So we have these various solutions, and we want to calculate their osmotic pressure at 20 degrees C and the equation. Poor osmotic pressure. If you're working with a property that is defined by the mathematical equation, always begin by writing that equation. First, solve it for the unknown. Here the unknown is asthmatic pressure, so it's already solved for the osmotic pressure. And we have 2.39 Moeller methanol Now methanol is a an elect, a non electrolyte eso. When one mole of it dissolves, we get one mole of methanol a que eso. There is no factor to take into account there, so it's just really a matter of multiply the molar ITI, which I've written as balls per leader because units have toe work any time you use are the ideal gas constant. Got to be sure that you're using the same units that air in it, and I am using moles and leaders and tell Vince and so I will get units of pressure for my answer and multiplying that out. That is incredible. 57.5 a. T. M. That is a tremendous amount of pressure. That's one of the reasons why osmotic pressure is so useful is it doesn't take a very concentrated solution to give quite a bit of pressure, and one can detect to that then. So now I'm not going to do the be part. I'm going to tell you, though, that that 9.45 million Moeller magnesium chloride give you 9.45 million Moeller magnesium ion plus 18.9 Billy Mohler chloride ion because you get two moles of chloride for each mold of the compound to dissolves and one mole of magnesium. And so when you go to plug in the polarity into the, uh, osmotic pressure equation, you need not to plug in 9.45. But let's see, that's 27 28 0.35 and that's Millie. So times 10 to the minus three Moller And other than that, you will work to be part exactly the same as the A Now in the sea part. We're given the volume of glycerol that was mixed with enough water to make 250 milliliters of an inquiry a solution, and so we've got to use the density formula. Multiplying both sides by V gives me the d V equals mass. Take the given density and multiplied by the 40 milliliters, and you have got 50.6 grams of that Ah bliss role C three h 803 Now we need molar ity if we're going to calculate osmotic pressure the way we did in part A And so we need to know not how many grams but how many moles that is. So I have calculated the molar mass of the glycerol and converted the grams to moles of glass raw and to get the polarity. Then I take that number of moles divided by the total volume of the solution. And now I finally have the polarity, as in part a Ah, here we have, Ah, a non electrolyte. And so it's just by equals MRT essentially the same as people War 2.1 98 Moeller. We're going to get a very similar answer. 0.8 to 1 leader atmospheres Permal, Calvin and they're all a 20 degrees. So to 73 to 93 Kelvin's. This is temperature. There is no equation and science where temperature can be anything other than Kelvin's Delta T change in temperature can be in a unit you want Fahrenheit Celsius, Whatever. Um, but, uh, and again that agrees with what we have tohave for units to cancel after have the same units as or that's 0.8 to 1 again, a huge 52.9 a. T. M's. That is a huge pressure. D will be essentially the same. You just have to convert the grams of calcium chloride, two moles and, uh then then you will be essentially at this point, just divide the moles by the volume, you'll have the polarity plug that polarity into the osmotic pressure equation.