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P?Could solution of equimolar amounts of HNO; and KNQ beused as buffer? Explain_ SoCulcm EONH Gwo/s ayd aud Tle KNO: weak ba Le S0 solulion csould bk Venj aucue Oud...

Question

P?Could solution of equimolar amounts of HNO; and KNQ beused as buffer? Explain_ SoCulcm EONH Gwo/s ayd aud Tle KNO: weak ba Le S0 solulion csould bk Venj aucue Oud 0 ] Qork eONH cuduld need 0 + BLE nuca omo)

p? Could solution of equimolar amounts of HNO; and KNQ beused as buffer? Explain_ SoCulcm EONH Gwo/s ayd aud Tle KNO: weak ba Le S0 solulion csould bk Venj aucue Oud 0 ] Qork eONH cuduld need 0 + BLE nuca omo)



Answers

Write equations to show what happens when, to a buffer solution containing equimolar amounts of $\mathrm{CH}_{3} \mathrm{COOH}$ and $\mathrm{CH}_{3} \mathrm{COO}^{-},$ we add: (a) $\mathrm{H}_{3} \mathrm{O}^{+}$ (b) $\mathrm{OH}^{-}$

Normally we have a weak acid conjugate base system. The ph is expressed by the normal Henderson Hasselbach equation, which some PK and log concentration of the conjugate base of the weak acid. But since we have a weak based conjugate acid system, we have to apply the analog Henderson Hasselbach equation, which relates the P. O. H. To the PKB, and the loss of concentration of the conjugate acid over the concentration of our weak base. So in this case our concentration or a weak base Is 0.50 molars. The concentration of the week asked the conjugate acid Is equivalent to 0.60 molars. And were given information that the PKB Of the week basis equivalent to 3.35. So now we can substitute everything into our equation here. Okay To find that her PO. H is equivalent to 3.43. And since we're interested in in the ph which is the 4th, 14 minus the P O. H, We can find that are ph in this case is 10.57. And this is our final answer. And that's it.

When hydro Nehemiah is added to a solution that contains a feel for two minus in each to peel for minus the week. Based on the solution is H feel for minus. So the hydro knee, um, will react with the HP four to minus and produce H two p 04 minus and water. If hydroxide is added to the same solution, the acid in solution is h to appeal for minus. The hydroxide will react with this species producing HBO for minus and water.

A buffer is a solution that resists any change in its speech when either hydroxide, irons or protons are added. If we add a strong acid on adding a strong acid, the protons are neutralized by a doxy. But hydroxide amine produce It's cool, and that's three I didn't court warning. Chemical reaction is shown over here. Two please in amount off hydroxide. A mine is equal. Duty is in amount. Dorf, Rachel and it's three positive ions on adding a strong acid. So there is change in ph. Violent on on adding a strong base. The hydroxide ions unutilized buying Rachel and it's three. Be fair, And it's too, which this is represented in this equation here. Also amount off at you in this three was it? Divine's degrees is the same as amount off. And it's, too, which in Greece trends there is no no change in the itch

So we're told that we have these two comments. So over here on the left. H o N h two This is a weak acid. Um, we can tell because of this, uh oh. Age group. Is this this Protons in the acidic. So we have a weak acid now on the right. We may be looking cautious is Doesn't look really related. How is this gonna be the contrary it base of this acid? Well, remember this Enter three. My assistant, ionic salt we really have is a choux NH three minus r plus part of me and at a three months. And now that I said this, um, I realized I may be mistaken when I said earlier, but I'm gonna keep this because this is a good learning experience for something that you to watch out for. So in doing this after I've broken apart, that's ionic salt right here. I've seen that. We have a Chouinard three and an a three minus. Now, if we compare h o n h to toe this right here, what we're seeing is that in comparison is that this has an extra proton, which means that really, this right here the H o N H two is a weak base, and this has acted as a and now this is it's contract asked. I'm gonna write C A to be more clear country acid. And now most of brings up a point. I just jumped to what's at the beginning of this formula. The O H. Really oh, alcohol group that's sitting. But don't forget. Look at the whole thing and be ready to realize you might not always be cracked with your initial list. And a shoe is a basic, uh, group. And so the nitrogen has a lone pair that could take a proton. And what that tells us is that we have a weak base and its conjured us. Now with that out of the way, let's talk about how it's buffer. So if we add H plus, which is an acid, we're gonna look friends reacted the base so H o N h two so plus h o N h two will react to form a tro NH three plus. And, um, that's so that that's what it'll uh, making a deal. Combine like that. No, uh, formally, we in water h plus is really h 30 plus. And so then the by product of this is gonna be H 20 But what you really need to know is that the age plus is going to react with the contrary bait with the base in this solution. And now O H minus, which is a base, needs to react with an asset, So H o N h three plus. And so this is going to react to form h o n age too. Take a proton from here and give it over T o h minus so plus water. And that's how this buffers


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