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IF b3 = 4, then b" (A) 2 (B) (C)12 (DP16positive [ number and w? = 2, If w is then wB N2 242ve <5023426 78. Ifz: = y', which of the following must be e...

Question

IF b3 = 4, then b" (A) 2 (B) (C)12 (DP16positive [ number and w? = 2, If w is then wB N2 242ve <5023426 78. Ifz: = y', which of the following must be equal [ t0 24+122Ifxis a positive integer such that x9 and * W; which of the following must be equal t0 x13? TW = 1 " + W -M+ 2w

IF b3 = 4, then b" (A) 2 (B) (C)12 (DP16 positive [ number and w? = 2, If w is then wB N2 242 ve <502 342 6 7 8. Ifz: = y', which of the following must be equal [ t0 24+12 2 Ifxis a positive integer such that x9 and * W; which of the following must be equal t0 x13? TW = 1 " + W - M + 2w



Answers

Complete each of the following equations: (a) $_{3}^{7} \mathrm{Li}+? \longrightarrow 2_{2}^{4} \mathrm{He}$ (b) $_{6}^{14} \mathrm{C} \longrightarrow_{7}^{14} \mathrm{N}+?$ (c) $^{27}_{13} \mathrm{Al}+_{2}^{4} \mathrm{He} \longrightarrow ?+_{0}^{1} \mathrm{n}$ (d) $^{250}_{96} \mathrm{Cm} \longrightarrow ?+ ^{98}_{38} \mathrm{Sr}+4_{0}^{1} \mathrm{n}$

Problem. 11 we have the determinant. Okay, equals one. Two. Key To K -1. And Any squared plus en plus two and squared and and squared plus in n squared plus En plus two. And the submission of DK from K equals one to end equals 40. We want to find the value of end. As long as key is only in a column, all in a row. Then we can expressed the submission of decade from K equals one to end as the determinant. And get the submission inside the firm. It's a submission from K equals warm To end of one and the submission From K. equals 1 to end two. K. The submission of K equals warm to end well To K -1. And here we have and Any square plus en plus two in squared and and squared plus in any square. Close and close to. That's a good. This old equals 48 because the submission equals 48. Let's get the submission of N. It's one plus. And here we don't have Okay, we just add 1 10 times. Then the answer is and you have your in and and here We have to 10 times. Then it's two in multiplied by the submission from K equals one to end of Cape. It's one plus N divided by two. And here we have the same. Then we have the same submission as before but We can sell one. Then it's in Blow it by one plus in minus in and we have here and squared. Yeah. Yeah And squared plus in plus two. This is N square the same as here and here and is the same as here. Let's multiply the first column By -1 and added to the 2nd column. Then We have 100 in this is and squared plus in. Yeah, Multiplied by -1. Then added to the 2nd column stoop. Then we have n squared plus in. Then we have in the square zero. Then we have any squared plus in plus two. We can simplify more by multiplying the first column by -1 and added to the third column because this is the same and this is the same. Then we have and zero zero and squared plus in 20 and squared zero and plus two equals 40. Let's expand using the second column Or the 3rd column. That's a good. The second column we must have We multiply too deployed by minus one to the power of I plus J. It's 2-plus 2. Not deployed by the determinant of n. And then plus two. It's and multiply the endless. Too- in squared, multiplied by zero. Then it's minus. It equals minus zero equals 48. Then we have and squared plus two in Equals 24 or -24 equals zero by five factories in this equation we have N plus six. Got employed by n minus four Equals zero. This means and equals six or four. Sorry, it's -6 or four. And this is rejected because And is used in the submission here and of course, and can be negative then And equals four. It's accepted answer. As a result, we choose. Mhm.

Given the following expressions and we need to determine which of these are quadratic. So the first one is written in the correct order those from the biggest exponents of the smallest exponents. So since the biggest exponent is three, so that's cubic. This is not quadratic. Quadratic means that the biggest exponents would be to not quite right. The second one, we need to clean this up. So we're going to first distribute. See that two y squared minus 14 plus three y illegal to six y one. Go ahead and move the six y over Miss one over. Oh, right. Those as two y squared minus three wide minus 15 is equal to zero. So it's written in the correct order. The biggest exponent is too since it's the biggest exponents to the second one is quadratic the third one we're going to distribute, Get rid of parentheses. So you get be a squared minus 33 a zero biggest exponent is again too. So since the biggest exponents to this third one is also Quadra the last one if we do vertical multiplication So we both cried right here. So that's gonna be to see to the third power right there. That's gonna be our biggest exponents since that's our biggest exponents. This is not going to be quadratic. So the first one was not quadratic because it was cubic. The second and the third one were both quadratic because they were both squared. The last one is not quadratic because it's going to be a cubic

Okay, So for apart a given W squared plus seven, w plus 12 is equal to zero. So this is a quadratic equation because it's in standard form after party were given, 60 plus 11 is equal to zero, so this is not a quadratic equation. Rather, it's a linear equation. And then for part C, we have X times When the ex post three Sophie Factor the X to get hopefully multiply the X again X squared plus three X is equal to two. That will be a pod Radic equation. Then Lastly, for Part D, we have k cubed minus four K squared. Plus came on his 15 is equal to zero. This is not a quadratic equation, rather a cubic equation.

In this question is given that one plus X to the power and difficult to a note plus even X less A two x esquire last on a N. X. To the power and hear anything in featured. Then we need to find the value of a not minus two plus airport minus ethics thorn minus here. 102. Let's see how to solve this question substitute X equals two i. In the given equation we get one glass hi to the power and it's called to a note plus even iota plus a Toyota Squire and so on. Yeah, since I squared plus two minus one. Therefore this expression can be written as a not class, even iota -8 and so no substitute X is called to -6. In the given equation we get 1 -1 ordered to keep our end difficult to you're not minus even iota plus a two minus iota to the power to and a thorn. And this will be called to hey no minus even iota -2 and so on. Let's see. Despite equation one and the second question too, Ed the questions one and two we get one plus I oughta be power and less 1 -1 Ought to be power and And this will be close to two A not minus a two and so on. So a not minus A two and so on. Still B equals two, 2 to the power and by two of course and by way for since and recalls to 102 therefore the above a question can be written as they're not minus a two and so on minus a 102. And this will be close to totally power On that and two x 2 of course. 102. Bye bye. Well thins Cause 102 by by four will be close to zero, therefore not minus A two and so on. I minus 802 will be equal to zero and option A. Yeah, he correct answer. I hope you understood the solution. Thank you.


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