Question
The value of the cofactor M3,2 is5 1 2 6 8 4 7 9 3
The value of the cofactor M3,2 is 5 1 2 6 8 4 7 9 3
Answers
Evaluate the matrix expression. $$\left[\begin{array}{rr}4 & 6 \\3 & -7\end{array}\right]-2\left[\begin{array}{rr}1 & 0 \\-4 & 1\end{array}\right]$$
So in the given question we are told to find the world range is the value of the longer rhythm log with base 3 81 of seven nine between. So we have to find a range or the value in between which this algorithm is uh is lying between. Right? So what we can do is we can take the inequality that We have 381 and seven or here. Right? So when we take the cube of seven, what we get is seven Q. Is equal to 343. So we know that 70 of us equal to 743. I mean 343. And when we take seven raised to four, what we get is 1372. So we can write seven tube is less than 381 And 381 is less than 7 to the power food. And now on taking longer than we can write log Number of seven Cube is less than Knob of 381 is less than nod off 7 to the power food. So when we are taking the longer than we are taking longer than with base seven. So now we can write that A property which says long with based A. Of A. To the power N. Is equal to end. And using this property. What we can write is We can write log with Bay seven of 7 Cuba's it 123. And love with Based seven of 7 to the Power four is equal to four. And in the next step we can right Then one x 3 is less than one by long. With May seven of 381 Which is less than one x 4. And the property that we are going to use next is that along with base A. Of B. Yes equal to one by log with base be of K. So using this property We can write that one x 3 is less than one by three. Yes, less than love with base 381 of seven which is less than one by four. So they required grains in between which the value of this dog rhythm comes is the is the range one x 4, less than one x 4 and one x 3. So this is the required range. That is one x 3. One by food. It comes in between one x 3 and one x 4 is the required answer. So in the options in the question we have a few options that give us different grains And the range that is given us one x 3 and one x 4 has option to write. It says that The value of the snow algorithm lies in between the numbers one x 4 and one x 3, which is actually correct. So this is the required answer. I hope you understood the method. Thank you.
Alright. In this exercise, we want to find the minor and co factor and want to find it for em. 32 and a three to. So we're gonna look at our third row second call up and find interment here. So we have m 32 equals. We got one times two, which is two minus negative. Three times 1/2 so minus negative. 3/2. And that's going to equal to plus 3/2. So too, is forward to plus three, which was gonna give us 7/2. Then a 32 is going to equal negative one to the power of three plus two. So five times seven over to Of course, negative. One to the fifth is when a negative one. So if we go down right here, we have the M 32 equals 7/2, while a 32 equals negative 7/2. And that's our solution.
All right. Indiscretion of the relevant given expression. Pull Bless. Five multiplied by six minus three. So first we will might apply it. So five and two sixes. 30 full Lester T minus three, then But I they're to number 30 plus Forrester DeFore minus three, which is equal to 31.
To simplify this expression. Let's start with simplifying the numerator and remember that when you multiply fractions, you multiply the numerator, so one time sixes six and you multiply the denominators four times 11 is 44. So if 6 44th divided by 3/7 another option would have been to start by reducing so you could reduce the four divided by two and the six divided by two before multiplying. Most fractions. Since I didn't do that, I'm now going to reduce my numerator. I'm going to divide the top and bottom by two, and I get 3 20 seconds. Now remember that if you have a fraction divided by a fraction, that's equivalent to the numerator fraction divided Excuse me multiplied by the reciprocal of the denominator fraction. So 3 20 seconds multiplied by 7/3. Again, we're going to multiply. The numerator is and multiply the denominators, but we can reduce first, So divide the three by three on the top. Divide the three by three on the bottom, and that reduces. And now what we have left is 7/22