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Consider the following solulions:1.8x 10 'M HzCO; 1.8 x 10 JM NaHCO; 1.8x 10 -M NazCO;For each of these solutions:list all possible species present write the e...

Question

Consider the following solulions:1.8x 10 'M HzCO; 1.8 x 10 JM NaHCO; 1.8x 10 -M NazCO;For each of these solutions:list all possible species present write the electrneutrality equation (charge balance) write short = statement (using complete sentences) that describes your approach for solving for pH draw' the appropriate pC/pH diagram write short statement describing one or more simplifying are justified. assumptions that you feel calculate the pH and concentration of all species.

Consider the following solulions: 1.8x 10 'M HzCO; 1.8 x 10 JM NaHCO; 1.8x 10 -M NazCO; For each of these solutions: list all possible species present write the electrneutrality equation (charge balance) write short = statement (using complete sentences) that describes your approach for solving for pH draw' the appropriate pC/pH diagram write short statement describing one or more simplifying are justified. assumptions that you feel calculate the pH and concentration of all species.



Answers

Calculate the concentrations of all species present and the $\mathrm{pH}$ in 0.10 $\mathrm{M}$ solutions of the following substances. See Appendix $\mathrm{C}$ for values of equilibrium constants.
(a) Ethylammonium nitrate, $\left(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{3}\right) \mathrm{NO}_{3}$
(b) Sodium acetate, $\mathrm{Na}\left(\mathrm{CH}_{3} \mathrm{CO}_{2}\right)$
(c) Sodium nitrate, $NaNO_{3}$

If we have a solution, that is 0.1 Moeller the base h o N h two. Then, to solve for the hydroxide concentration, we simply take the concentration of the base multiplied by the KP value which is given to us and take the square root of that. And we get 3.32 times 10 the negative five. This is definitely less than 5% of 50.1, so we don't need to use the quadratic. Then the pH is going to be equal to the negative log of the hydro knee, um, concentration, which is going to be the hydroxide concentration divided into K. W. And we get a pH of 9.52 for the next one. We have the conjugate acid to the base, so we need the K A value from the K B value. We divide the KB indicate W, and we get our K A of 9.9 times 10 to the negative seven. So the hydro knee, um, concentration will be equal to the square root of the concentration of the acid multiplied by the K A value we just calculated 3.2 times 10 the negative four, so pH will be equal to the negative log of 3.2 times 10 the negative four or 3.52 The pH of pure water, assuming it to 25 degrees Celsius and it truly is pure water is seven thin. The pH of a buffer solution that contains equal amounts of the weak acid in its conjugate base is going to be equal to the P K A. Of the weak acid. In this case, it's 6.4 p k a being the negative log of the K value and this being log of one which is zero.

So asked h r create the pH of each. So we have the concentration of its Jill. Um, so we know that the equation for a P H is equal to the naval vlog of the concentration of a trio. So what I'm gonna do is just plug them into a calculator. I see that if I plug in the or try to solve for the pH. Uh, when our HBO plus concentration is point girl for four, I plug in to my calculator. Negative log of 0.44 What, you have a name? 1.3565 Let me just double check that negative log. Uh, 0.44 Right. That's fine. So we did the same for it. A concentration of 0.45 That doesn't point 1.3468 and then not for your cage for last one is 1.337 two

So it's actually a pretty quick problem here. Remember, the pH is equal to in negative law of our concentration of H 20 plus. And so, since we're given this, it's really easy to find Ph. So, for our first scenario here, where are concentration H 20 plus equals 0.44 bowler. You can plug that into this formula and you'll find that pH is 1.35 65 I'm gonna write off two extra so that we'll see why that's important. Prince 0.45 Mueller, we have 1.3467 His point is your 46 Mohler. It is my apologies. 1.3372 And so take a look at what happens. So if we only tapped, for example, three digits overall, In other words, we cut it off here and we rounded. We wouldn't be able to appreciate the difference in the constellation here. Even worse if we decide. Oh, we only have Ah, Michael eyes mark that wrong? A common mistake is to think. OK, well, we have to significantly use here, so, um, we're gonna only keep two right here. And so then if we round, we're gonna end up with the values 1.31 point three 1.4. And this really, truly doesn't capture. The difference in the pH is on this makes appears. If there's only a difference of 0.1 when really work? Um, traversing a little bit more than that. And so, uh, rather it exaggerates it here, and it exaggerates the difference between these two, but under represents the difference. It's abuse to pieces. And so, in other words, instead of cutting it off after two significant figures of the pH, we do it after two decimal points, and then we can have pH. Is that really represent much more accurately what's happening?

So this is asking for the pH of strong acid solutions. PH is just negative log of the hydrogen ion concentration, so you really just take the negative log of all of these numbers. So for the 1st 1 you're taking the negative log of two times 10 to the minus two, which is 1.7, and then you just take the negative log of each of the numbers. And so for B, you get negative 0.6 and Percy, you get 11.


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