This is the answer to Chapter 21. Problem number 46 fromthe Smith Organic chemistry textbook. And this problem asks us to predict the products of three reactions. Um And so at first glance, the first thing that I see here is that each of these is the formation of a vinegary agent on then reaction of that vinegary agent with a court Neil compound. Um And so, uh, we should remember from this chapter that, uh the way that the book likes to form vinegary agents here is to react in alcohol. Hey, lied would try fennel phosgene on. Then treat that with beautiful lithium to get to the active Vidic species on. Then react that video species with a carbon compound. And indeed we see for each of these reactions, uh, it's it's literally that it's treatment with trifle phosgene followed by treatment with beautiful idiom, followed by treatment with a cardinal compound. Um, and so each of these products is going to be the out keen formed Bye reaction of the vig made from our starting material, um, and the carbon Neil that is always listed as the third re agent for each of these problems us are bearing that in mind that I'm a pretty much just becomes, ah, filling the pieces type deal. And so one strategy to approach this might be just too right. Um, the algal hey, lied the alcohol group from the alcohol hayride That's going to end up contributing the left half, as you might think of it of the product, um, and then writing Ah, the piece that's going to come from the carbon you'll compound. Um, so like that, uh, and then just just connecting them with a double bond. Um, and so that's one sort of easy way O r shortcut to arrive at these answers here. Once you've identified that, that's the process that that's going on, that it is formation of a video, ge Um and then just ah, video reaction. And so we can do the same thing for each of these one thing to bear in mind if you d'oh choose two approaches this way eyes Just that you're always going to lose. Ah, hydrogen here. Um, so you can see it's ch three ch two in the starting material, but ch three c h in the product here. So that is one thing to just just be mindful of as we solve these next two. And so using that, that same approach be is gonna look like this Eso there's the portion that comes from our starting material, and we can actually write that out of a CH if that makes it easier. Um, And then the portion that's gonna come from our third re agent in this sequence that were given, it's gonna be see age ch to see age too. C six h five c six each five. Um, and we can just connect them with with double bond there. Um and we should also note we're going to get the e and the Z I summer's here, So e n Z um, and of course, in a that's it's not really an issue, since the the right half of the molecule has identical substitue INTs. Um, so easy. You're gonna walk the same. There's not gonna not gonna be a difference there. Um, okay. And then for C, um, it's just gonna be more of the same here. So we're gonna form the video from our starting material and then reacted with this carbon Neil that were given is the third re agent s o following that seem sort of methodology. So, um, here we can just put ch uh, that's easier than just leaving it in. And typical line notation, um, and then we can draw again. The right half that's gonna come from our coward annual compound re Agent three. Here, it's gonna be ch ch two ch two ch three teach to see h two c h three time and again, we're just gonna connect these two by double bond. Um, and again, we should note that here is Well, we're going to see both the e and Z. So, sis and trains stereo chemistry around that double bond. Um, yeah. Okay. And so, uh, again, I think the key to solving this problem is just to look at the re agents and recognize that each of these is the formation of a vig, and then a physical reaction. And then once you've done that, you know that the product of vinegar reaction is always an AL keen. Um, and you know how the two pieces of these molecules his product molecules should be joining up so you can just draw out each piece and then connect them by a double bond. Or however it's easiest for you. Uh, yeah, but so that's the answer to Chapter 21. Problem number 46.