5

Given the following data at 298 KCsHo(g) Hu(g) CHs(g) CHs(g) + 5 0.(g) Co_(g) - 74 HO() C() + 0.(8) C0.(g) Hx(g) '.0.(g) Hod)A-HO =-1246 kJlmolA,HO =.2220 kJmo...

Question

Given the following data at 298 KCsHo(g) Hu(g) CHs(g) CHs(g) + 5 0.(g) Co_(g) - 74 HO() C() + 0.(8) C0.(g) Hx(g) '.0.(g) Hod)A-HO =-1246 kJlmolA,HO =.2220 kJmolA,hO = .393 kJmol4,H" 286 kJmol

Given the following data at 298 K CsHo(g) Hu(g) CHs(g) CHs(g) + 5 0.(g) Co_(g) - 74 HO() C() + 0.(8) C0.(g) Hx(g) '.0.(g) Hod) A-HO =-1246 kJlmol A,HO =.2220 kJmol A,hO = .393 kJmol 4,H" 286 kJmol


Answers

Calculate the standard enthalpy of formation of $\mathrm{CH}_{3} \mathrm{OH}(\mathrm{I})$ from the following data: $\mathrm{CH}_{3} \mathrm{OH}(\mathrm{l})+\frac{3}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CO}_{2}(\mathrm{~g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}): \Delta, H^{e}=-726 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $\mathrm{C}$ (graphite) $+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CO}_{2}(\mathrm{~g}): \Delta_{c} H^{\circ}=-393 \mathrm{~kJ} \mathrm{~mol}^{-1}$ $\mathrm{H}_{3}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{3}(\mathrm{~g}) \rightarrow \mathrm{H}_{2} \mathrm{O}(1): \Delta_{f} H^{\ominus}=-286 \mathrm{~kJ} \mathrm{~mol}^{-1}$

Hello students in this question based on the values of the bond energies given, we have to calculate the entropy of formation for the reaction. So we know that the entropy of formation for the reaction is bond energy of the reactant minus bond energy of the product. Okay so we can write that from the given values. That is the bond energy of the N. N. N. That is 9 41 plus two player by bond energy of the ancient edge. That is 4 36 minus in the product. We will have the bond of N. And N. Which will be the single bond that is having bond energy of 1 59 plus. Former player by bond energy between N and edge that is 3 98. So and help me from here after solving changing and therapy from here after solving is 60 to kill a jewel per mole. Okay so from the given options option B. Here it is the correct answer for the problem. Okay thank you.

Hello students in this question, I'm given three reactions. Okay, first of all I have first reaction carbon graphite. Okay. And uh the combustion reaction of carbon graphite and it is giving us the 02. Okay, so delta edge uh tell before this reaction uh required to minus 3 93.5. Okay. And the next reaction is heads to plus half or two. And it is giving us it's too Okay. And there it is for this reaction is minus 2 85.8. Okay. And the third reaction is C. +02 plus H two. It has given us CH four and two or two. Okay. And delta edge for this reaction is given to be equal to 8 90.3. Okay, let's say this is our first reaction and let's say this is our second reaction and this is our third direction. Okay, so for now from this reactions, what I can do is I can add reaction number one and number three. So I would get carbon grey five plus switch to Giving us Ch four plus auto. Right, so let's say this is a reaction number four. So delta H. For this reaction would become minus 3 93 point uh 3 93.5 plus 8 90.5. Okay, so this would be 4 96.8. Okay, now we will multiply the reaction number two with two. And then we'll add uh that reaction with the action number four with this reaction. Okay, so I would get this reaction carbon graphite which is the required reaction carbon graphite is taking up two hydrogen molecules and it is giving us see it's called. Which is the required reaction. Okay, so Delta Edge would be 496, my mind 8 -2 times the tilapia of second reaction. That is 5 71.6. So this would be -74.8 kg. So this will be my answer. Thank you.

Question. We are given that the Ben joke as it was a C. Six H. Five F. C. O. S. In solid state plus 15 by two or two which is engages from their forms seven C. +02 gas plus three H +20. In liquid form and liquid form. Now changing. And tell P. For this reaction. That will be sigma delta edge for the products, the changing and help you of the products minus change in and help of the reactant reactant. Here we have these are the two products and these two are the reactant. So we can right here we have 702. So four C. 02. It will be seven multiply changing and help you up. So 2 -3 93 plus the changing and healthy for us to is minus +286. And here we have three years to three multiply minus +286. So this will be the change in And help you of the product minus changing and help you of the reactant will be changing and help you of the banjo weak acid plus zero is changing and help you of the oxygen. So here we get minus 3 to +01. Kill a jew. Kill a jewel. Now we are going to find the heat of combustion of Benji Kassid. So we are going to find delta E. That will be equal to delta H minus delta and G. R. T. Here delta and G. Is equal to look at the reaction here we have uh 702 and 15 by two or two. These two are in the geishas home, so seven minus 15 by two that comes out to be minus one by two minus one by two. So put the values here, delta equal to delta, h minus 3 to 01 minus delta, and G is minus one by two. And our is uh 8.8 point 314. It isn't jewel. So if you want to convert in kill a jewel Permal, then we will divide by 1000. Multiply, T is 300 we get minus 32 double zero, approximately minus 32 double zero kg jule. So in the given options option we will be the right answer.

Question. We are given that the Ben joke as it was a C. Six H. Five F. C. O. S. In solid state plus 15 by two or two which is engages from their forms seven C. +02 gas plus three H +20. In liquid form and liquid form. Now changing. And tell P. For this reaction. That will be sigma delta edge for the products, the changing and help you of the products minus change in and help of the reactant reactant. Here we have these are the two products and these two are the reactant. So we can right here we have 702. So four C. 02. It will be seven multiply changing and help you up. So 2 -3 93 plus the changing and healthy for us to is minus +286. And here we have three years to three multiply minus +286. So this will be the change in And help you of the product minus changing and help you of the reactant will be changing and help you of the banjo weak acid plus zero is changing and help you of the oxygen. So here we get minus 3 to +01. Kill a jew. Kill a jewel. Now we are going to find the heat of combustion of Benji Kassid. So we are going to find delta E. That will be equal to delta H minus delta and G. R. T. Here delta and G. Is equal to look at the reaction here we have uh 702 and 15 by two or two. These two are in the geishas home, so seven minus 15 by two that comes out to be minus one by two minus one by two. So put the values here, delta equal to delta, h minus 3 to 01 minus delta, and G is minus one by two. And our is uh 8.8 point 314. It isn't jewel. So if you want to convert in kill a jewel Permal, then we will divide by 1000. Multiply, T is 300 we get minus 32 double zero, approximately minus 32 double zero kg jule. So in the given options option we will be the right answer.


Similar Solved Questions

5 answers
Part AWhat is the magnitude of the electric field at a point midway between a 6.8 pC and a +7.8 /C charge 8.0 cm apart? Assume no other charges are nearby: Express your answer 'using two significant figures:E =ValueUnitsSubmitRequest AnswerPart BWhat is the direction of the electric field?toward the positive chargetoward the negative chargeSubmitRequest Answer
Part A What is the magnitude of the electric field at a point midway between a 6.8 pC and a +7.8 /C charge 8.0 cm apart? Assume no other charges are nearby: Express your answer 'using two significant figures: E = Value Units Submit Request Answer Part B What is the direction of the electric fie...
5 answers
351045-Kuaddjoul/ ZZilr? Iow/mx 09 "pIIow/mx ZvlpIow/(4 0911low/fx 28- iel "uo 1al3sS! uoioeaj 3513424 341 J04 K6uau3 uohleniipe 241 "Iow/ma 091 pue Iow/mi 28 Jo K6jau? uonenide ue Se4 4o42e3i Kueluauu3i: HM Suoinoead Neiuawai] 4e84
351045-Kuadd joul/ ZZilr? Iow/mx 09 "pI Iow/mx Zvlp Iow/(4 0911 low/fx 28- iel "uo 1al3s S! uoioeaj 3513424 341 J04 K6uau3 uohleniipe 241 "Iow/ma 091 pue Iow/mi 28 Jo K6jau? uonenide ue Se4 4o42e3i Kueluauu3i: HM Suoinoead Neiuawai] 4e84...
5 answers
Duano Nncton Cpratonted Dy to proph 0l Ine linay= Ir) mo Igua
Duano Nncton Cpratonted Dy to proph 0l Ine linay= Ir) mo Igua...
5 answers
Question 9A wheel of diameter 0.70 m rolls on the floor without slipping; with its center moving forward at 1.0 m/s What is the rotational speed of the wheel?(type the answer without any units XX format)
Question 9 A wheel of diameter 0.70 m rolls on the floor without slipping; with its center moving forward at 1.0 m/s What is the rotational speed of the wheel? (type the answer without any units XX format)...
5 answers
11. Provide the reagents necessary to carry out the following conversion_ OH12 Provide the reagents necessary to carry out the following conversion
11. Provide the reagents necessary to carry out the following conversion_ OH 12 Provide the reagents necessary to carry out the following conversion...
5 answers
Q} Gaseoi5 heivm is in Stelage tank w i {h ve(vme 0 F 50 |iters andatempexa(vre oF 25 = The pressure iS 40 afm, Assumc thaf helivm is an ideal jasnlhal i > the number OF mte(es 2 F He Present in the tank? 4)Vak/2 79 opened and t J*s is (56 b) &lhen tic tnermly revers ;1y sXpenedto 1 ~'mosphare, and Finathe Wotk done b4 Jas.
Q} Gaseoi5 heivm is in Stelage tank w i {h ve(vme 0 F 50 |iters andatempexa(vre oF 25 = The pressure iS 40 afm, Assumc thaf helivm is an ideal jas nlhal i > the number OF mte(es 2 F He Present in the tank? 4) Vak/2 79 opened and t J*s is (56 b) &lhen tic tnermly revers ;1y sXpenedto 1 ~'...
5 answers
Coiee anmung Irom conic ) idel Inlo culindncr coe CECC Complcle pants (a} and (D):ore inmntstponeng whcn 70 cotco Fhe conuIa*n 00ia7Im / Inin Raund Geimg 5eeneCeeenHovhaleJevehnune cord Lallina ton?[nnededTardhn
Coiee anmung Irom conic ) idel Inlo culindncr coe CECC Complcle pants (a} and (D): ore in mntst poneng whcn 70 cotco Fhe conuIa*n 00ia7 Im / Inin Raund Geimg 5eene Ceeen Hovhale Jevehnune cord Lallina ton? [nneded Tardhn...
5 answers
= Tnuz =u3tn 20
= Tn uz = u3 tn 2 0...
5 answers
Uhch Hhc ~follouing NOT propesty einef soluzats Micsl 0i highly Flmable normally uataclive oiola Etars 6as4> incompa #ible fadicd Commionly nscisk 74h Iac( 6oits Finis IRcic mclecu 6) relatiely kigh A2ghis_hcinn 5*0| 4620c4 (PF produet Fofifd Mykeo 'Pvra Pvriot AfcniA| 8tterConr? Milute Mxtc asic #jatett (2) = coliioaL( Ls)TsciToet Meai/es Collonirg 418 atab Zan alueers
Uhch Hhc ~follouing NOT propesty einef soluzats Micsl 0i highly Flmable normally uataclive oiola Etars 6as4> incompa #ible fadicd Commionly nscisk 74h Iac( 6oits Finis IRcic mclecu 6) relatiely kigh A2ghis_ hcinn 5*0| 4620c4 (PF produet Fofifd Mykeo 'Pvra Pvriot AfcniA| 8tterConr? Milute ...
5 answers
1. In a clearly labeled diagram, show the effect of a decreasein the return to skill in the origin if the origin has higherreturns to skill than the destination (both initially and finally,but the relative return to skill in the origin shrinks), andindicate your answers to the questions below.Immigrantsare: Positivelyselected NegativelyselectedThe number of immigrantswill: Increase Decrease NotchangeImmigrants will become (pick 1 of4): More
1. In a clearly labeled diagram, show the effect of a decrease in the return to skill in the origin if the origin has higher returns to skill than the destination (both initially and finally, but the relative return to skill in the origin shrinks), and indicate your answers to the questions below. I...
5 answers
Psview Congtanbs PencoYoj May want to reforonce (Page) Scction 14.6 while camnlelina Ihis pnooeM_Calculate Ihc tpiowina [HsOeach * utp given Ihe JOH valuerIOH ] 3-6*10 Express your angwer usingdeclmalplacesAEq
Psview Congtanbs Penco Yoj May want to reforonce (Page) Scction 14.6 while camnlelina Ihis pnooeM_ Calculate Ihc tpiowina [HsO each * utp given Ihe JOH valuer IOH ] 3-6*10 Express your angwer using declmalplaces AEq...
5 answers
+-RNAanti-codonm-RNA edonDNAMn
+-RNA anti-codon m-RNA edon DNA Mn...
5 answers
Find the local maximum and minimum values and saddle point(s) ofthe function. If you have three-dimensional graphing software,graph the function with a domain and viewpoint that reveal all theimportant aspects of the function. (Enter your answers as acomma-separated list. If an answer does not exist, enter DNE.)f (x, y)= x2 + xy + y2 + 4y
Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software, graph the function with a domain and viewpoint that reveal all the important aspects of the function. (Enter your answers as a comma-separated list. If an answer does not e...
4 answers
A previous study estimated the value of p tobe 0.21. Find the minimum sample sizerequired to ensure that yourestimate (ˆp)(p^) will be within 0.025of p with 99% confidence.IMPORTANT: Use a critical value that you foundwith your calculator (not from a table), and round it to 3places after the decimal point before youplug it into a formula and perform your calculations. Do notround-off anyother intermediate results.
A previous study estimated the value of p to be 0.21. Find the minimum sample size required to ensure that your estimate (ˆp)(p^) will be within 0.025 of p with 99% confidence. IMPORTANT: Use a critical value that you found with your calculator (not from a table), and round it to 3 places afte...
4 answers
Non-disjunction is when homologous chromosomes or sisterchromatids fails to properly separate during cell division. Whatcould happen in the offspring of a diploid animal that experiencednon-disjunction of chromosome 4 in its germline cells?
Non-disjunction is when homologous chromosomes or sister chromatids fails to properly separate during cell division. What could happen in the offspring of a diploid animal that experienced non-disjunction of chromosome 4 in its germline cells?...
5 answers
Question 4 (1 point) Which product(s) could form in the following elimination reaction?CH3DBNCHsCHzC.A and BO)AB
Question 4 (1 point) Which product(s) could form in the following elimination reaction? CH3 DBN CHs CHz C.A and B O)A B...

-- 0.022786--