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The chemical formula for biotite is K;Mg_AISi;O (OH)z Calculate the coordinator number for KUsing the table identify the positions of the K and 0 ions: Does your pr...

Question

The chemical formula for biotite is K;Mg_AISi;O (OH)z Calculate the coordinator number for KUsing the table identify the positions of the K and 0 ions: Does your predicted value agree with the number of 0 ions surrounding the K ion?canth $ crust are the silicate minerals. The basic building block for the silicate The major minerals in the minerals is the Silica tetrahedron: The tetrahedrons can be arranged in different ways 0 create the various cach of the crystal models listed below; place the

The chemical formula for biotite is K;Mg_AISi;O (OH)z Calculate the coordinator number for K Using the table identify the positions of the K and 0 ions: Does your predicted value agree with the number of 0 ions surrounding the K ion? canth $ crust are the silicate minerals. The basic building block for the silicate The major minerals in the minerals is the Silica tetrahedron: The tetrahedrons can be arranged in different ways 0 create the various cach of the crystal models listed below; place the model in the classes of silicate minerals (Fig; 2). For correct silicate structure group Explain why YOu placed the structure in the particular group:


Answers

The rutile and fluorite structures, shown here (anions are colored green), are two of the most common structure types of ionic compounds where the cation to anion ratio is $1 : 2$ . (a) For $\mathrm{CaF}_{2}$ and $\mathrm{ZnF}_{2}$ use ionic radii, $\mathrm{Ca}^{2+}(r=1.14 \hat{\mathrm{A}})$ $\mathrm{Zn}^{2+}(r=0.88 \mathrm{A}),$ and $\mathrm{F}^{-}(r=1.19 \mathrm{A}),$ to predict which compound is more likely to crystallize with the fluorite structure and which with the rutile structure. (b) What are the coordination numbers of the cations and anions in each
of these structures?

The first thing that we need to do in this problem is draw the shorthand notation off our Cilic eight an ion and the reason why we draw these shorthand notations. And so we can visualize the strength of our anti on meaning that we can see where negative charges are. We can see where electro negativity would move and for a silicate anti on. This is what our shorthand notation would look like. And from the shorthand notation, we could deduce, um, information to draw the Louis structure that corresponds with it. So our Louis structure would look like this for we have three silicon atoms that are bound together by oxygen atoms, and the oxygen atoms coming off of our silicon atoms will have a negative charge. So what this is meaning is that we have electro negativity going toward our oxygen atoms, which is why we draw these shorthand notations and structures so we can see that and we can write a formula for this structure. Remember, we have three silicon atoms. We have a total of 10 oxygen atoms, and we have a charge of negative eight confirming that we have an anti on and now What we need to understand is we're told that we have other atoms in our essentially in our molecular formula and were told Well, what's going to happen to our formula when we add these different atoms in? So let's remember that we have a negative a charge, so we have an anti on on. What we want to do is we want a neutral molecular formula so well neutralizer negative eight charge by adding cat ions specifically will add calcium. And I pardon me, calcium cat ions and copper cat ions and our molecular formula or more complete one will be calcium to copper, too. One silicon atom three. Oxygen's a 10 oxygen's and we'll have to water molecules as well. I hope that this problem helped you understand. Would number one why we use shorthand notation? And now hopefully you can deduce some information on how to draw it and how we control Aw, structure is based off that shorthand notation, and more importantly, now we can understand how we can add an ions and cat ions to form a more complete and neutral molecular formula.

So we're continuing on with the reactivity off the non metals they were taking a look at on how it replaces. It's a half of the silicon atoms in S I 02 So our feldspar is a mixture of minerals metals. So we're looking at the ratio of a out s I That is not 0.5. So we have one on the menu. Her s ice 308 In our also closed, this is a mineral. Whether it's aluminum silicate are potassium metal and therefore the chemical formula for are also close is K A al s I 308

I'm going to work on the main group elements. And what we're focusing our attention on here is to draw out some structure that is the mineral barrel. So this is a mineral that has cyclic silicate and ions. So what we have is long chains of S. I. 04 that our tetrahedron in geometry that are all linked together. And what we have is negative charges on the chain that are balanced by the cattails. So what this would look like is as follows silicon oxygen, silicon oxygen, silicon oxygen, silicon oxygen. And so this changes repeats. That's what the brackets indicate. And on the selic, each silicon we have two oxygen. So we have a single bond. And so if we have oxygen in a single bond that tells us that we have three lone pairs on the oxygen. And to facilitate this, we need a negative charge on the oxygen and the cult Ryan's that are the Catalans. We have to A. L. Three plus, Found three b. E two plus

In this question, we want to draw a portion of the mineral barrel which is a mineral consisting of cyclic silicate. And I'll then we want to verify the empirical formula given. So this is an image of the structure of barrel. So we have cyclic silicate, an ion. So the silica and ions look like this. They are The system of the silicon atom in the centre double bond into an oxygen and then singly bonded to two ox. So you can see that this gives us a tribunal planer molecule. And then we have the beryllium atoms as ions. You can see in the largest structure here, the brilliant is represented by the green green spears. So we have some brilliance that are basically arranged like a triangle in between the cyclic silicate and islands. So if you refer to a large structure, you could see that there is basically a triangle that is In the center of these three cyclic structures here. Then we have aluminum, which is also in between the cyclic silicate structures. So if we were to break it down to show the empirical formula, we basically need to show that we have six of the. It's okay and I on. So you see here we have 123 or five. The picture here. Okay, so in our sketch we would probably want to just depict another one. So if we close up on this, we want to depict six of them. So we can Circle six of these Tribunal Plantar Cilic eight and I on. And then we're going to find three beryllium. Is that are close to that. So so actually if we look at this one we can see we do have the three brilliance. That could be part of the same formula unit as those six silicate and ions. And then we have two aluminum. So we're just going to also include this in the sketch to the two rooms. So if we were to do just a rough sketch then we could probably just draw the overlapping triangles. So we're just going to draw it has shown here. So we're just doing a rough special just show the six triangles overlapping. So we have three on top playing and then very Going to have to here and then another one here. So as long as you're showing six and overlapping like that, that's fine. And then we can also draw in the brilliance. So there are just the three brilliance that we have depicted. And then we have the aluminum. So we can just to pick the aluminum here as well. So the aluminum is going to be bigger than the beryllium because it is to the right period of table. So that would be accurate to draw like that. Um and also we can also draw in the silicon cons. So that would be the silicon atoms in the center of these tribunal planer structures. And we can also draw in the oxygen atoms if we want we don't really necessarily have to because it's just a sketch of the real main point of this is to just depict how this is showing the empirical for me. So if we want, we can also count the auction. And so we have 1234 5 6. So each of these triangles gives us three and we have 123456 triangles, six times 3 is 18. And if we refer back to the empirical formula, that is how much is in the empirical formula. So we don't have to really include the one in the center that's shown here. So this is just going to be what our schedule looks like. And we can also basically just label the atoms to. Um so you can go ahead and do that or use a color coded key like they have here. And that would basically how we would schedule.


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