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~S (in N"I Canaturall 7cumnZ even that Ilc mcta JUUI SU4 | HYLLIM of magnesium Cakulaic tk 4786 Mg-24 (78.99" 7(10 00 * abundunc < Isotnpic n1a * chund...

Question

~S (in N"I Canaturall 7cumnZ even that Ilc mcta JUUI SU4 | HYLLIM of magnesium Cakulaic tk 4786 Mg-24 (78.99" 7(10 00 * abundunc < Isotnpic n1a * chundunc: ~DQ -dcics iolupes: Mg-2S , 23.985 airiu| Mg-23 (11.01 #turJanee; isotopic anEsntyle oftla nctal, and; cobal: in Rok Liatal nokaCacual numbercalcium atotsThe mass of 0.735 Tkes ofN FaIES fir thc followtg compounk~ Give SYStCMC NO: Cch BalOHH OAw (EOZH L 'OS N (

~S ( in N" I Ca naturall 7cumnZ even that Ilc mcta JUUI SU4 | HYLLIM of magnesium Cakulaic tk 4786 Mg-24 (78.99" 7(10 00 * abundunc < Isotnpic n1a * chundunc: ~DQ -dcics iolupes: Mg-2S , 23.985 airiu| Mg-23 (11.01 #turJanee; isotopic an Esntyle oftla nctal, and; cobal: in Rok Liatal noka Cacual number calcium atots The mass of 0.735 Tkes ofN FaIES fir thc followtg compounk~ Give SYStCMC NO: Cch BalOHH OAw (E OZH L 'OS N (



Answers

Calculate the atomic mass for magnesium given the following data for its natural isotopes: $$ \begin{array}{lll} { }^{24} \mathrm{Mg} & 23.985 \mathrm{amu} & 78.70 \% \\ { }^{25} \mathrm{Mg} & 24.986 \mathrm{amu} & 10.13 \% \\ { }^{26} \mathrm{Mg} & 25.983 \mathrm{amu} & 11.17 \% \end{array} $$

Let ER f 24 b The abundance off M G 24 and let F 25 is the abundance off mg Ah 25 and let the F 26 be the abundance off mg 26. Then the entry off the periodic table for the MG is 24 plus 3 +12 is equal to 23.98504 times F 24 plus 24 49 +8584 times F 25 plus 25 49 +825 Mine times F 26. Since there are only three isotopes we can write, F 24 plus F 25 plus F 26 is equal to one we solved for ah F 25 F 26. The second equation gives us ah F 26 is equal to one minus F 24 minus. If 25 we substitute this expression and the F 24 is equal to 0.7899 into the first equation that we have pain so over Expression becomes 24.312 is equal to 23.98504 times 0.7899 plus 24.9 85 feet four times if 25 plus off 25 or 10 +98 259 minus 25.92 5 Mine times 0.7899 minus 25 49 8 259 times if 25 the solution is then f 25 G's, we have 0.9303 Then we can ride F 26 will be than one minus 0.7899 minus 0.0 mine three. They're free. This gives us off this use of 78% which is 0.1171 well off the naturally occuring magnesium off M G 24. Thus, for about a, um, 9.303% off mg 25 and for bond, be 11.71 11.71% percent or off. N. G. M. G. 26. Here you can see 11.71 person for F 26 abundance

Everyone. So in this question they've given naturally offering magnetism is the following isotopic abundance or 24 magnetism 78.99% atomic mass. 23.9850 for the in 23 magnesium 10% abundance. 24.98 for it for as atomic mass 26 mine is um Learn by not one person 25 pine 98-49 is the abundance. What is the average atomic parts of Magnuson and sketch the mass spectrum of Magnesium? So for super right, the given later given me to my kids, atomic myself. Atomic moss of 24 Magnesia. That is equal to 23.98. Are you 04 a young you the next abundance of Baghdad abundance of No 24 Magnesium. That is equal to 78.99%. That is equal to 78.99, Divided by and read and part is equal to .7899. Then I do it myself myself, grandi for you. Magnesium. And that is equal to 24 98584. How you make are you 84? I am you. Yeah then abundance. Self carbon balance of 25 stagnation is equal to 10%. That is equal to 10. The worry by 100. They're difficult to zero plane 01 My next economic myself. No, so 26 magnesium that is equal to 25 points 92 59. Hey um you by next abundance oh mm 25 magnesium that is equal to learn 250.1%. And that is equal to 11.1 divided by 100 At this .1101. That's right. Therefore a bridge the a bridge atomic mass of magnesium magnesium is equal to it's heavy. 23.98504. Them too plane seven names my nine plus. 24.98584 myself. Him too. Nothing. 0.01 plus yeah. 25 points 98-49 To find night into 0.9 0110 one. That is equal to that is equal to Mhm. 24 points please. The role fire to fire you ate. And that would follow testing Therefore the average atomic mass. The outrage. Atomic moss. Oh and consumers. That is equal to 24 bind. Okay. Turkey one a.m. Atomic Mass. Your name. Atomic moss. You need then be five yeah. B. Five mass spectrum of magnesium moss. Spike drum. Yeah of my mission. Yeah. Yeah. Thank you. All right. Well most spectrum of yes like Maceio so we can draw a blood off and we've got one of my passions. That's that's yeah everyone. Yeah. Yeah. Yeah. No that's a we can drive blocked off. Okay percentage intensity against a mass. I'm sorry. I think they say okay A against a moss. So here we can say this is you see it all man Brandy the next or B next six ft next 80 you can say. And they're so this is a percentage in density. Uh huh. For some cash intensity. Okay. Yeah and City Games must have that. Yeah A young man you know. Yeah. Yeah. Yeah that can't be right. You know this uh 20 I sort of 23.98 for you careful reading this. Yeah. They set up. Mhm. Sweet. Let's discretion. Yeah. Right. Yeah. Yeah. So uh this is The one I set up everything there. Mhm. Yeah. Yeah. And okay this was the yeah secondary cycle and then this is yes. Yeah. How would I sort of So uh he compares this produce you can say Sir Magnesium. This is against a magnificent 24. Mhm. Yeah. My mission 24 and C 24. And this is 78.99%. It's uh Marcy is outside. Yeah. Six more Aussies going deep three points. Because yeah We find. 985. Yeah. Yeah. 23 points 98 for you. Mhm. The second I sort of that is you can see it appears only yeah. Pain percent. That is magnesium guarantee for you. Yeah. My guests in 25% is 24 points 98 Okay. 48 yeah. By a The next one is alone find right. 01 magnesium 26. This says 25.98- six. Okay so this is what the mass spec come off magnesium

You know, work on problem 24 from chapter four in this problem, whereas, to calculate the atomic mass of magnesium provided, um, the atomic masses and relative abundance for three, uh, common magnesium face it tooks. So we do this by multiplying the abundance times the isotope mass and adding up for each isotope. So again, for, uh, for the abundance were given in percentage we want to use as a decimal. So you divide by 100. So 79.99% become 0.7999 would multiply it by the ah mass of that isotope, which is 23.985 Then we add this to another isotope which has a 10% abundance, which is 0.10 Uh, at the desk boom, we multiply by the massive this isotope just 24.986 and then finally, the third isotope has an abundance of 11.1% which become 0.1101 This isotope has massive 25.982 And so we multiply and add up here and we get an atomic mass of 24.54 atomic mass units for B uh, atomic man

In this question, Let's first use the information provided to determine the average mass of a mag museum adam. Sure. This is 24.31 times 1.6605402 times 10 to the -24g. And this is going to give us 4.03 uh 677 Times 10 to the -23 g. And from this we can find the number Yeah. Of magnesium atoms. Mhm. in 24 31g. This is equal to 24 .31g times 403 677-10 to the -23g In one Magnesium Adam. Should we make museum there? And this is equal to 6.0-2, 10 to be 23 atoms. And then we use the information provided to find the average mass of an iron atom. Mhm Yeah, iron is 55.85 Times 1.6605402 10 to the -24 g. And this gives us 9-7 4116, 10 to the -23g for the mass of one iron adam. And then we can calculate the number. Yeah. Uh huh. Iron atoms. Yeah. In 50 585g. This is equal to 55.85 g. Yeah. And this is 9-7 411, 6 times 10 to the -23g in one iron adam. And this works out to 6.02 to 10 of the 23rd atoms. So if we look at the two numbers here, let's compare the answers and what conclusions can you draw? So if you look at these two numbers here for the number of iron atoms and the number of magnesium atoms, these two numbers here are actually avocados. Number. It's the number of atoms in one mole. So, knowing this without performing any calculations, how many Atoms do you think would be in 40.070 g of calcium? So the number, yeah, uh calcium atoms. Mhm. In 40.78 g 40.78 g is the molar mass of calcium. This one has same number 6.2 times 10 to the 23 Adams. Mhm.


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