5

45 (Uha Quule kxyne IUPAC 1kx (2 4hs Cbnpa Rielyl-|nlancl, 20clyyl 4hflnx peaskare 4mAlyl-z-pnlanoly estnipeotane ZielyLkpLpaua ly Zhyclbxy [ynch 1CCx5"1"...

Question

45 (Uha Quule kxyne IUPAC 1kx (2 4hs Cbnpa Rielyl-|nlancl, 20clyyl 4hflnx peaskare 4mAlyl-z-pnlanoly estnipeotane ZielyLkpLpaua ly Zhyclbxy [ynch 1CCx5"1" Lalledi J 'afol Ctuol be2sndlerC-sh l hasfamshu . ChyChzoll Fo 1.61 ('#gCHzUNa no 2-M0 Na LH __

45 (Uha Quule kxyne IUPAC 1kx (2 4hs Cbnpa Rielyl-|nlancl, 20clyyl 4hflnx peaskare 4mAlyl-z-pnlanoly estnipeotane ZielyLkpLpaua ly Zhyclbxy [ynch 1CCx5"1" Lalledi J 'afol Ctuol be2sndlerC-sh l hasfamshu . ChyChzoll Fo 1.61 ('#gCHzUNa no 2-M0 Na LH __



Answers

1The IUPAC name of is (a) 3-oxo-2-heptyne (b) hept- 3 -yn-4-oxone (c) hept- 4 -yn- 3 -one (d) hept-3-yn-4-one

So for this question, we have four different. You pack names here, type tone or can, um so we can see here for this 1st 1 we have 23 dyke or oh, Where metal first. It's pretty daunting. But if we just look at this route here, this will tell us what we need to know. For our base of our compounds, we go 12 three or five. Six. So there's our heck sane. Now we have to look at OK, is it gonna be 23 to here from the die in front? And then we have koro here as our route. So it's basically saying that we have to Corinne's on the second and the third carbons here. So we'll put a pouring there and according here. So here's our Corinne's and then on our fourth carbon here, you can see that we have a metal so arm Ethel is just one one carbon. Nothing too fancy there. So we have 123 for a dyke. Loro, Then on our fourth carbon here. So 1234 we have a metal. And there's the structure for this. Are you back name moving on to the next one. Once again, we want to look at the root. The route here is heck sane. Same thing. So 123456 Same here and saying so here. I always start from the front side and then work backwards after I have my route. So here we have on our fourth carbon, we have 1234 We have a bro mean here, right here will put a stick upwards and put our bro mean here. I'm gonna put my highlights and read just that they stand out a little bit more. Um, and then also on our 4th 1 we have an ethyl. So Ethel is basically instead of metal, metal means one carbon Ethel means to nothing too fancy about the name. So we can just kind of stick it on like that. You know, um, sometimes you have to put them on the wedges and dashes, um, to show what's in front and what's in behind, uh, of this main structure here. But that's only whenever we get to, like says Trans or are an s. We don't have any of that, so we can just stick it on. That's and Then on our second, we have one metal here. So one carbon. So 12 will stick that upward like that. So that's why you pack. That's a structure for this I fact name moving on to this one. We have pain tain as our route here. So let me underline that you also have a Iot toe, which is, um I dine instead of romaine or chlorine. Um And then we have a tetra Well, here. So that's why we have to to for four, we have four different numbers for where these four methods. They're gonna go. Um, so we go. 12345 There's our contain. Then on our fourth car, we can go. 1234 stick upwards. But the iodine on their I, Dean, whatever you say, it doesn't really matter. Um, and then we also have our tetra metals. So on our 12 we're gonna have one, because we have one to in a on our fourth carbon, we're gonna have 44 So we already have a metal here because each carbon could only hold four things. So this is 1234 So we'll put one more up there and we already have our for me metals here. So we have a metal here. We have ah, meets a different color. Have a metal here of a metal here, have a metal here, and we have a metal here. So this one would technically be 12 432 Metals here, two metals here that completes this idea packing their the structure for this I This one's a little bit different because we have says up in front services is something that's gonna tell us. Is it on the same side or is on different sites? Trans we'll have on different sides of the structure. Says they'll be on the same side then. Here we have contain but a little bit different. Here we have this thing called. It means it's a circle. So, Joe, a little house figure the best, But 12345 We have five right there in a circumstance of cycle. Um, then we look at one bro mo to Ethel cycle. Pity. So because it says these are gonna be on the same side, So doesn't matter. We could use a wedge for them or a dash. I'm just gonna use a wedge. Um, this is one promo. I'll just go ahead and stick this here. Our wedge There's a row mean here and then on our second carbon we could you go this way or this way it doesn't really matter. Just go ahead and put this one on a wedges. Well, just to show that it's gonna be says and not trains. Because if it were Trans, this one would be a dash where this one would be a dash. Just one. We're a wedge. They basically would have to be opposite to be true. So that would be to Ethel. So there's are one carbon here cause this would be basically metal. So we have to show that we have another carbon there. So there's 12 for Ethel. So this is the structure for this you pack name. It's a little bit different cause we have that citizen front, but overall, it's pretty much the same

Growth structures Responding to the foreign names a guy I support you mean well, I support true three. Try a little. I mean one a little No, A mill. A little in mithril in union. And you with one hard dejan substituted with missiles N f l M Mitchell cycle up into I mean cycle up until I m f l and Missiles and I support cycle Hexcel. I mean critics you and isopropyl in if if I roll Fertile and Ethel.

Hi, everyone. So the structure of the P H and H toe in this he thought Ph next toe it is the so called une lean. Then structure up. I relevancy needs of the scenes. Are you know of anything? Their next structure off I saw propelled by insane are two final broke. Then the further again called Soufan. L Okay, then. Yes. See trees. Yeah, This is a zone on its Benzali. Hi. In this aids? Yeah. Then say gas it. Okay, the same bang Xylan covered. Then this is keep. When I told you in that is ch three, then Paras Eileen. Yeah, Yes. Three ch three. Then want to die a minor benzene. So this is 12 diamond avenging.

This is the answer to Chapter four. Problem number 41 fromthe Smith Organic chemistry textbook. I'm in this problem. We are given many I you packed names and asked to draw the molecule for each of these. Um and so just a heads up. This is gonna be, ah, a bit of a longer answer than usual on theirs. Quite a few names that were given, and so I am just gonna start drawing them out. I mean, so remember the way to approach this. The end of an AIPAC name tells us either the longest carbon chain or the biggest ring. If if there's a ring that's bigger than any of the carbon change president and so that's a good place to start. Start with that bass name again. That's the end of the name. Um, And then I used the rest of the name to fill in some information about substitutes. So, for a we have three ethel to metal. Heck, sane. Um, and so again, the end of the name tells us this is a hack seen derivative, so we can go ahead. Six. There's a hex ain on. Then again, it's three ethel to metal so want to three Ethel to metal. So there we go. There's three Ethel to metal hack sane for a time. And so that's Ah, that's the way that I'm going to solve these. I'm gonna look at the end of each AIPAC name. Used that to determine, um, the base chain or the base ring on and then use the rest of the name to fill in the substitue INTs. Um, okay, so that was a B. We have sec. Beautiful psycho plantain. So Psychlo plantain is the bass name here. So five members ring Psychlo pen tain, um, and then on any of these carbons, we can draw a sec. Beautiful group. So I don't like the way that looks. Um, So there we go. There's a better sex. Okay, um, and again, it could be any carbon because we're not given a number or anything. And really, there's no way to number it, because all the carbons air equivalent until we put a substitute on there. So that's Ah, sec. Beautiful Psychlo plantain. So then looking at sea, we have four isopropyl 245 Try metal. Hep teen. Okay, um and so again, obtain is the bass name here. So 1234567 Then let's see. Four isopropyl 245 Try metal he obtain. So, uh, I like to go left to right whenever possible. So this will be carbon to there's, um Ethel Carbon four. There's, um, Ethyl carbon five. There's a metal. Ah, and then four ice a pro bowl. So actually, let me back up a little bit. So there's one on carbon five. There's one on carbon four. Ah, and then here is our isopropyl group. Also on carbon for okay. And that's for isopropyl 245 Try metal hip teen s. So then d is gonna be Psychlo. Beautiful Psychlo. Hep teen. Okay, so this is a seven member ring with a four member to ring attached to it. Okay. Seven members rings, um, are are always a struggle to draw. Ah, I like to pretend that I'm drawing a six member dring. I'm And then instead of, um, bringing the last two sides together, as I would for a six member drink, I bring each of them down on Lee a little bit. Ah, and then put a connecting peace between them. So that's That's how I do it. Um, that's not great looking. There we go. It's a little better. So there's our Psychlo hep teen on then anywhere we can put a cycle of beauty. So there we go. There's day e is going to be three Ethel 11 dime Ethel Psychlo vaccine. So we need to draw a cyclo hexane to get started. So draw a hexagon, and then it's three Ethel 11 dime, Ethel. So we can pick any of these carbons to call one, so I'll start here. This is carbon one. Ah, that makes this carbon three. Um, you know, or you could have done the bottom carbon as well. If you name that carbon one. Ah, it doesn't really matter. Just as long as you know your numbering is consistent. Ah, and so there's e f is going to be four beautiful 11 die. It'll psychlo octane. Oh, boy. Psychlo octane. Okay, so this is gonna be an eight member ring. I'm so bear with me as I tried to draw this, so All right, let's see here. No, I know how to do this. Okay, so right. So this is just like drawing a seven member ring, but you do the same at the top and the bottom. So there we go. There's an eight member drink. Okay, Um and this is four beautiful 11 die, Ethel. So let's make, uh, this carbon number one. So one ethel group two other groups on and then four. Beautiful. So we'll go to three. Four, and again, you could go the other way. A CZ Long as you are consistent in your numbering. Ah, so beautiful one, too. 34 Alright, there we go. Um, there is Ah, four beautiful 11 die a full psych low octane. Okay, um and so I'm gonna move on to a next page here. G is asking us to draw six isopropyl to three. Dimethyl na name. Okay, So non ain is ah, the base of our name here. 123456789 There's non ain six isopropyl to three dime, Ethel. So again, I like the number left to right. There's nothing that says that you have to, but that's how I do it. There's 23 I would should make 456 ice a pro bowl. There we go. there's G, um, Kane's h h is gonna be 2 to 67 Penton. Ethel Octane. Um, so we start with octane. 12345678 2 to 667 So five methyl groups here. So 22 345667 Okay, um, so next eyes gonna be cysts. One ethel, three metal Psychlo painting. Okay, so, again, Psychlo plantain is our base name. We can start by drawing a five member ring cycle plantain. And then this is cysts one ethel three metal. So, um, we can draw them dashed or wedged as long as we draw them both the same since they're cysts. Um, and so arbitrarily make this carbon carbon number one. I'm so one asshole. Three meth. Eliza's gonna look like this. So there we go. Uh, one Ethel. Three metal psych, Lapentti. Okay. Um, so that's I on again for I, Like I said, we could have made them dashed, uh, or wedged as long as they were. Both are the same. Okay. And so, uh, it looks like J. Uh is is the last thing we're asked to draw here. Um, S O. J is Trans one tert Beautiful four Ethel Cyclo Taxi! So the first thing to do is to draw a cyclo taxi. So again, it's just gonna be a hexagon. There's our hexagon. And then let's see Trans one Turk beautiful for Ethel Cyclo taxi. So Ah, we can start with Ah, the one tert beautiful. So there is Ah t Beetle Group. Ah! And then we need to put on Ethel Group on four. And remember, we want that to be trans to the turbulent group. So since I made the Turk Beetle group wedged, I'm gonna make the Ethel Group dashed on. So there, that is. Um we could, of course, do the opposite. Where the Turk Bugle Group is dashed on, Ethel Group is wedged. It doesn't matter, so long as they're trans to one another. Um, and that's the answer to J. Um and that's the end of this problem. And to remember, the way to approach this is to look at the eye you pack name, um, and remember that the end of the AIPAC name tells you the base chain or the base ring. Um, start with that structure and then use the rest of the name to figure out what the substitutes are and what number carbons they're located on. Ah, and that's the answer to Chapter four. Problem number 41.


Similar Solved Questions

4 answers
370 of arginine are 1.8, Dand 12.5. Show the ionization scheme of arginine 18. The pK values and calculate its isoelectric= point
370 of arginine are 1.8, Dand 12.5. Show the ionization scheme of arginine 18. The pK values and calculate its isoelectric= point...
5 answers
Ifyou are picking . number between and 100 inclusive; what Is the probability of picking = number which Is not a multiple of 277
Ifyou are picking . number between and 100 inclusive; what Is the probability of picking = number which Is not a multiple of 277...
5 answers
Which of the following is an expression of P? Write "yes in front of those which are expressions of Pand write "no" in front of those which are not: (1 point each) Ax - B2. Bxx V < Ay3. ((Vx) ^ axC=(x)Qx 5. (Vx)Px ~ (y)Qy
Which of the following is an expression of P? Write "yes in front of those which are expressions of Pand write "no" in front of those which are not: (1 point each) Ax - B 2. Bxx V < Ay 3. ((Vx) ^ ax C=(x)Qx 5. (Vx)Px ~ (y)Qy...
5 answers
The area of the shaded recion encosed by the curve in the figure could be represented as:f(x)A=j r)ax -J r(x)axA=f (r)dx f f() dxf (*)dx WS (*)dxfKJax
The area of the shaded recion encosed by the curve in the figure could be represented as: f(x) A= j r)ax -J r(x)ax A= f (r)dx f f() dx f (*)dx WS (*)dx fKJax...
5 answers
DETAILSSCALCET8M 5.2.074.Express the limit as a definite integral:lim 0 +01 + (i/n)2
DETAILS SCALCET8M 5.2.074. Express the limit as a definite integral: lim 0 +0 1 + (i/n)2...
5 answers
Let1Compute AB and 2A 6
Let 1 Compute AB and 2A 6...
5 answers
(9x106) (4x102) significand 1oexp onent (7.6* 10-4) (25*104)significandexponent
(9x106) (4x102) significand 1oexp onent (7.6* 10-4) (25*104) significand exponent...
5 answers
For the distributon in question_Wnat is thc mcanH?What is tha variance,0*7Whal [s thc standard dcvation,07
For the distributon in question_ Wnat is thc mcanH? What is tha variance,0*7 Whal [s thc standard dcvation,07...
5 answers
This question should be uploaded as one file that includes all parts a - f Be sure to clearly mark the identifying letter for each of the problems.Consider the following matrices:c=| -2 2 52]0547-2-3Find the following (Show work to support your answers) If the operation is not defined, s0 state and explain why:(All parts are 4 points each except € and are 2 points each) Please circle or box your final answer for each part:ACb. 5A - 3DDTDBtr(C)c-1
This question should be uploaded as one file that includes all parts a - f Be sure to clearly mark the identifying letter for each of the problems. Consider the following matrices: c=| -2 2 52] 0547 -2 -3 Find the following (Show work to support your answers) If the operation is not defined, s0 stat...
5 answers
The molar solubility of lead carbonate in a 0.266 M potassium carbonate solution isM.
The molar solubility of lead carbonate in a 0.266 M potassium carbonate solution is M....
5 answers
Objective 4Find the least common multiple of 12 and 9 .
Objective 4 Find the least common multiple of 12 and 9 ....
1 answers
Solve each problem by using three variables. See Examples 5 and $6 .$ remember that the sum of the measures of the angles of a triangle is $\left.180^{\circ} .\right)$ (IMAGE CANNOT COPY) In the 2008 Summer Olympics in Beijing, China, Russia earned 5 fewer gold medals than bronze. The number of silver medals earned was 35 less than twice the number of bronze medals. Russia earned a total of 72 medals. How many of each kind of medal did Russia earn?
Solve each problem by using three variables. See Examples 5 and $6 .$ remember that the sum of the measures of the angles of a triangle is $\left.180^{\circ} .\right)$ (IMAGE CANNOT COPY) In the 2008 Summer Olympics in Beijing, China, Russia earned 5 fewer gold medals than bronze. The number of silv...
5 answers
Are Yersinina pathogenic in humans? What strain and what disease? Explain?
Are Yersinina pathogenic in humans? What strain and what disease? Explain?...
5 answers
Lhardumerence henveen alchabutu hemclumedineWhat chcmical dcfined medium?Whalart Iwo enzvme presentDacterizdes[ro peroxidtoxide and which bactenarnar inoseeoivtneWhat'$ the difference wth photojutctrophs ana chemo? utotrophs? 20.22
Lhar dumerence henveen alcha butu hemclu medine What chcmical dcfined medium? Whalart Iwo enzvme present Dacteriz des[ro peroxidt oxide and which bactenarnar inose eoivtne What'$ the difference wth photojutctrophs ana chemo? utotrophs? 20.22...
5 answers
Find the values of T, y and that correspond to the critical point of the function:f(z,y) = 5r? 5z + Ty + 2y? IryEnter your answer as number (like 5, -3,2.2) or as calculation (like 5/3,243.5+4).PreviewPreviewPreview
Find the values of T, y and that correspond to the critical point of the function: f(z,y) = 5r? 5z + Ty + 2y? Iry Enter your answer as number (like 5, -3,2.2) or as calculation (like 5/3,243.5+4). Preview Preview Preview...
5 answers
Attached is spectrum of chlorobenzene. Identify the base peak and molecular ion peak: Given that the nominal mass of chlorobenzene is 112 daltons, why do we see such = strong peak at 114 daltons? (3pts)Benzene_ chloro- MASS SPECTRUM10010.0100120
Attached is spectrum of chlorobenzene. Identify the base peak and molecular ion peak: Given that the nominal mass of chlorobenzene is 112 daltons, why do we see such = strong peak at 114 daltons? (3pts) Benzene_ chloro- MASS SPECTRUM 100 1 0.0 100 120...

-- 0.020432--