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4. Caleulate the vapor pressure lowering of solution of 2.00 g aspirin (Mr 80.15 g/mol) in 50.0 g methanol (CH,OH) at 21.2 "€. Pure methanol has vapor pr...

Question

4. Caleulate the vapor pressure lowering of solution of 2.00 g aspirin (Mr 80.15 g/mol) in 50.0 g methanol (CH,OH) at 21.2 "€. Pure methanol has vapor pressure f 101 torr at this temperature_ What is the minimum concentration of ethylene glycol (HOCH,CHOH) solution that will protect the cooling system from freezing at 0,00PF? Assume the solution is ideal.) ^ 0.30 M solution of sucrose at 37"€ has approximately the same osmotic pressure as blood. What is the osmotic pressure of bloo

4. Caleulate the vapor pressure lowering of solution of 2.00 g aspirin (Mr 80.15 g/mol) in 50.0 g methanol (CH,OH) at 21.2 "€. Pure methanol has vapor pressure f 101 torr at this temperature_ What is the minimum concentration of ethylene glycol (HOCH,CHOH) solution that will protect the cooling system from freezing at 0,00PF? Assume the solution is ideal.) ^ 0.30 M solution of sucrose at 37"€ has approximately the same osmotic pressure as blood. What is the osmotic pressure of blood?



Answers

Calculate the vapor pressure at $35^{\circ} \mathrm{C}$ of a solution made by dissolving $20.2 \mathrm{~g}$ of sucrose, $\mathrm{C}_{12} \mathrm{H}_{22} \mathrm{O}_{11}$, in $70.1 \mathrm{~g}$ of water. The vapor pressure of pure water at $35^{\circ} \mathrm{C}$ is $42.2 \mathrm{mmHg}$. What is the vapor-pressure lowering of the solution? (Sucrose is nonvolatile.)

Chemistry. And so we have the major component of the solution. This is identified as the solvent. And we often find out this will be in the same phase as the solution and the minor component. So we can have one or more. These are identified as the sole cute. So here we're looking at collaborative properties and these are the properties of solutions and mixtures that depend upon the concentration. So they do not depend on which sold it is added to the pure substance. For example, we can have the freezing point depression, boiling point elevation, vapor pressure lowering and osmotic pressure. So here's what we have is the following equation. So we have delta P. So that's the formula for vapor pressure lowering. That's equal to I. P. A. Star XB. So here the eyes is the number of irons. And then when we have P. A. Start, this is the vapor pressure of the pure solvent and XP is the mole fraction of the salt lake. So here we can fastly calculate the number of moles of 24.8 g of sucrose, so and be is equal to 9.9725 moles. And then we can calculate the number of moles of 17.1 g of sucrose. So that's an A. It's equal to 3.89 moles. So the mole fraction of sucrose, that is XB. That is equal to N. B. So that's not points, not 7 to 5, divided by 9.97 to 5 at 3.89 So what we get is not point not one A three. So then we can go back to our equation for delta P. So that is equal to 11 I are multiplied by 42 point to miller meters of mercury, multiplied by 9.9183 The value we just calculated to get 9.772 millimeters of mercury.

Let's calculate the vapour pressure. The solution. Here we have 17 grams of Yuria in 100 milliliters of methanol. So let's find the moles of Yuria. What we call the 17 grams molar mass is 60 grams per mole. Miss would yield, uh, point 283 moles of your area. Let's find the mass of the C H three to H the methanol. We have 100 mill leaders, and its density given to us is 0.792 grams per milliliters of this would yield 79 0.2 grams on Let's Find the Moles C H 30 H, which is 79.2 grams. Moeller Mouse. The methanol would be 32.0 grams per mole, so 79.2 divided by two 2.48 moves. Now let's find the mole fraction of methanol, which will be, uh, 2.48 Smalls, divided by 2.48 Smalls plus 2.283 moles. So are more fraction. Here will be port, more fraction work. So to be point, eat nine eight and the vapour pressure. The solution, um, is more fraction of methanol on paper pressure Ah, which would be equal to 2.898 times 95.7 millimeters mercury and are vapor pressure. The solution works out to be 85.9 millimeters of mercury.

So a pond. Mm be professional. Mhm of build H two at 70/50 years is 2 33.7. You're right. Um Let's find the mole fraction first. So malls is equal to 25 g of glycerin divided by molecular moss Which is equal to 0.38. Move right so so this one was for blistery. Now we'll calculate moles for water which is wondering you find grounds, divide and bias 18.02 g or more. 2026 2094 moles. So this movie 6 90 6.94 millions of water divided by six point 94. It's an old 10 plus 0.38 Multiplied by pressure to 33.7 doors. The same people do 21.6 two. When you go on to the next spot we have to find the vapor pressure pictures intelligent. He eight divided by the not. Right. So it's C- 286 and two is equal to it. Thanks delight in my 100 seven bridges. We did find one. So now you have one in two Can do about three g of c. two which vice in which Driving by 46 times 37 grounds Or move which is included. 21.7 million of seating pitch fight or rich. And now we're being the worst being tried to calculate See to it 682. So let this will be more Sleep to F six or 3. Let's follow this way just so that I know because we still be wide Plus 21.71 which will be photo. Okay so this will be good to you to find one equals y. or boy. What? I was 21.71. So as you will find one 21.71. That's why Little Fun. one Night Last 2.171 Costa Y. Therefore 0.9. Why did you go to 2.171. Why is this building 2.4 one more Of people at 6:40. Now we have to have a little mass. This will be most of Seti at 603. Multiplying by six student currently was seven rounds. One more 1. 15 rounds of C. Six F six. We'll see Figure X six Open.

So we have these various solutions, and we want to calculate their osmotic pressure at 20 degrees C and the equation. Poor osmotic pressure. If you're working with a property that is defined by the mathematical equation, always begin by writing that equation. First, solve it for the unknown. Here the unknown is asthmatic pressure, so it's already solved for the osmotic pressure. And we have 2.39 Moeller methanol Now methanol is a an elect, a non electrolyte eso. When one mole of it dissolves, we get one mole of methanol a que eso. There is no factor to take into account there, so it's just really a matter of multiply the molar ITI, which I've written as balls per leader because units have toe work any time you use are the ideal gas constant. Got to be sure that you're using the same units that air in it, and I am using moles and leaders and tell Vince and so I will get units of pressure for my answer and multiplying that out. That is incredible. 57.5 a. T. M. That is a tremendous amount of pressure. That's one of the reasons why osmotic pressure is so useful is it doesn't take a very concentrated solution to give quite a bit of pressure, and one can detect to that then. So now I'm not going to do the be part. I'm going to tell you, though, that that 9.45 million Moeller magnesium chloride give you 9.45 million Moeller magnesium ion plus 18.9 Billy Mohler chloride ion because you get two moles of chloride for each mold of the compound to dissolves and one mole of magnesium. And so when you go to plug in the polarity into the, uh, osmotic pressure equation, you need not to plug in 9.45. But let's see, that's 27 28 0.35 and that's Millie. So times 10 to the minus three Moller And other than that, you will work to be part exactly the same as the A Now in the sea part. We're given the volume of glycerol that was mixed with enough water to make 250 milliliters of an inquiry a solution, and so we've got to use the density formula. Multiplying both sides by V gives me the d V equals mass. Take the given density and multiplied by the 40 milliliters, and you have got 50.6 grams of that Ah bliss role C three h 803 Now we need molar ity if we're going to calculate osmotic pressure the way we did in part A And so we need to know not how many grams but how many moles that is. So I have calculated the molar mass of the glycerol and converted the grams to moles of glass raw and to get the polarity. Then I take that number of moles divided by the total volume of the solution. And now I finally have the polarity, as in part a Ah, here we have, Ah, a non electrolyte. And so it's just by equals MRT essentially the same as people War 2.1 98 Moeller. We're going to get a very similar answer. 0.8 to 1 leader atmospheres Permal, Calvin and they're all a 20 degrees. So to 73 to 93 Kelvin's. This is temperature. There is no equation and science where temperature can be anything other than Kelvin's Delta T change in temperature can be in a unit you want Fahrenheit Celsius, Whatever. Um, but, uh, and again that agrees with what we have tohave for units to cancel after have the same units as or that's 0.8 to 1 again, a huge 52.9 a. T. M's. That is a huge pressure. D will be essentially the same. You just have to convert the grams of calcium chloride, two moles and, uh then then you will be essentially at this point, just divide the moles by the volume, you'll have the polarity plug that polarity into the osmotic pressure equation.


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