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KnIElcucnCWAlemenlElctnentAnIAemcuB"@o ES " 498 5022CALCULATIONS Sources and #2= Describe the basic difference between the spectrum from the tungsten fil...

Question

KnIElcucnCWAlemenlElctnentAnIAemcuB"@o ES " 498 5022CALCULATIONS Sources and #2= Describe the basic difference between the spectrum from the tungsten filam- ncon g45 source_Sources #3 and #4: Identify the element in source #3 and the element in source #4.Hydrogen gas source: Using equation ( I ) , find values for = and nz that will give the approprian the wavelengths that YOu measured. To do this, rearrange equation ( 1):eq: (3)Substitute the values of 1 that YOu observed into the lef

KnI ElcucnC W Alemenl Elctnent AnI Aemcu B" @o E S " 498 502 2 CALCULATIONS Sources and #2= Describe the basic difference between the spectrum from the tungsten filam- ncon g45 source_ Sources #3 and #4: Identify the element in source #3 and the element in source #4. Hydrogen gas source: Using equation ( I ) , find values for = and nz that will give the approprian the wavelengths that YOu measured. To do this, rearrange equation ( 1): eq: (3) Substitute the values of 1 that YOu observed into the left side of equation (3) and calculate IR: By trial and error substitute values for n , and nz, into the right side of equation (3) un "



Answers

Calculate all the wavelengths of visible light in the emission spectrum of the hydrogen atom. Hint: There are infinitely many wavelengths in the spectrum, so you'll need to develop a strategy for this problem rather than using trial and error.

Okay, so for this question, we're going to use the Rydberg equation, which is shown here, and we're gonna try to find the first two lines with the spectrum. So this would be, um, five dropping to four in six, dropping to four. So five is gonna be the first line in six would be the second line. So from here, we can just plug what we already know in. And, you know, I'm gonna write our which is, um, Rydberg Constant up here. Just so I don't have to keep writing it because it's a little long. So 1.97 times 10 to the negative second is red Berg's constant. So it's going to say one over our wavelength equals R. And then we are given that our m is, um oops. Did not want to do that is four. So four squared minus 1/5 squared. Great. So if you want a positive video and do that little calculation, you should get a wavelength, uh, 415 nanometers, and then we're gonna do the same exact thing for, um, the second line, which would be formed six dropping to four. So one over the wavelength equals R, right? Burt Constant. And then 1/4, the four shown it changed were given that and then minus 1/6 squared. Great. And again, if you're solved for wavelength, you should get 2000 625 nanometers. Great. So now, since we know the weight links, we can use this equation e equals H C over wavelength in order to get our energies. And we know we want it in kill jewels per mole. So we're gonna multiply it by avocados number. Great. All right, so let's start with five. So we know that our wavelength is 4000 and 15 so we're just gonna plug everything in that we know. So we know H is Plank's constant. 6.6 times, 10 to the negative, 34th times the speed of light, which is 10 hoops stunts on when I wanted three to be 8, 10 3 times 10 to the eighth. Sorry of that. And then we know we want to multiply this by Alba God Rose number, which is 6.2 times 10 to the 23rd. Again, I'm leaving out my units, but it's always going to write them. I just don't want him to slow down because I'm kind of slow withdrawing. Okay, then we know that our wavelength is 415 nanometers. All right, this is where things get a little tricky, and we want evaluate what we have. So we know that, right? Bergs are we know that plank's constant is in. Oh, sorry. Not what I wanted. We know that the speed of light is in meters, so we want to make sure that we also have our wavelength and meters in order to do this. Since it's Nana meters, we could just multiply about this by 10 to the negative ninth. That way you want You want to make sure that your unit's always match up, all right? And then you should get by doing that Calculation. 129 0.80 killing joules per mole. Kill it, Jules. Hair more. Sorry. Okay, great. So we're gonna do the same exact thing for our, um our second line 46 year. The only thing we're gonna change and I'll change my color here is that we're gonna change the wavelength, so I'm just gonna go ahead and erase this. And then all we're gonna do is replace this with our wavelength for the second line. So we have to 6 to 5. Sorry, my markers acting up to 6 to 5. And we know that's a nana meter. So we want a multiply it by 10 to be negative nine. And we should get an answer of 45.59 Sorry. My market is not working. 45 point five nine killer jewels per mole. Her more Sorry, It kind of lost it at the end there. And these are both going to be in the infrared region, so I are.

Elements which emit radiation in the visible part of spectrum. The visible region is 400 27 50. No no meter. Founder given this stop animals only. Very. Um Garcia, potassium and saudia. Um It radiation in the visible part of spectrum very um has. We're playing it off 4 55 0.4 nanometers. Go see em this 4 22 17 nanometer, potassium has an wavelength 404 17 nanometers, sodium, something sodium has no evidence of bye 89 169 millimeter. All of this maybe then lies between the visible region. Thank you. B Any man which has this Waveland Bellew will emit photons of highest energy. This is because energy equals two A. C. By linda linda is let them from this equation we get that energy is inversely proportional to paper. The element which has this weapon value is good having we plant off to 67 when six nanometer as the agreement has list Waveland blue will emit photons of highest energy. Similarly elements which have highest wear brand value will emit photons of lowest energy decent. And the agreement is soda. This has highest weapons mandate was to 5 89 0.6 nanometer. So it will emit photons of lowest energy. Next see to calculate the were planned, he is equals to see right linda lbc frequencies is speed them dies. Problem. Therefore linda is equal stupid. See you. Bye. P CDS Cheap foreign zero and 2 10 to the power eight meter past second frequency is given six point right 9-10 to the power 14 seconds. This is equal to zero 45 right. And to 10 to the power -6 meter. This can be do tennis 4 55 Into 10 to the power. My last nine m for the lender is equal to 4 55 And to tend to the for my last nine m. Very um, which is Waveland because to 4 55 when full nanometer is the enemy. Okay. President sample

Any man which emit radiation in the visible part of spectrum visible indigenous 400 who seven. It did nanometer from the given the stop elements on Liberia, Garcia, potassium and sodium. Um It radiation in the visible part of spectrum video. Has they play or 4 55. Fine or nanometer, calcium has 4 22 17 nanometer mainland. 40 cm has 404 17 nanometer. sodium has 5 89 16 nanometer. All of this way. Then drives between the visible region range. Okay. Any man which has this way. Brand value will emit protons of highest energy. And the element is good. Hey you. He says we blend off to 67 16 nanometers. This is because energy is equals to A. C. By linda. The agenda is the weapon from this equation. We can say energy is indirectly proportional. Do that. They plan so gold emmett photos of highest energy. Similarly element which have highest wave land value will emit photons of lowest energy. And the element is sodium which has wavelength of 5 89 16 nanometer, sodium emmett photos. Uh huh. The West energy because it has the highest back there. See to calculate the with them P. Is equals to see by linda here. Based the frequency. See speed. Lambda is weapons. Therefore lambda is equal stew see by P. She is chin to 10 to the power. Eight metaphors. Second. Yeah. And this is given six point 59 into 10 to the power 14th five seconds. This is equal to 0.4 fight. Fight. And you tend to the power when a six m. This can be indigenous. Yes. Okay, this can create an S. 4 55 in 2 10 24. My last nine meter. Therefore lambda is equals two 4 55. No, no we don't. Therefore video. He says movement of 4 55 point Conan zero m. Easter element present in that simple

We are given the following information. As you can see, we've got 10 elements and were given the wavelengths that of the light that they emit when they're burnt first we are asked to determine which elements emit radiation in the visible range. I'm going to highlight those that he met in the visible range. There's barium or just over 400 calcium. There we have four barium calcium, potassium and sodium clips for part B. We were asked which emits the highest and lowest energy. Highest energy will be the lowest wavelength. So that will be gold and our lowest energy will be the highest wavelength. What is squeaking here will be sodium third. We're told that we have a I think I'll go to the next page. We have we burn a substance and we have light of a frequency of 659 Times 10 to the 14th. As to the -1. Which one of these samples without likely be in order to do this. We're going to find the wavelength which is equal to see over new, which is equal. I wrote that wrong, So it'll be equal equal to 2.99, 8 Times 10 to the 8th m/s, Divided by 6.59 Times 10 to the -14. As to the -1. And that equals where did I write my values 4.555 Times 10 to the -7 m. And just because we can do it quickly here, let's convert that to nanometers by multiplying by one times 10 to the 9th And that will equal 4:55 nm. Going back to the other page, we can see that the element that that represents will be berry, um and we're done.


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