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Reactions products of the following 99. What are theHO(CH;CHz)NCH3O CH;o _CH3SBrHOCHzO _...

Question

Reactions products of the following 99. What are theHO(CH;CHz)NCH3O CH;o _CH3SBrHOCHzO _

reactions products of the following 99. What are the HO (CH;CHz)N CH3O CH;o _ CH3S Br HO CHzO _



Answers

What are the products of the following reactions?

This question asked us to draw the products of each of these reactions. These air, both deals, older reactions. So just to quickly recap a deal's older reaction, we have a dying and a dying A file these air, the simplest two examples of those, and we'll have some electrons moving around here. So this will move over here. This move over here in this back here, and we will always get a six member ring with a one single pi bon left over on the dying side. Um, and so I'm gonna orient each of these in this way to make it easier to see. So for part A, we have a five member green here that has already oriented correctly, and then our dining are joining file. Looks like this. And then we have this key tone coming off of it like this. So if we do that reaction here, this comes here. This comes here and that goes back there were going to get a bicycle IQ, um, ring. So first we have our six number ring that we always get with. That one double bond looked over on the dying side. Um, and then the leftover carbon from If I remembered, ring will just be in the middle. So it's like this and then the rest of Dinah file it's just right over here like this. So that is one way to draw. It will also often see these drawn in this sort of, um, drawings. And then this one up here is the other end of the remembered ring. This is where our Dina filed waas. And then we have, um, that key tone over here. So either one of those ways of drawing this product is correct. And then for part B will do the same thing. So we have our dying already in the correct confirmation, and then we'll put our Diana file like that here. This is the same Diana file we had in a part. A. And so we'll do that same electron movement like this. So we'll get a new a six numbered ring with that double bond left over. We have the rest of that old one between those two car end carbons, and then we have the rest of the Diana file. Or you can draw this one in that other confirmation as well. So it would look like this, which have two carbons up top now. And, um, that key tone the left over. Over here. So again, two ways to draw this product.

So here are a Parkside Ring breaks due to the nuclear Filic attack by the Gilman's re agent. And then upon the reaction with our acid, the negatively charged oxygen atom reacts with H plus, which is our proton and forms the alcohol functional group. So the above we just illustrated in a mechanism while we start off, we've got ah, the Parkside. Ring him where we have a cyclical structure without oxygen involved and then we simply open up the chain. And then what we're left with is a negative charge. We react with the Prothom in order to generate our final alcohol structure which will look as search as you concede. We have our alcohol functional group as grooves requested in the information above by reacting are negatively charged oxygen after which is hair with a proton. So here is our final product just at the bottom. And then this is a side product that was also formed

So here all we're doing is looking at products structures. So in our fast example here, you can see that we haven't aromatic. We've got a benzene ring, then on one of its substitute. Since we have and Al Qaeda group where we have a double bond present in our second structure, we now have we still have a sec trickle structure. However, it's not aromatic. And then like in our first we had that alcohol chain. However, at the end, we haven't alcohol group here and then again, just another cyclical structure. However, we have cough on lithium associated him. So in our side example, we have the cyclo hex. Meanwhile, we have a double bond in our vaccine structure and then we also have another alcohol chain with all single bonds. Where were also generating another alcohol chain was copper on lithium chloride. So looking at on next one, now we have again Bansi and bring. We have an aromatic with a substitution that has a double bond present and it also has a carbon. I'll present so getting close to the end. Now we've got one more aromatic in a simple alcohol chain. Like our previous examples are very last example is similar. However, we just have the addition off that double bond in our AL keen chain rather not al cane chain.

So in all of the following reactions here, we're forming an organic elysium or gonna incorporate and lastly, a couple ing reaction. So as you can see here, we've got many mechanisms where our first couple we're looking at or organa lithium. So we've got starting materials that are very good leaving groups, for example, bro mean. And then we're taking the product of our fast reaction to use for our second in the product of our second reaction to use for off that, as you can see here. So in our second example here, the reactions are similar to those we just looked up. So will only cover the last one that is Abbas. A slightly different produced A having a cess al came present in our starting material we need to retain that sets confirmation in the product moving on to see Now we're using a groups catalyst. So we see the compounds undergo of ring closing metastases looking next that our example. We have a Suzuki reaction taking place in the next two examples and then lastly, we're looking at a heck reaction taking place in the synthesis


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