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(10 Pts) The data Tor convex Jcntahot bclotWhat the focal length of the lens?Convex Lens41x+0.5 R? = 1050.04 ! 0.03 0.02 0.010.440.46 0.48 1/do (cm)...

Question

(10 Pts) The data Tor convex Jcntahot bclotWhat the focal length of the lens?Convex Lens41x+0.5 R? = 1050.04 ! 0.03 0.02 0.010.440.46 0.48 1/do (cm)

(10 Pts) The data Tor convex Jcnt ahot bclot What the focal length of the lens? Convex Lens 41x+0.5 R? = 1 05 0.04 ! 0.03 0.02 0.01 0.44 0.46 0.48 1/do (cm)



Answers

A lens has one convex surface of radius $6.00 \mathrm{~cm}$ and one concave surface of radius $10.0 \mathrm{~cm} .$ When an object is placed $35.0 \mathrm{~cm}$ from the lens, a real image is formed $50 \mathrm{~cm}$ from the lens. (a) What is the focal length of the lens? (b) What is the index of refraction of the lens?

We have to find the radius of curvature of convex surface solution here given some value. Is there focal length off your first of all focal land of planning, convex lens Is 0.3 m And Reflective Index. That is the value of musical to seven x 4. So we have to find the value of various so we know that the power of the powerful is very cool surface. It's PS is exposed to P. M plus two p.m. So this is one upon F. S. Is equal to burn upon FM pledged to upon F two. Again We can write this cell burn upon a fairly big push to new -1, one Upon our 1 -1 upon our. So you can see that And this is new -1 and this is one upon art C -1 Upon Infinity. So put the values again. So one upon F. L. Is equal to seven by four minus one and this is one upon RC minus zero and you can see three by four and multiply by but upon arts so this is a value of one upon fl. So we know that the value is and F M is equal to RC upon to. So this is the situation second and this is first and used in their situation. So the value of burn upon Fs is important to to upon artsy plus six upon ford galaxy. So this is the value of putting and by solving this we get F. S. is equal to four upon 14 RC. So the value is mm R. c. The call to 1.05. Meet it. So now this is the value of party So we can see here. The value of art says 1.05 m, and the correct option is zero for 1.05 m and at the.

In this solution we have a plano convex lens. So this is side convex. And this idea is planning and plain aside is silver uh polished by silver. So when light travel from air to convict service then reflected and goes to plan surplus and reflected. And again go to convict starvation reflected. So two times reflection and one times is a reflection. Okay so we calculate equivalent focal and so one divided by capital F equals to one, divide by F. E. Plus when you had by F. M. Plus when you add by F. M. So the F. B. It was too New -1 divided by our bless Dubai infinitive and plus New -1 develop where infinitely because Focal length of plain mirror is infinity. So then we sold and one divide by f equals two who New -1 Divided by Art. Okay question number first where F. Is the focal length of lens and FM of mirror. In buying decisions where to refraction and wonderful action will be take place. So one divide by F. The value of Oakland given by 0.2. So one divided by 0.2 equals two. And refractive index given by 1.5 minus one divided by our So we calculate the value of our then our job was to 0.2 m. And this is our final answer. And this answer. Union option B. So often be. It's correct. Okay

Finland has a convex surface of radius 20 cm and a concave surface of right radius 40 cm. And it's made of glass of refractive index 1.54 compute the focal length of the lens and state whether it is a converging or diverging lens. Okay, So they are, One has a radius of 20 cm and the other has a radius of 40 cm. So both of them have, their curvature occurs to the right. So we can use this in lens equation or the lens maker equation you have won over F is equal to N -1, one over R one -1 over R two. So we're told, and is 1.54. R. one is 20 cm. R two is 40 centimeters. So solving this out for the focal length And you get a focal length of 74 cm. Since it's positive, it's converging.


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