delta T is from 45 degrees finest a tape. So, doing the calculations, we should get about 1.17 kill chose grand degree Celsius. So this is the heat capacity off the council


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