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Wnat DNA the comt seement = 'plimcntaty 1:5 D140 DNA nu Tath Segment 2: = TACCTGGGACTGCTT Lntnt? Transcribe TTGGCGTAACGTAAG DNA each segment - 1: 5' thes...

Question

Wnat DNA the comt seement = 'plimcntaty 1:5 D140 DNA nu Tath Segment 2: = TACCTGGGACTGCTT Lntnt? Transcribe TTGGCGTAACGTAAG DNA each segment - 1: 5' these " DNA " DNA segmentsE TACCTGGGACTGCTT _ into an Segment = mRNA 2: 5' strand Use: TTGGCGTAACGTAAG-?' the previous - Amino acid mRNA sequence sequences determine the amino Amino acid Acid sequences sequenceuensue Hep AlG U C 0 U G U 9 Crc) Arg (R) G JPW; A C U Ser (5) C Lys (K) UlGlA oceplel-Suil Slop

wnat DNA the comt seement = 'plimcntaty 1:5 D140 DNA nu Tath Segment 2: = TACCTGGGACTGCTT Lntnt? Transcribe TTGGCGTAACGTAAG DNA each segment - 1: 5' these " DNA " DNA segmentsE TACCTGGGACTGCTT _ into an Segment = mRNA 2: 5' strand Use: TTGGCGTAACGTAAG-?' the previous - Amino acid mRNA sequence sequences determine the amino Amino acid Acid sequences sequence uensue Hep AlG U C 0 U G U 9 Crc) Arg (R) G JPW; A C U Ser (5) C Lys (K) UlGlA oceplel- Suil Slop



Answers

The base sequences in mRNA that code for certain amino acids are
Glu: GAA, GAG
Val: GUU, GUC, GUA, GUG
Met: AUG
Trp: UGG
Phe: UUU, UUC
Asp: GAU, GAC
These sequences are complementary to the sequences in DNA.
a. Give the corresponding sequences in DNA for the amino acids listed above.
b. Give a DNA sequence that would code for the peptide trp–glu–phe–met.
c. How many different DNA sequences can code for the tetrapeptide in part b?
d. What is the peptide that is produced from the DNA sequence T–A–C–C–T–G–A–A–G?
e. What other DNA sequences would yield the same tripeptide as in part d?

And this question were given some code ions that code for certain amino acids and no more in A and were asked to give the corresponding sequences Indiana for part. So these are all the M r and A sequences, and we're going to draw the right down the corresponding DNA pairs. So the only difference between Arnie and DNA is that Arna uses you instead of tea. So you Oops, wise my pen working you. There we go. You becomes t in DNA. So here we have g a. So jeepers with C and a pairs with t. So C T t and then g a g becomes C T C now for availing here g you you So this becomes see and then you, um, is based is the up the same thing is t will not the same thing but the replacement for t. So what base pairs with a So see a is our bass player here and then we have C A, g, C a, you and C A C form a thiamine. We have t a c and then we have a C c and A A g. And then down here we have C T A and C T G. So those air over D and a corresponding pair or sequences and then part be asked for a Danny sequence that would code for the peptide. Um, but for this pep side here, so the first one would be a C C. And then the next one. If we look for this, was right here. There's two options here, so we'll just pick one. So it's a C T t. And then next we have again two options. So let's say a and then last one, there's only one option, so Ta c. So there is our, um, sequence for that peptide. And then part C asked how many different DNA sequences could code for that peptide. So there were four positions in that peptide for the first position. There's only one possibility for the second one. There were two possibilities for the third one. There were two possibilities, and for the fourth one, there was one possibility. So that's a total of four. So one times, two times two times one is for So there were three other peptides that could have coated for Besides the one that we drew three other sequences. And then Part D asks, What is the peptide that is produced from this DNA sequence here? So ta c t a c c t g a a g So ta c Issa viney c T g is, that's and then a g is finality. So that is our try peptide and then party asked what other DNA sequences would yield the same type up tight as Part D. So again, we have three positions. So from a fining, we have only one option for the second one. We have two options, and for the third one, we have two options. So it's a total of four. So again there is three other sequences that could yield the same try peptide, um, as the one that we have above.

Uh, this problem gives us a few different amino acids here and tells us what the, um I'm are in A codes are for them and then the part A assets to give the corresponding sequences Indiana for each of the ones that they give us. So, um, remember that G pairs, Let's see, And then a pairs the tea and you'll notice there no teas and these that there are use on. And so India Day We used timing, but an or in a diamond is replaced with your cell, which is you. So a also pairs with you. So starting with the 1st 1 here G a a so g is see and then a turns into t indiana, So C t t um and then the 2nd 1 The second version of this amino acid is G A G so B C T c for failing, which is next. We have g u u So g turns into C, and then you turns into a sea of C A G. You see becomes C a g with its pair, um, and then g u a g become See you becomes a a becomes T in DNA and then g u g, we have C A C is our compliment or finding, which is next We have a you g So a becomes t Indiana, you becomes a and G become see for trips A fan you g g So you becomes a G becomes C So a cc fennel Allan e which is next you you you becomes a you. You see, we have a from the use and then see becomes G for G a u G becomes see a becomes T um, and you becomes a and then g A C G becomes see a becomes T and C becomes G. So C T g um and then part be asked us to give a DNA sequence of a code for this peptide here. So first, we have trip to fan. So that is right here. We just coated that for a C C. Um, and then read it like this, actually. Okay, C c. And then for the next one, we coated two different options here, so each one will work. So I'm gonna use C t. T. So there's two options for this 11 option for this one professional Allen and we also had two options. I'm just going to use the 1st 1 which was a a a and the informant buying in the only had one option, which was t a c. So there is our code for part B, but part see, it asked how many different DNA sequences can cold for that peptide. And so that's why I wrote these little numbers above here. So there was one option for the first part, Um, and then two for the 2nd 22 for the third and one for the first. So there is one possibility, or the first, uh, code on to the second coat on to third coat on and one for the fourth code on. So we multiply all those together, we get a total of four. So there's four different sequences that could code for that same peptide on. And then port de asked us what peptide is produced from this DNA sequence. So ta see, Let's go find that in decoded. So TC is defining t g a. Let's find that in here. Oh, sorry, C T G. Oh, my gosh. I've read that wrong. C t g is right here. And then a G's or last one, that is, uh, final tally. So there is our three amino acid code there, and then party asked what other DNA sequences feel the same truck outside as party. So, um, tiny has one option. Um, the next one has two options, and the next one has two options as well. So one times two times two is four. So there's four, um, total options for that. So three other DNA sequences would give us that same trip outside.

Um, the sequence off the m r and a molecule that is synthesized from the Janus. Try and having the sequence. $5. 80 c g t a c C g T T A three is five. You a a c g u a c g you tree. Um then according to the genetic codes in in just given Strand yeah, a u G three the immunized sequence starting from five days and that are encoded in the base sequence off M Arna are u b r o S c r S p They are B and M e Dean thirties in a self free protein synthesizing system that does not require require Ah, start code on I start, go down the see Gwynn's the sea grants off Paulie Pep died that is formed that is formed on addition mhm off poorly You you a c is poorly. L u tell you the h r Do you like our

This question involves the topic of base pairing and the general process of transcription. First. Let's see about about base pairing. Remember that you have for D. N. A. You have four naturally no spaces adding. Okay, You have one in, you have cytosine and you have saving for R. N. A. For any type of RNA. The only difference is that instead of timing you have in your arsenal. Okay, that's the only difference. Now. Remember that happening piers with timing or your asylum case of RNA and wanting bears with cyrus in. Now let's talk a little bit about. A DNA. DNA is made of two cents. Okay, this is going to stand and this is the other stand. It just has a name. For example, I suppose this instant is the cold instant according to stand and this is the template strand. The coding strand is called like that. Because when this DNA undergoes the process of transcription, it means the process by which uh M. R. N. A. Is produced. The M. R. Name is going to have the same nucleotide sequence than to the coding standards A. D. N. A. It means if the coding system has a has a following sequence of A then the the M R. N. A is going to have the sequence A. Two. If it is a G C. T then it is going to be G. C. You remember that you use your brazil instead of timing in the in the RNA. Okay, so that's the coding stand talking about a temporary stand. The temporary sent as its name says, it is useful as a template for transcription. So for example and it is going to have the complementary sequence than the M. RNA. For example. Let's give another example. Not this. Let's suppose the template is A C. G. D. A. Okay, so what will be the sequence of the M. RNA? As I mentioned, the template has the complementary sequence to the M. RNA. So the marinade, it's going to be that what binds what place a dining remember it pairs with uracil? So they're going to be in uracil uracil, G C. E. In you. It is going to be the aymara name. Okay. And if you want to know that coding a son for DNA, well it is going to be this sequence. But remember that with time instead of curiosity, it means that calling a son would be T T G C A. T. Okay, so with this knowledge let's transcribe this sequence. Okay, this is the first sequence. Um The question says that all the sequences they are providing us are the template DNA sequences. It means this is the complementary strand to the marina. So our marina is going to be the complementary strength to this. It means instead of tea it is a instead of G it is a C. Instead of a. It is you you the G a do g c c a U G G and you Okay. This is the M r n A produced from this template. A strand of the DNA. Now let's subscribe the next DNA sequence. Okay, as this is the template, the stand then the nitrogenous base that pairs with G. Is see the original space that with C. S. G. A nitrogenous base. That there's a your A C. The G A U U U. She U a n G. Okay. This is the M RNA produced from this is simply the strand of DNA.


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