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E4achce ueheftk funetionmeking table vlucaI)er-12...

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E4achce ueheftk funetionmeking table vlucaI)er-12

e4achce ueheftk funetion meking table vluca I)er-12



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Use the given equation to complete each table. $$ y=2 x+15 $$ (table cant copy)

So we're gonna do problem 47 over again, using the entropy of combustion for this methanol. Let's see here. So we have methanol, and then we have 120% oxygen Theoretical oxygen. So here's our reaction. Our reactant, our products are at 60 C and Hunter killer Pascal. So we have toe adjust for that, Um, we can again look at the moles of of vapor that we can have in this product here. And we can see that. In fact, we, um what will not have any vapor in our not have any liquid we can. All of this amount of to two moles of to kill a moles of water can be saturated in this, um, in this, uh, gas at this temperature and pressure. So we got all of this water is going to be saturated or vapor. And so we we know we had the entropy of formation for the C h. 03 but we don't need that in this case, but we can look up what the entropy of combustion is, And then the converted to a mall basis using the molar mass, and we get minus 643,000, 956 killer jewels per kill A mole for this methanol. Now that he transferred again, we have to adjust because we're up above our nominal conditions. And so we have to adjust for the co two the H 20 the 02 and the end to and again we can look all these values up and plugging everything in. We get at the increase change in an therapy because of the change in state is 10,898 killer jewels per kill a mole. So we know this and we know this so we can calculate that. And it comes out to be about minus 627 mega jewels per kill. A more of heat on booth. Negative of that is how much is going out

To answer this. We have to follow the formula. If he is 24 then we're doing 24. Divided by 12th 24. Divided by 12 is too. So our first answer is to If he is 72 then we're doing 72. Divided by 12 72. Divided by 12 is six. So six is our second answer for a last one. If P is 1 80 we're doing 180 divided by 12. 180. Divide by 12. 15. So you're three. Answers are 26 and 15.

And this problem we have. Let's see here. We want to redo problem. 43. I'm using the table 14.3 instead of table 10 point a 10. So we're gonna use the entropy of combustion instead of the entropy of formation, which is just another way of solving the problem. So we have. Let's see, here we have this guy and I can't remember what that iss um all these names are. Heck, Tank, we have obtained. So we have a pep pain and we can figure out the the again we have. Let's see here. I'm gonna go back to 43 year. I can tell you what we actually have. Wait a minute. Wait out here. Oh, I need a flip through the book. Here. Let's see here, Larry. You know, no e went too far. Let's see here. Um, 43. Let's All right. So we have 120% 125% theoretical air and being they're cooled in a heat exchanger to 16. 600 k. All right, so that's the deal. So because we have extra oxygen or extra air, we can again to our component or atomic violences. to figure out that, um, we need this much this many molecules of oxygen, and then coming along with that, would that be that many? This many moles of nitrogen. And so then we get seven per per kill a mole of, um of plantain. We obtain, we get seven killing moles of carbon dioxide, eight kilometers of water, 57 point of 51.7, killing moles of nitrogen. And this excess oxygen is 2.75 killing moles. Now we know our chance for them from energy equation is, um this is the entropy of combustion. So it's just the entropy of the entropy information of the products minus the entropy information of the reactions. And then we also have because of the state is not at the based based state. We have some anthropocene from the The change in state of the gas is of the products. And let's see, here, um, we're assuming that this vapor this water is a gas at the 600 Calvin. So we have the entropy of combustion, plus the entropy, um, change from the change in state. Now we can get this, um, on a Moeller basis. Let's see here. So we know again we can look up the entropy of combustion on a kilogram basis. But to get it in a Moeller basis, we need to multiply by the molar mass of this heh obtain, which we can calculate. Then we have the change change in, Let's see here the change in the increase. And so all of the all of the combustion stuff, the entropy of formation stuff is in here. So now we just need to change stuff and the change we have seven co two's getting the change of state eight waters and 57 57 nitrogen and 275 Oxygen's. And so again, we can look all this stuff up the oops, I forgot. I forgot to put a change in here. So in going from the baseline 25 c 2 600 Calvin, we can figure out what the change in entropy of these different different products are. And I'm plugging everything in and just cranking through the the analysis. We get minus 3842 mega joules per killem, all fuel, and that is exactly what we had in the previous case.

All right. So for this problem, we're looking at this table right here your X and T. And when we have Your Excellency with a 3.7 in 10 out of this equation, T is equal to X minus 1.5. What's playing extra equation to try to find T so on X is three points that we have tea 3.7 minus 1.5. That is important to point you. Now we can put in 10 under. This ingredient of T is equal to X. That's 1.5. In this case, X is equal to tense up T 10 minus 1.5, which is equal to 8.5.


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