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(1 point) Find the equation of the tangent line to the graph of y(w) 5 cot8 (x) at € = T 4Equation of the tangent line is y...

Question

(1 point) Find the equation of the tangent line to the graph of y(w) 5 cot8 (x) at € = T 4Equation of the tangent line is y

(1 point) Find the equation of the tangent line to the graph of y(w) 5 cot8 (x) at € = T 4 Equation of the tangent line is y



Answers

Find an equation of the tangent line to the graph of
$y=g(x)$ at $x=5$ if $g(5)=-3$ and $g^{\prime}(5)=4$

Today we will find the equation of a tangent line at X equals five. G five equals negative three and G Private five equals four. So to find the equation of a line we have the equation y minus y zero equals m times x minus X zero. For this case, M is equivalent to G prime of X and X and X zero and Y zero are just the points. So it will be X and G f X. So we'll basically just plug in the numbers. Why minus g f X is negative. Three. So positive three equals the slope is this one so four and X minus five. So to simplify and sulfur y, we'll have y equals four X minus 20 minus three, which is equivalent to y equals four x minus 23 which is our final answer.

So let FX be two x cubed at four. X squared minus five X minus three. We want to find the equation of the tangent line at X equals minus one. So do this not to find first thing is, you find the derivative at this one on. The second thing is, we did find a point AP on the line hates Let's go and do the first problem. Personal way to find What is that? Private X. So we're just different change. Everything kind of turned points. We have six x squared. That and the direction of four X squared is eight X Georgian off minus five X is my five Joe to my 30 This is our derivative. Now we want to find f prime of minus one. So we just substitute is it six times minus one squared. All right. Eight times minus one minus five. This is equal to six minus eight minus five. Which is going to be cool. Six months at sea. This is gonna be minus two on his five. His mind. Seven. Okay, now, the next step is to find a point on the line. So we're already given the X value off the thing That's interesting. So getting minus one and then the y coordinate is just gonna be getting by F minus one. So this is a point. Maybe so let's go ahead. Calculate minus one. Refuse two times minus one. Cute at four times. Last one squared minus five times minus one minus three, which is minus two class fool plus five minus three, which is going to be equal to see. So we stuff got minus five plus five plus four. Just full. The point is minus one full. Now the equation of the light it's going to be why minus B because and X minus a Now let's just substitute everything in. So why minus full? He calls minus seven x minus. But this one. But she's same thing saying Why? Who's minus seven? X Linus seven plus Fool, which is minus seven X minus three. This is that a tension line and we are done

All right, we have a function Y equals G of X. Let's just write it off over here. We have a function Y equals G of X. We do not have the graph of G of X. But we do know a little bit of information. We know that G 05 is negative three. uh that means when X is five, the value of the function G is negative three. That means 2.5 common negative three is on the graph. So that's this point right here. All right. Here's the .5 comma -3. We know this point is on the graph of G Fx. Now we also know the derivative of G Uh at x equals five is 4. So the derivative of a function At a particular x value. Like five means that the tangent line to the curve to the graph of the function at X equals five is going to have the same slope as the derivative. That's the most important point. So, let me rephrase that the slope of a line that is tangent to a graph At X equals five will be the derivative of the function at five. So, when G prime of five is equal to four, this means That four will be the slope of the tangent line to slope of the tangent line. It's really pretty simple and try not to make it too complicated. The slope of the tangent line is the derivative of the function at the point where the tangent line touches the graph. So four is going to be the slope of the tangent line. So what is the tangent line going to look like? We're not actually even going to graph the function G Fx. I'm just going to graft the tangent line Now we know that when X is five to function G 05 equals negative three. So that's how we know that the 30.5 common negative three is on the graph of G Fx. That's the only part of G F X. That we're going to graph. But the tangent line detain geant line is going to touch the graph of G F X at this point. So the tangent line will pass through the 0.5 common negative three. And we know the slope of the tangent line is the same as the derivative. So G prime at five is four. So four will be the slope of the change of life. Now you need to remember that you can think of slope as rise over run so we can write this whole number four as 4/1. So, from this point since the slope of the tangent line which of course equals two derivative is 4/1. Rise over run. We're going to rise four and run one. So rising four units from this 40.1234. Okay. And then running one brings us right here. So let's draw a line from this point. Rise four over one. That's what the tangent line looks like. So this black line is not the graph of g F X. It's the graph of the tangent line lastly what we need to do. We just need to write the equation of the tangent line. Now in algebra, you learned what was called the point slope form of the equation of a line was why minus Y. One equals M Times X -X one. The Y and E X are going to stay Y and X. But we're going to substitute in for X one, Y one and The X one is going to be ah the coordinates of this point. Okay, this point is tangent to the function G. Of X. Okay, this line is tangent to the function G fx at this point. So even though we don't have the great G of X, we know what the tangent line looks like. And we need to coordinates uh of this point right here to be our X. One and ry one, those two points are on the tangent line. We are trying to come up with the equation of the tangent line. So you need a point on the tangent line. This red dot is red point is on the tangent line. And so these coordinates are X one and Y one. Lastly, we just need em while the slope of the tangent line, once again is the derivative of the function at the point. So the derivative G prime when x was five G prime is equal to four. And so now we just substitute in Why minus why one? Why subtract why one? Why subtract negative three equals M. M. The slope is the derivative for and then times X to Y. N E. X. Stay the same. You just substituting it for Y. One M. And now X one. Uh So X subtract now we substituted for X one. X one was five. Moving this down just a little bit. All right now we just do a little algebra to clean up oriental. Why should attract negative three? Uh Is why plus three Equals distributing the multiplication four times x is for X. Ah Subtract four times 5 is 20. Now we can attract this three from both sides of the equation and we get y equals four X. Subtract 23. That is the equation of our tangent line. So even though we never had a picture of the graph of G F X. Uh We just knew that this black line here, this this line was tangent. It touched the graph of G F X at this point. And we wanted to find the equation of this tangent line. And to find the equation of any line. You just need a point on the line. So we had this point that was on the tangent line and he needed to know the slope of the line. And of course the slope of a change in line is equal to the derivatives

Given a parametric curve. Um Actually close t to the fourth T to the fourth plus one. Y because T. Q plus one. And were asked to um finally equation from the tangent line when uh uh when t not when he is minus one. So to find the tangent line to a parametric curve or find the slope of this parametric curve. You can write dy dx as dy DT divided by the X. 30. Now that's um you can't just say that these cancel out but you know they talked about that in the book. That is really the chain will that allows you to do that because the Y. D. T. Was dy dx dx DT and then you can soften dy dx. So we need to take dy DT that just becomes three T squared dx DT is 40 the 40 cube. So The sole point of being 3/14. So we can see when you T0 which is right here we have a vertical a vertical slope. Um But at one at minus one to minus one. We're down here somewhere equals minus one. We're at 20 right here. Um Our slope is minus 3/4. And so the tangent line is then minus 34 times the quantity X minus x now. And that's two. And then plus why not? Which is zero. So are tangent line is minus 3/4 X plus three have and that is right here. So we can see that. Indeed it is tangent to our curve right there


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