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Coordination number function VIII XI Radius 1.28 124 1,32 1.53 1.16 1.03 0.68 0.54 1.67 1.78 1,26 148 1.06 0.92Tablelmc TuicilAomicElenieng Oxten Sediuu Magnesium A...

Question

Coordination number function VIII XI Radius 1.28 124 1,32 1.53 1.16 1.03 0.68 0.54 1.67 1.78 1,26 148 1.06 0.92Tablelmc TuicilAomicElenieng Oxten Sediuu Magnesium AuITuIUMI Slicon (hlarine Potaseiuml CalciumColor code for crystal You will need refer Table In order Inswvcr the following Allestons specifie crystal models. that mnalc up Ihe models ure color models The balls coded: The color Eodt given Table 2. >our calculations Color Element the ionic ridii for ions in VI coordination (Table Bla

coordination number function VIII XI Radius 1.28 124 1,32 1.53 1.16 1.03 0.68 0.54 1.67 1.78 1,26 148 1.06 0.92 Table lmc Tuicil Aomic Elenieng Oxten Sediuu Magnesium AuITuIUMI Slicon (hlarine Potaseiuml Calcium Color code for crystal You will need refer Table In order Inswvcr the following Allestons specifie crystal models. that mnalc up Ihe models ure color models The balls coded: The color Eodt given Table 2. >our calculations Color Element the ionic ridii for ions in VI coordination (Table Black Mec The chemieal formula for olivine is Mg SiOa Calculale the Grey AMgFs C coordination number for Mg and Si. Robins epg OH blue Ciold Orange Inter[uyer cations of4LO Using the table, identily the positions of the Mg Si, and ions. Count the number of 0 ions around Mg and Si. Do your predicted values agree with the observed values: note of caution: the models are accurate and the predicted values are not always correct: You do need to actually check the model for agreement:


Answers

The coordination number for $\mathrm{Mg}^{2+}$ ion is usually six. Assuming this assumption holds, determine the anion coordination number in the following compounds: (a) MgS, (b) $\mathrm{MgF}_{2},(\mathbf{c}) \mathrm{MgO}$

This question is mostly associated with the crystal field theory. This question describes that there's a certain first order transition metal that forms different colored solutions. Four coordination compounds with this metal have the same coordination number, and when dissolved in water form red, yellow, green and blue solutions. Further experiments revealed that two of the complex ions are para magnetic with four unpaid electrons and two or die a magnetic. So what can we deduce about the four different coordination compounds that are created? Well, according to the Crystal Field Theory, building upon a knocked ahead RL complex, we can have energies of the D orbital's as being split where three of them are lower and energy, and two of them are higher. If the higher energy D orbital's air significantly higher, it can force all of the electrons into the lower energy state. When this occurs, we have all paired electrons, and we have a DIA magnetic species, so this must be occurring for two of the coordination compounds. This often occurs when we have negatively charged Liggins, forcing this greater energy difference with a greater energy difference than higher energy. Photons are absorbed in order to transition an electron from a lower energy state up to a higher energy state. If higher energy photons like blue and green or absorb the molecule, the coordination compound is going to appear more yellow or red. So two of them must be like this where we have negatively charged Liggins and two of them must be like this alot filled or weak field arrangement. In a week field case, we have electrons that could occupy the lower energies up in the higher energy because the higher energy is very close and energy to the lower energy. This results in a maximum number or this can result in a maximum number of four unpaid electrons, which is the case in this problem. So that must mean that this lower energy is low enough to cause two of the electrons that could be paired to be UNP aired higher energy Orbital's. If we have a lower energy hi energy D orbital's, then that means that there's less of an energy transition that occurs, so that means lower energy photons are absorbed. Lower energy photons like yellow and red photons if they're absorbed in the blue and the green light passes through and the solution appears blue and green. This typically occurs when we have uncharged Liggins attached to the metal. So it's likely that we have to negatively charged to coordination compounds with negatively charged Liggins, resulting in a strong field, two of them with neutral Liggins, resulting in a weak field, causing a red or yellow solution in this case and a blue or green solution in this case.

So in this problem, we're trying to figure out something about some coordination. Compounds were given some information to help us, so it's a first row transition metal. All right, so that narrows it down. We have something between basically these. I don't include zinc here because we're actually looking at different colored solutions. Now each has the same coordination number two of the complex ions repair magnetic with four unpaid electrons and the other two our dia magnetic. So if it's pair magnetic with four unpaid electrons, it would have to either be this or that. Now the other two were dia magnetic. Look, something like that. So in this case, we say it's probably gonna be a D six. So if we look at our options, you have iron two. Plus, we have cobalt three plus, and then from there, we know that it forms a range of colors, so that probably means when he had a cobalt compound and we're gonna have four different Liggins cause those Liggins air going to change the Delta e

We no yes radius ratio. And with the radius ratio we can find out the coordination number, ordination number or that given crystals. If the radius ratio is 0.1552 0.225 Then it has coordination number three. If the radius ratio is between 0.225 two, 0.414, Then it has radius ratio four then it has coordination and bird food. If it has Radius ratio between 0.4142, then it has coordination number six. And if a crystal has radius ratio between 0.732 to Europe to one zero, then it will have aid coordination number. So here we have to blisters, one is M do and another is MDS. Now these two any components for these to any component, we will find out the coordination number with the help of this given data. Now radius ratio is given by radius of the Catalan divided by lydia's of that and I so for M G O. That is magnesium. Outside the radius ratio will be the radius ratio will be Videos of Catan here this is 0.65. I'm a strong And radius of an iron, this is 1.40 and get strong, Solving it will be 0.464. So since the since the radius ratio is between since the various nations is goodwin 0.414 two, So it has coordination number for the coordination of what is the coordination of what is six now? For MGS for MGs radius ratio is given by Radius of Quetta inductive 0.65 and a strong radius of an indicative 1.84 Under Strong. So dividing it will be 0.353. So now the value of radius ratio is between the value off radius ratio is bedouin 0.22 size, so 0.414. The coordination and berries food well coordination of berries. So now the correct option will be and option. Mhm. That is 64. So option is correct. 6 4? Yes.

Hello Overall. My name is that Majali in this question we have in the first complex metal armed and here we has to metal under the year we has warm, it'll arm and we want to write They're oxidation state on the coordination number In the first case, that coordination number mystic seditious It is posted history and the coordination number is six. In the second case, we have global and we have manganese Go over to extradition estate is posted history and the coordination number is six mandir eases boasted toe and a coordination is six is the lost one. His oxidation listed is postive story and the coordination number is sakes Thank you.


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