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3-menthene an essentia oil found herbs. 3-menthene reacts with E-Nu; where part and Nu the nucleophilic Panthe electrophilicE-NuUse curved arows show how E-Nu react...

Question

3-menthene an essentia oil found herbs. 3-menthene reacts with E-Nu; where part and Nu the nucleophilic Panthe electrophilicE-NuUse curved arows show how E-Nu reacts wilh 3-menthene torm inlermediale and Product B. Draw the structures and Circle the electrophilic part ol HCI, Br-Br, and H,SOz 3-menlhene undergoes Ihe reaciions shown; Draw the structure of C , Identify Reagents and EInuninol

3-menthene an essentia oil found herbs. 3-menthene reacts with E-Nu; where part and Nu the nucleophilic Pan the electrophilic E-Nu Use curved arows show how E-Nu reacts wilh 3-menthene torm inlermediale and Product B. Draw the structures and Circle the electrophilic part ol HCI, Br-Br, and H,SOz 3-menlhene undergoes Ihe reaciions shown; Draw the structure of C , Identify Reagents and E Inuninol



Answers

(a) Benzene reacts with tert-butyl cation $\left[\left(\mathrm{CH}_{3}\right)_{3} \mathrm{C}^{+}\right]$ by a two-step electrophilic aromatic substitution mechanism to yield tertbutylbenzene $\left[\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{C}\left(\mathrm{CH}_{3}\right)_{3}\right] .$ Write a chemical equation for each step in the mechanism and use curved arrows to track electron flow. (b) Electrophilic addition of hydrogen chloride to styrene gives the product shown. Write the mechanism for this reaction including curved arrows.

Okay. This problem is asking us to draw the structures of Company A and Company B and describe how we got to those particular products with the conditions that there. And they were also asked to describe the mechanism of a transforming into see. Okay, so it's going to start off with the mechanism of this compounded into Compound A and the structure that correspondence to company. Okay, so first up, we see that we have a l V a l B. It's a very strong base. It's also constant consider to be non nuclear folk, so we know it's only gonna be participating as a base. Katie HF that simply just a solvent and negative 78 degrees Celsius. That is obviously very cold. Okay, So if I am in cold conditions with a very strong base such as L V. A. I know that I'm going to take off first of all, in a state of proton, but also the acidic proton that is going to lead to the to a relatively unstable in elite ion. Okay, What I mean by that is that I have two options here. Technically, I've three, but more in reality, more like to. Okay, so I have three carbons. 123 Okay, as far as Esther's go, those air less acidic than Keystone. So we're gonna get rid of that carbon for now. We're not gonna focus on that one. So the question is which proton to take off. Take off that proton or a take off the proton over here. Okay, so this lies and the temperature negative 78 degree cells. Just that is very, very cold. Okay, this is going to lead to the kinetic product. And the kinetic product is the product that occurs the quickest, right? Because if we are negative 70 degrees Celsius, the molecules in the solution aren't interacting as much because there's as much movement in the flask. So we're going to get the the hydrogen that is going to be depopulated. That's going to be the one that is most available. Slash accessible. So if I have a very strong base like my with him Oh, sorry. My l V a. That looks like this. This is a very bulky base. It's gonna come in and have a choice. You can either take off the proton here, or the proton here and getting because it is so cold. The molecule in this molecule there kind of jumping about in the reaction in the flask, I mean, but not as much. So as, perhaps, is your degree Celsius, because again, remember, the higher the temperature, the more movement within the solution. So in this case, because we're in such cold conditions, we're not gonna get as much interaction between this molecule. And this molecule leading us to de protein ate the most accessible slash available hydrogen, which is going to be this one. So after that d pronation, I'm gonna get the in comparison the unstable in a late getting by comparison. I mean, that's the other version would have had to deep red state this hydrant leading to the other, you know, with my own, which would be more stable. So in cold conditions such as negative Soviet resources, when you get this in which we can go ahead and move those electrons around like that in order to form the unstable annoyed I on which would be the Al Qaeda right there and then my our group over here. So, as you can see, we have this hulking with my 200 wins over here and then the rest of my compound versus the stable intellect ion, which is going to be considered to be the thermodynamic product in Missouri Resources. And that's gonna look like this. And we should have my the rest my chain. OK, So as you can see, if this stable, this outcome is considered to be more stable than the other version. So this is the thermodynamic product as far as intellect islands go. And the other version was the kinetic product that their margin image means that we have the more stable came and kinetic means that we have the left they walking, it just happens faster. Okay, So with that in mind, after the base deep rotates my most instead of carnage in of that molecule, I'm gonna have a direction with CHD. I so see, if the I that is just the Electra file that's going to be attacked, attacked by my nuclear Philip carpet in this case, the nuclear fuel carbon is this one that's gonna go ahead and attack my carbon, eventually leading to the addition of a method group on that carbon. Okay, so as far as my brother goes I'm gonna erase a It's gonna look like this. I'm gonna have that extra metal group there and then the same exact product as before. Okay. It's just gonna be located on that, um, last carbon. I'm just gonna highlight this and plop it down right on top of that group. Get so just like that. Okay, Now, let's do party. So again, Part B is gonna lead to the thermal general product, and that is simply because we are in a little bit hotter conditions. So we have more more movements within the flask, we're gonna have more interaction between the base and the molecule question. So that means that we're gonna be more available to take off the proton. That is gonna lead to the more stable product. So again, I'm gonna form the extra method group down on that second carbon for sorry that third carbon technically, and then we're gonna have the Monaco just plopped down onto that position. Okay, so that method group is gonna be located right there and again. That's because we had to deep rotate this carbon as opposed to this one, simply because it leads to the more thermodynamic product. The more stable, you know? Later on. Okay, So with that in mind, let's go ahead and move on to the next one. So how do we get from a much Is this one depart? See? Okay, let's go ahead and to pick that mechanism. So if I start off with Compound A and I need to cut get the compound C. I and I am in these conditions. This is a basic condition. So again, my series 30 that is very basic. I'm gonna go ahead and take off the most acidic proton fit. So in this case, we have two options. Again, we have this option the hydrogen assoc without off carbon as well as the hydrogen associate with this awful carbon. But which one are we want to be? Protein eight to eventually form this six member green. We're gonna take off the hydrogen right here. And that is because if I take off the hydrogen, I'll have a nuclear Philip carbon there, and then that will be 123456 carbons away from the electrical excitement about to attack it versus a far to take off the hydrogen associate with the other awful carbon, such as right here. I would have my nuclear Philip carbon beacon be considered to be right there. And the electrical, except that I want to attack, is only 1234 carbons away. So that would lead to a four member green. And I want a six member doing, so I know I'm going to take off this one. It is also favorable to form a six member green, much more preferentially to a four member green. So that's why we think that proton to it. So Partridge in there, my base takes off the proton, move the electrons onto that carbon, eventually forming my nuclear felt carbon at that position. So I have this right here, in which have my no good file. Be right there. Okay. And then that is gonna go ahead and attack the Electra file, which is again 123456 carbons away. And that's gonna for my six member green right here. 123456 In which this is gonna be my number. 12345 and six kids. And now I just quote unquote decorate my reign by simply adding whatever substitute is attached to the number and system that I wrote right here, so attached to carve a number one right here. We have a muscle group. So that's my main figure on my six member green attached. Carbon number two, We have my carbon eel. So here's my company on carbon Opportunity attached to cover number three. We just have hydrogen is but we don't have to represent that in a skeletal structure for 7005 something but six is where we have a couple of different things. First off, we have the auction, which we had to move the electrons up to after retake the Carneal. So have the auction with the neck of charge as well as my Oh, say three. Okay, so now it's gonna be considered to be a classic conversation. So this whole entire thing is considered to be an interim with the closing conversation, otherwise known as Deacon con decision. And what that does is it basically makes my six member green or in other cases, five or seven member brings. I'm gonna move the electrons down from the oxygen to reform a carbonell and in the process, get rid of my oh, sagely. And that's gonna form this in which I have my six member green. I have my key tone, my Method group and my other key tone over here. Okay. And then, of course, I have my o ch three after we got rid of that. Okay, so we're not actually done with the mechanism. What we have to do now is use this base, which we just got rid of, and it's gonna go ahead. And D protein ate the most aesthetic proton and the bucks instead of Proton is the other hydrogen associate with that spot. It's the one sandwiched between each of these two carbon eels get. So I'm gonna go ahead and take off that proton, eventually moving the electrons onto that carbon, and that's gonna form it. This good product in which I have Carbonell Neil methyl group as well as my lone pairs there and then this should this problem should actually have an HDL to finish off this product because right now it's just gonna be stuck with this. Okay, we can theorize that we're gonna use the h o. Ch. Three in which we use this hydrogen, but in reality, it would be something more sitting like that, then that would be like hcl it. But that would be the mechanism for that information products get mnd deformation of the way. Don't necessarily have to talk about this one, But basically, the formation of this is going to take off the same protons before in this case is going to be, sir, it's going to be this one. And that is simply because if we're to take off this one, the hydrogen associate with that carbon again would lead to a 1234 member during and we don't do that. We want to take off the other hydrogen, which is going to lead to the formation of the six member green. So the hydrogen right here and get that would form a six member during to eventually form. And this product of D. Okay, so that is problem 87

Hello Today we're doing problem nine point forty six and this problem asks us to Java organic products formed when pro panel is treated with each of the following regent. So we'LL start from and work our way to eye. So hey, we have propane all reacting with a strong acid. The strong acid in this case is so fury acid. So as you guys know, I lie just to rewrite my strong acid is h A and you know, strong asset fully associates in solution to H plus and a minus. So when we see and alcohol with a strong acid, we know that a dehydration reaction will occur. So as before, as every single problem you'd identify, What is your new cool file? What is your electrified nuclear file being the source of electron? Some has very electron rich. The only thing that's electron rich here is your oxygen alcohol. So you know that's going nuclear. Quickly attack your hydrogen to pick up a proton and get pro nated into oh, age two plus. Now we know that always two plus is not favorable. Option is not like part of charge. It likes to be neutral or negative so this will want to fall off. But in order to fall off, we will use our A minus which is free and solution to Hera. Allow out dehydration reaction to occur to rember dehydration. You go from S P three carbons Espy too. So you lose a degree of saturation So essentially from Al cane, you goto al Keen. So the way you do that is by picking up one of these beta proton. So beta proton, meaning something that is actually adjacent to your leaving group. And as she saw, it's not these ones that debate a proton, the's air, the beta protons here. So if you see here, this alcohol group was attached to this which is called your Alfa Proton and right adjacent to that is this pro this carbon here, which is your beta proton. So your conjure get acid will pick up the protons from that beta carbon. So if I were to just I raised this and show that are conjugated base, I'm confident. I said sorry will pick up the proton making a bond. When you make a bond, you need to break a bond. So Sigma bond between the hydrogen and carbon will break forming our Al Kane, making you bond when you make a Bonnie's Break a bond. So that's Sigma Bond attached to our water will break to give out dehydration, product and free water plus age two. Oh, plus, we reform our strong acid. And because we reform our acid, we know that this is an asset catalyzed reaction because we reform the catalyst. So next for letter B, we see that we have the propane on reacted with sodium hydride, sodium hydrate associates, toe Saudi and plus an H minus story in plus being unexpected ion h minus. Being the hydride, you can act you, Khun. Imagine that H minus is very reactive and would want to pick up another hydrogen to become a TSH to gas. So the only hydrogen that is a label label meaning that is it's susceptible to nuclear Filic attack or to be ripped off is this hydrogen attached to her alcohol? So we make a bond between the two hydrants forming our age to gas and therefore the bond between Owen Rachel Break, giving those two electrons of that signal bon onto options nucleus to make a formal negatively charged. Oh, minus plus H two gas. And now, if you were to continue this reaction, that's all mine. And after the strong nuclear fall to attack any electro file that we add into the mix Sure. So below here we see that we have a primary alcohol with a strong acid. I would associate into h plus and C l minus so as similar to the first one, we know that we're going to protein eight are alcohol because it was nuclear Filic properties. And now because we know we have a primary I'LL call originally, we know that this is going to occur through s into mechanism in which our nuclear file will backside attack our electro hour No electoral Filic carbon making a new bond. And when you make a Bonnie to break upon So now that we broke that bond, we can draw our substitution product plus our age too. Next we have another strong acid. So this exactly going to be the same thing as what we did before HBR Associates in solution to H plus NPR minus oxygen having nuclear Filic properties will attack this proton to put Nate itself Oren always two plus and because the primary I'LL call We know that our BR minus with its nuclear Philip tendencies because of that formal negative charge giving it extra electrons making an electron rich we're gonna back side one eighty Attack that electoral Filic that electron poor carbon and former s into substitution product. When you make a bond, you need to break a bond and reform water as well. Next, it's another way to do a substitution. Been out with Sokal. So I draw out the structure of soccer here we see that we need to first identify a nickel fall. The nuclear fall, as in all these cases, is our oxygen and electro Felix center. Here is the sulfur Adam here. This is the very election poor electron deficit center here because of those electro negative chlorine ions pulling electron density away from the salt sulphur nucleus as well as this carbon. So we'LL attack our electoral filic sulfur making a bond we make about me to break upon the label group Is this carbon old that'LL pop up make giving us formal negative oxygen? An extra loan para lecture on those lone pairs will collapse back down to reformer Carbonell making bond when you make upon you break upon. So this chlorine being a good leaving group because it's a hail ID will pop off plus C l minus. But now we have positively charged oxygen, which once again is not favorable. So we will use period in in the mixture which it with its nuclear filic nitrogen to act as a proton mop. So this mops up any protons to neutralize all your molecules in your reaction vessel and really promotes reactions to go forward to completion. So now you have You're leaving Group, which was originally hi jocks all group that was converted into a very good, very strong leaving good. So now our nuclear file being the seal minus can back side attack that on pop off our leaving group. Next we have PBR three, so same thing occurs substitution reaction. But instead of chlorine, we're talking bro Ming. So we get our brominated product finally to start off with question with letter with letter G, we have our hydroxide with a tosel chlorides or Tosel Cloyd's once again make your leaving group into a poor living group of hydroxide which is very poor living group into something that is a very strong leading group. So if I were to draw the structure but my toss of chloride, we have this just like Sokal Sulfur is the electro file here. It's very electron poor while our nickel follows of election rich oxygen. So we know that we're in a nuclear physically attack that and eventually pop off our very good leading group, which is the chlorine. Now we have our tosel eight, but oxygen is still prone ated. So we use a proton mop with its nuclear filic nitrogen with those long pair electrons to pick up that extra proton to neutralize our product. So now we have something that is a very strong leading group which in future reactions, if you were to react this with a nuclear file, we would get Essen to reaction mechanism. Something to note up until this point, you're sterile. Chemistry is retained. There is no inversion stare chemistry yet. However, if you continue to reacts with your nuclear file, you will get an s into reaction, causing your inversion on stage chemistry. So if we want to question G, you have your sodium hydride that deep throat Nate, your oxygen just like we did before number and letter B. We had our own minus. And like I said, this can act as a very strong nickel foul to react with any electrifies you add in the mixture. And this is our left far. We added here and you see here, bro Ming being the very strong leaving group it is. We attacked the carbon that is bounded to the bro mean making bond When you make upon, you know, break upon So that bro Ming will break off giving us our either and bromide and ion the last question here we see that we have our alcohol reacted with tosel chloride. So just like before, we made hydroxide which was very bad, leaving group into something that is a very strong leaving group and oh tasa wait. Now we reacting it with a nuclear fall We've in sodium that forms a respected ion this assault. So we have any plus and hs minus sulfur being our nuclear file because of its election rich nature. So we can get an s into reaction mechanism from sulphur going to the carbon, making a bond when you make a pawn in its break up on. So now we have our Sile group here, plus our sodium spectator ion plus our tar soit

Find the second up in pain RDX with HBR and produces it. Prearranged bromide full of the girth airs and proposed mechanism for the whole election for convenience number carbons in the starting line Encyclopedia pain with the full of the error this burg breaks. So now there is no bond between carbons one in three and the bump between carbon once and two is firm. So is it you born the charge forms? I'm comin for you because it lost turtles. Electrons are pushed from this double burn, so it becomes a single barn and the bun between h nbr breaks informs B R minus which accept electricals and this hydrogen EDS. So this problem, that's one of those hard pigeons or vinifera. And on the second step, bromide, the maids air prayer off electoral for the grab A cattle and forms it you born

For everyone to hear. We're doing Chapter 18 Problem 36. And this problem asked us to draw the product form When Fino, which is a benzene with an alcohol, is reacted with each of these re agent. So there is quite a bit of re agent. So just bear with me while we work through this. But if you're if you understand why you form the products in each one of these regents, you guys will be in very good shape for any upcoming quizzes or assessments. So let's start with a band before we serve it, eh? So I struck a here before he started today. Let's identified. So a field we know that we have an auction in Reno. Auction has long prayer electrons. So we need a first identify where the substitute they're gonna add is going to be placed on our benzene ring. So we know that because auction has long pair electrons, they can go through some residents structures. That place is a full carbon on a full negative charge on the benzene ring, their force and increased electron density on the bench entering. Therefore, it is unless on donating group. Therefore, we know the lecture on Tony in groups direct or so and pere on our benzene rent. So every one of these creations will have it too. I summers or most of these products will have to ice summers one being orthe ally summer one being the Paradise mur. So for a we see that we're reacting this funeral with a metric oxide and sulfuric acids. We know that we're adding in nature group to this, so fortunately is promise and not ask us for the mechanism because then we'd be here forever doing his mechanism. But hopefully later in textbook, there will be some mechanistic questions that we can go through to fully confirm why we get and Eno to group when we have these regions in these type of problems, so one is going to be an NL too and nitro group on Ortho Bishan Post will get the Paradise Zimmer having that, you know to group at the Pera position now for B for adding s 03 with sulfuric acid. So we're adding the soul final group here, so be well once again citing the soulful group and now also three h but now adding it and the Ortho and proposition just like this nitro group. So all of these regions are in your text spoke so you can just refer to that to confirm the mechanism of these type of problems or look at the later problems that will cover in this textbook. But it's also good for organic. Commission does not have much memorization. But for simple things like these, these air not too hard to memorize. And once you understand the mechanism, it really helps you to clarify why a certain product will be formed. And that really takes the memorization completely out of it is because you can't just rationally work through the mechanism and obtain the product. So before you guys were doing that, or just the first time saving our system for some multiple layers of verification, memorizing the products for these reactions are helpful. So I just want to see, See, we have now this alcohol hale I group with Louis acids. So we know that this is going to be fearless craft calculation. So we're gonna add 12 carbons onto the ortho or onto the para position to Iceman is being formed one, the Ortho, and won the pair I smear once again, it's the Orthodox and have one to carbon And then the para is gonna have once again 12 carbon So in deal So we have now here we have field crafts I'll, uh, a solution now. So in D, I'll draw the easel group just so we can clarify. So we have one too. So we have one too. Then we have die. A thaw like this is writing this group onto the ortho and armed to the power position in separate I sinners. So plus that I simmer terrorism, getting this one. So now let's move on to e even now have halogen nation. But we have held a nation with some sort of Louis acid. So I'll do Ian on different color. Just help us clarify overhears a e writing bro Ming Group. But now, because we have this asset, we reform this Louis asset to every cycle off adding a bombing on this monkey. Also now consequence of that is that you will get Polly prom in ation so you'll get domination at all your available directing site. So you will get pronation old orphan and Paris site because you're reforming us Louis acid and you're making this bro me in group. That diatonic bro me into such a stronger electoral file Because, in essence, what you're forming is br b r plus down Teo E B R three minus. So you're now making this bro Ming group into such a stronger electoral fall now. So because you're adding it in such strong electoral, you're making to destroy Electra file on your reforming this Louis ass in every time you get a consequence of having this polychrome a nation occurring. So what you gonna be end up with is one product with every single directed sites of both Ortho in the one metre or so one para having domination a current now f that problem is resolved because now we don't have that Louis assets. So once again, we're gonna have only one bro Ming being added to either one of the ortho positions or the pair positions. So once again, because we have no lose acid in this time you will get the substitution products with having one. I simmer at the ortho position. And when I saw her at the Pera position Now, Gene, we're doing thie exact same thing as an E, but we're just changing the identity of the daylights out of the yard to we have sealed to instead of Ft. York Trivia Fncl three. So G is exactly like Eve announcing a blooming It's going to be including. And this is just because we're just changing the density of Hey, lives now on each. So in a JJ, What we're doing is we're taking the product of a and they were adding, reducing agent here. So what we gotta do is so let's draw the product of a CZ. We have two product, eh? So we'll draw the products of a first of its age on DH misses one ice mur. Then we have the other ice murder, and now we're adding tin on DH strong acid. So we know that tin with a strong acid using your textbook as a reference is the reducing agent. So because it's the reducing agent, we know that the only reducible groups here alcohol is already at this most reduced form. It was Aldo hide we could reduce that are herds of gastric introduced that but alcohol's already fully reduced. The aromatic ring here is too stable to be touched. So only thing that's left is the natural. Perhaps we can reduce natural to aiming so they can reduce the ortho and pear. I simmers into Ortho Pera ice summers of aiming so N H, too with him and a strong asset or any sort of reducing agent an inch, too. And then I'll switch colors against Let's do I now. So I was taking the products of Divan, adding another reducing agent here. So we're at in part of the D, which is the Fear Crafts isolation product now was I? And now we're adding zinc mercury with assess this, another reducing agent just like Tim Acid. So once again, alcohol's feli reduced. But now, instead of having the Nitro group, we have a key tone which could be reduced to just see it too. So we can fully reduce this basil drew into an alcohol group. This is actually method. How through feel cross isolation, we can get a straight Shane Carden. Yeah, So you get one item. It looks like this and the other I simmer. Dorcas, Dorcas, we get that also the parallelism don't lose that key tone to look like this. Now, J. J What are we doing in a chair? In generating the product of D, they were adding hydrazine and alcohol. So we add hydrazine and alcohol. This is actually another way to fully reduce your a social group. So this is actually very specialized way of reducing a little group. So you actually will get the same products as in I hear. So these three agents, so hydrazine in on hydroxide and I on with zinc mercury, um, and I said, strong acid. The Syrians alert different. They're both reducing agent. Specifically, they will reduce your carbon on group's heir key tones to stretching. Al came. So both I Andrzej, we'll give you the same products. So now what about in K and this hydrogen in the mechanism for this has also shown in the textbook just for reference. But this is one of the case where it's good to have a little bit of memorization, organic chemistry, just to be able to identify these things quickly. So you don't waste your time on a test so Jay will take a product and see, So let's take that product and see okay groups. We have to i summers and we're adding roaming and light, so each new is light. So this is a radical Bram in ation mechanism. And specifically this type of radical Dr Abomination occurs at the bins. Ilic carbons here been zilla Carbon is the first apartment off your Benzedrine. So these are your penzler carbons. Urine after brewing. Ah, hey, Light onto these positions. So you will have once again your toy summers one ad in the roaming off the ortho position and one IDing the brawny off the para position benzel of carbon. And now, last but definitely not least so. L were often the product of C And then we're using came and afford fully reduce that Oh, sorry, fully oxidized that. Sorry. So I was thinking the product of C and we're using came in a four toe fully oxidizes sow. What you will we know about came in before is that it won't touch this alcohol because if you were to put a double bond here than this, carbon here would get five bonds and we know that's not possible. It's only carbons that it can touch. Is this Ah, Ethel Group that we added here. But some people might say that well, we would have a carbon spacer and then oxidized that this terminal carbon. But what would they think that we often is terrible for mechanical force so strong that is gonna oxidize the first carbon off of benzene. So it's gonna happen in multiple steps. First will oxidize this into a key tone, then to an alga hide and into a car park Cilic acid. But overall product is going to be that car looks like acid product with on ly one carbon attached to it. So what I mean by that is that you'll have this carbon here being remains staying on. Then you oxidize it with the Taliban oxygen. But then we're gonna have your car back. So gas, it's so this carbon here falls off in a process of this oxidation because first we go through key tone that I had to hide them car back so gassid but came in before you. You cannot isolate the elder Hideaki Tone product. It's goingto oxides fully right away instantly to your fully oxidized Carmack silk acid form. And you're gonna have this with both of these ice immers, and that's it's for this problem


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What is AG'rxn in kJlmol for this reaction at 314.2 Kelvin? Please report an integer, without units: 4 HNOalg) + 5 NzHAU) + 7 Nzg) 12 HzoU)AH'; (kJ/mol)133.950.6285.8s"(JlmolK)266.9121.2191.670.0
What is AG'rxn in kJlmol for this reaction at 314.2 Kelvin? Please report an integer, without units: 4 HNOalg) + 5 NzHAU) + 7 Nzg) 12 HzoU) AH'; (kJ/mol) 133.9 50.6 285.8 s"(JlmolK) 266.9 121.2 191.6 70.0...
5 answers
Which of the following would have t0 lose two electrons in order t0 achieve & noble gas clectron configuration? Check all that applles -SeMqHeSt
Which of the following would have t0 lose two electrons in order t0 achieve & noble gas clectron configuration? Check all that applles - Se Mq He St...
5 answers
CH; JCH;CHHCH; HCH;H CH;Whizh of the above has the highest amount of energy? DACH; CH;
CH; JCH; CHH CH; H CH; H CH; Whizh of the above has the highest amount of energy? DA CH; CH;...
5 answers
0/15 pointsIt is of interest to determine the average number of upvotes Reddit posts receive from its users; Assume an analysis of 10,000 randomly selected Reddit posts revealed an average of 54 upvotes Identify the following:Population10,000 randomly selected Reddit postsParameterReddit postsVariablenumber of upvotesStatistic54upvotesSampleaverage number of upvotes
0/15 points It is of interest to determine the average number of upvotes Reddit posts receive from its users; Assume an analysis of 10,000 randomly selected Reddit posts revealed an average of 54 upvotes Identify the following: Population 10,000 randomly selected Reddit posts Parameter Reddit posts ...
5 answers
Find thc Tullvning _-scuresMle Mre#the lefr of the >-scnre 0.9750 The 4rtil rght of thl cicutl 0.13147U1070 02The z-scor"e thac separates the lonest 10%rhe population
Find thc Tullvning _-scures Mle Mre# the lefr of the >-scnre 0.9750 The 4rtil rght of thl cicutl 0.1314 7U10 70 02 The z-scor"e thac separates the lonest 10% rhe population...
5 answers
Enough of a monoprotic weak acid is dissolved in water to produce 0.0149 M solution. The pH of the resulting solution is 2.34. Calculate the Ka for the acid.1.08 ~3 xlOKa
Enough of a monoprotic weak acid is dissolved in water to produce 0.0149 M solution. The pH of the resulting solution is 2.34. Calculate the Ka for the acid. 1.08 ~3 xlO Ka...
5 answers
Time taken by a bus from point A to point B is normally distributed with standard deviation of 2 minutes. If the bus takes more than 40 minutes 5% of the times what is the mean time the bus takes to travel from point _ A to point B?
Time taken by a bus from point A to point B is normally distributed with standard deviation of 2 minutes. If the bus takes more than 40 minutes 5% of the times what is the mean time the bus takes to travel from point _ A to point B?...
5 answers
Question 20Which compound gives the NMR spectrum below? (Note s = singlet; d = doublet; t = triplet) OHOHHOHO"PPM
Question 20 Which compound gives the NMR spectrum below? (Note s = singlet; d = doublet; t = triplet) OH OH HO HO" PPM...
5 answers
I! H 1 H 3 9 [ 3 1 1 V druio8 1eiio
I! H 1 H 3 9 [ 3 1 1 V druio 8 1 e iio...

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