5

C>teneJr- <F GlaGel Hopatfelm Wum Emf;httpa;{ushzeridthezxpzntacon Common TakeTutoralAssignmantaspxaueate Md fctmlenle [ueonedlLeuLou culchmdideieu Houes ura$...

Question

C>teneJr- <F GlaGel Hopatfelm Wum Emf;httpa;{ushzeridthezxpzntacon Common TakeTutoralAssignmantaspxaueate Md fctmlenle [ueonedlLeuLou culchmdideieu Houes ura$ Reein Dute; 4uS 0a *Idop Prublemu J= A em [ % mnducedbv rjlalic ? ICCQ lut Randonird lnriables ta JVeDade; 423 70j? 1] * CO?N Egbb { ) CC Imagretle beldducale col yAmEent = mrWClic han Wr deredniePrcblem Stitas4 172 138 Em:iqamubed Tathe plingofen: cod Meniizl PaelaerEznz ; #eldenlinncttcd 5 beparIld ti: feleenet Doaic Ico3, Sulalehd

C>tene Jr- <F Gla Gel Hopatfelm Wum Emf; httpa;{ushzeridthezxpzntacon Common TakeTutoralAssignmantaspx aueate Md fctmlenle [ueonedl Leu Lou cul chmdideieu Houes ura$ Reein Dute; 4uS 0a *Idop Prublemu J= A em [ % mnducedbv rjlalic ? ICCQ lut Randonird lnriables ta JVe Dade; 423 70j? 1] * CO?N Egbb { ) CC Imagretle beld ducale col y AmEent = mrW Clic han Wr derednie Prcblem Stitas 4 172 138 Em:iqamubed Tathe plingofen: cod Meniizl Paelaer Eznz ; #eldenlinncttcd 5 beparIld ti: fele enet Doaic Ico3, Sulalehda ME ULO 1o5 3cd LSi | Ial ~ols Dan JJn TII FETEE: | fecdtatlilEOcucuFer [crozic Screenshot saved Ihe xrcenshol Wis adku OneDrive; One{Jnve Ee TyFe here searcr ARMO



Answers

If a 1 -megaton nuclear bomb were exploded deep in the Greenland ice cap, how much ice would it melt? Assume the ice is initially at about its freezing point, and consult Appendix C for the appropriate energy conversion.

So this question start asking, why doesn't freezing accord to the entire volume off a lake? So in this situation, the air at both the lake is below zero, and we need that out lake to be at zero degrees and has had enough energy to transform into ice. And because hit must be conducted from the water to cool, cool it to zero degrees. And because of face transition, the entire full volume off the water is not that face transition temperature. So on Lee, they they're a top part here, can perform in tow, tow ice. And that's because that's why the whole border for doesn't transform because you can propagate in left and there's you through the ice to make this part off the water to lose enough energy to tow toe past it. Face transition becomes our become ice now, in part to be, they ask you, ah, to derive a relation between the thickness off the eyes and the time it take toe to form this eyes. So let's walk to how we can do that. So the heat that must leave the water in the order to freeze must pass to this to tow this block of ice. So the larger this block is, the harder the hit who have to lower the heat. But they have to travel and worst, this process will become. Let's go see the section off the ice that has area cross sectional area A. So this Here we'll be the cross sectional area A and let at time t This has a height off hate. So eight as a friend Charity in a few days, more interval. So the tea we have, I think there's more sickness that it's the age and the mass off This infant is more block. Well, it will be. The M is equal to rule B V. We assume this density to be constant. So does this row. The cross sectional area is the same. The only thing that gross is this d h here. So this is a relation between the how much mass we have in a I feel it is more block here with the haIf off the block. This is just, uh, Cube. No, the heat must be conducted away from this mess off war to phrase it. So the Q is equal to the end. Well, if and we have This infant is more mass. LF is a lot of heat off the water there it is necessary to to transform Ah ah, War to toe ice. So this gives role. Hey! Oh, uh, the age. So here we have a relation between the heat and the height Now that we know how to ride the change of hate. So h is the change of heat is you could thank you. The t he hears time. This is ego too. The coefficient off the border the off the ice because the heat is propriety in the ice. So Ki I the cross sectional area the difference in temperature 30 age Manus called divided by page. That is the thickness off this block here So we can write this here Don't as the Q is equal to okay, I a the age minus the code times did he divided by age and we can't see that both off these expressions are for Dickie the Cube. And then we can just equal this true toa have a relation beating the H and ditty and integrating this relation. We've got ah, expression that relates the height to the time it takes to generate this this block. So let's do this. We can it quit both sides, so rule a Well, uh, the age is you go to K I A tea hot minus t code Bt over height This thes time we moved to apply in the left side in both sides by age toe pass this guy's toe here and integrate So let's right to they grow from zero to age It's the age physical Tok the age honesty cold rule l f interval from zero to t from the tea and here in the boundary condition at zero height we are at the time That's why both are zero here This is just AIDS square over too. And this is just a And because this hate square virtue will pass this to brother decided take square root So this gives us age is equal to the square old off two. Okay, I the heart dynasty code divided by row l f time screwed off time. So this is their relation that they want to tow Obtain that the the height is proportional to the square Root off fine at part. See, they want to tow to use his equation assuming that the difference in temperature is 10 degrees and from zero to Afghanistan and how much time it takes to form sheets that is 25 centimetres thick, so they want a five time. So to find time, we just, ah, square both sides and passed this so the other side, So equally we can write this equation, Steve, because eight square rule, huh? Divided by Chiu. Okay, I the hut minus c cold and let's play values that they give us so they want a sickness off 0.25. This is the death tee off ice and this is the Latin hit 3 to 4 times. All right, 24 times 10 to the Cube and Jew Times. They hit capacity of the ice and the difference in temperature zero minus manage. Stan is this equal to six points? There's to the fifth seconds. This is 107. The hours now for the last part, they want to know Ah, if the lake is full, different frozen. How much time it pigs, given that the latest foreign mirror sleep. So let's write the equation again. The is eight square root divided by two Hey, I the hot, minus T code. We assume the same difference in temperature and everything else the same. The only difference is this value here for square times 20 times 334 times. Man to the cube, divided by two times 1.6. I'm zero minus. Manage, Stan. And this is absurd number. This is 1.5 times tend to the 10 seconds. This is roughly 500 years, so it will not happen.

Hello students in this question we have given a cube of iron of density rho iron. It is equal to 8000 kg per meter cube And specific heat capacity of iron that is C iron. This is equal to 4 70 jewel per kilogram Calvin. Okay. Is heated to high temperatures supposed capital T. And it is placed on a large block of ice at the ice equals to zero C. Now cube melts and the ice blow it and displaced the water and things. So it means the volume of the ice block. This is equal to the volume of the iron block. Uh Sorry there are I for the balls. So this is supposed ice. Okay so volume for the iron block it is equal to volume of the ice or water displaced. Okay so we have to calculate this temperature t. So we have given the density and latent heat of fusion of the ice also. So we can right here that the heat lost by the iron cube, this will be equals to heat taken by the ice cube. Okay, so heat lost by the iron Q. Will be mass of the iron blurb. Specifically capacity of the iron mercury temperature difference of the iron and the ice is very large. So it will police heat or it will take heat by fusion. Okay, so mass of the ice. McLaren latent heat of fusion for the ice. So most of the ice will be density of the ice maker by volume. We suppose these two volumes are we and see I and delta. T. This will be equals to mass of the ice, will be density of the ice, mercury volume V. And mercury latent heat of fusion. So this volume will be cancelled out. So substituting the remaining value. So density of the ice is 8000 Modular-based specific heat capacity is 470 and temperature difference will be T zero. This is equal to density of the ice, which is nine 100 program per meter cube, and latent heat of fusion for the ice is 3.36 multiplied by 10 to the power five joule per program. From here, after solving the temperature T it is equal to 353 Calvin, which can be written as 80° integrate. So this becomes the answer for this problem. Okay, thank you.

Hello students in this question we have given four ice cubes of dimension to centimeter By two cm x two cm. Okay. Are taken out from the refrigerator that is initial temperature is 0° integrate of the ice cube and are put into Vol of the drink. It equals to 200. Okay so for the part we have to calculate the temperature of the drink when thermal equilibrium is reached. So first of all calculating the mass of the ice. So this will be equal to density of the ice maker by volume of the ice cube. Okay, so density of the ice is given as 900 program per meter cube and more player by volume will be this one cube. So too manipulated by two manipulated by two and this centimeter will be 10 to the power minus two m. And these are three so we can right here cube. Okay. And uh there are a total four cubes Summer player by four. So we get from here the mass of the ice cube. It is equal to 0.0 to double aid program. Okay, now we can calculate the mass of the drink similarly. So density of the drink market, volume of the drinks. The density of the drink is 1000 program per meter cube as further question and volume is 200 ml. That is equal to 210 to the power -6 meter cube. So from here, after solving most of the drink, it is equal to 0.2 kg. Okay, now we can calculate the heat required to melt the ice of Q. Ice will be most of the iceberg player be latent heat of their projections. So most of the ISIS 0.2 double eight kg. And latent heat of the reproduction for the ice is three point former player bait. And to the power five jewel per program. So we get from here. The heat required is 9792 jewels. So this much of ice is required to melt the ice completely. And the heat supplied by that bring it is equal to mass of the drink. Molecular. Be specific heat of the drink. Popular. Big temperature difference from we have given the temperature from 10 C to zero C. So 10 minus zero, initially zero. Okay. And the final is given as 10 C. So we get mass of the 20 0.2 kg. And a specific heat of the drink. That is water which is 42 double zero jewel per kilogram degrees, integrate. And this is equal to 10. So we get from here 84 double Jiro jewel. So it means the heat supplied by the drink. Is this 84 double zero jewel, but require heat by the ice to melt completely. Is this value? So it means we have given us, it is less than Q. Eyes. So it means ice will not be completely melt. Ice will not melt. Okay, So if ice is not melting then the equilibrium temperature, equilibrium temperature t equilibrium. This will be equal to zero C. Okay, so this becomes the answer for the part of the problem. Okay, no solving for the part B in which we have given that that if IsIS not melted then the amount of mass melted of the ice. Okay melted. So the heat supply is us and this will be utilized to melt the ice of mass. I am Butler be latent heat of protection for the ice accuse supply is 84 double zero jewel by the drink. And this is mass of the ice melted marble. Herbal latent heat of a production is three point former Player B. And to the power five jewel per program. So from here mass of ice melted. This is equal to 0.025 Kg, which can be written as in the ground. So mass of ice melted, it is equal to 25 g. So this becomes the answer for the part b of the problem. Okay, thank you.

In this exercise, we have an accent whose men brain has an area of five times since of this minus six meter square, and the thickness of the of the membrane is not his age. Time sensitive minus nine meters and the electric constant copper of the membrane is six in question. A. We have to treat the accident as the excess membrane as a parallel plate capacitor and calculate the capacitance off the memory. So remember that the capacitance all the parallel plate capacitor, is equal to Kappa Times, the area of the surface divided by four pi times. The combs constant K times the um copy six a is five times said to the minus six meters squared. But it before high times comes constant, which is nine times into the nine Newtons meter squared Brooklyn Square times. The which is a time center, the minus nine meters. So the capacitance C is equal to three point 32 times 10 to the minus eight Ferret in question be we have to suppose that the potential difference across the membrane Delta V is equal to 0.8 votes, and then we have to calculate the magnitude of the charge. Uh, that is on each wall. The memory. Remember that the capacitance C is equal to the charge divided by Delta V. So this means that the charge on H membrane on each wall will be see Time's out of E. So that's three times 32 times 10 of her 3.32 times sent of the man is eat Farid times your 0.8 vote. So the charge is 2.7 times sent them on his nine goals. This is the magnitude. Ah, the charge on each wall on questions. See, we have to conquer lead. Ah, the energy that's needed to charge the capacitor. So basically, this is the energy ah, store in the capacitor when it's fully charged. So that's just see times v do. I did, uh, by actually it's on lea si Times e. It's C C times the square divided by two. Um, this is the energy. So the capacitance, as we calculated, is 3.32 times 10 to the minus eight ferret ah times the potential difference square to it. 0.8 square, divided by two. So the interview that stored is equal to 1.6 times 10 to the minus 10 jewels in question D. We have to calculate the magnitude off the electric field across the membrane. So the the electric field just to separate it from the energy I'm gonna use a prime here, so we prying for the tactics you'd is equal to the the potential V divided by the thickness of the memory D So this is your points your weight divided by ah eight times Stand to them on his nine and this is 10 to the seventh votes per meter. This is the magnitude of the electric field in question e. We have to calculate the the energy store in this field so you know that the average is stored in a magnetic field is equal to Kappa times the magnetic field square divided by eight pi. Okay, so this is six times the magnet Matic magnetic field square. So that's sent to the 14th Ah, vote square meters squared, divided by, um, age pi times Coombs costs. And so that's nine times Stand to them. I does not happen in search of the Nine Newtons meters squared birth film square. So this is equal to 2.65 times 10 to the third use for a cubic meter. And I'm questions. See, you have to calculate the total energy that's stored in this feud by multiplying the that energy density you, by the volume V off the other the membrane. So I noticed that the volume V of the membrane is equal to the area of the membrane times its thickness. So you v will be the unit area density you times eight times D. So this is 2.65 times 10 to the Third Jews per cubic meter times the area, which is five time stand to the minus six meter square times D, which is eight times 10 to the minus nine meters. So this is equal to 1.6 times 10 to the minus 10 shoot. That's the total energy that's stored in the electric field. And I have to compare this with the energy of questions. See, on the energy of a question. See, is 1.6 times 10 to the minus 10 juke. So basically they are the same. So the total energy that stored in the feud is the same energy that's stored in the capacitor, which makes sense, right? Um so the interviews are the same


Similar Solved Questions

5 answers
Define fn : R - R s0 that fn () = ez+for every n € N and1 € R: Determine
Define fn : R - R s0 that fn () = ez+ for every n € N and1 € R: Determine...
5 answers
Nlio" [2 points] Section 9.6 # 7: Determine the convergence of using the Ratio (2n) Test . If the Ratio Test is inconelusive, state and determine convergence withanother test,
nlio" [2 points] Section 9.6 # 7: Determine the convergence of using the Ratio (2n) Test . If the Ratio Test is inconelusive, state and determine convergence with another test,...
5 answers
Lct flz)#d a(z) I - 10Wiite ths ,omain < in interval notuti Fina 3(3) Find { (93)}. Write ation af orderrul pairs=hucuonfuuction un explain hyu8019 posicive Expouens onlySimaplilySiplify; 2V2u %455 $Writein tJje FOru
Lct flz) #d a(z) I - 10 Wiite ths ,omain < in interval notuti Fina 3(3) Find { (93)}. Write ation af orderrul pairs= hucuon fuuction un explain hy u8019 posicive Expouens only Simaplily Siplify; 2V2u % 455 $ Write in tJje FOru...
5 answers
A steel tape measure used t0 measure 10 m distance at temperature of 10PC. If it was calibrated at 220C , by what amount in m is the measurement incorrect?2.1* 10-31.1X 10?1.1X 10 413 * 10-31.1x10-3
A steel tape measure used t0 measure 10 m distance at temperature of 10PC. If it was calibrated at 220C , by what amount in m is the measurement incorrect? 2.1* 10-3 1.1X 10? 1.1X 10 4 13 * 10-3 1.1x10-3...
5 answers
Given the points A(-1,0) and B(2,3) in the plane, find all points C such that A, B and C are the vertices of a right triangle with a right angle at A and with IlACII = 2
Given the points A(-1,0) and B(2,3) in the plane, find all points C such that A, B and C are the vertices of a right triangle with a right angle at A and with IlACII = 2...
5 answers
An enzyme involved in the control of glycolysis isall of these enzymes control glycolysisaldolasephosphoglycerate mutasenone of the answer is correcthexokinase
An enzyme involved in the control of glycolysis is all of these enzymes control glycolysis aldolase phosphoglycerate mutase none of the answer is correct hexokinase...
5 answers
Quertion 25 Doyer Onbwerad#onplete theffollowing equation by writing the mojorproduct#ored DuliomNH;Wag Dueaor
Quertion 25 Doyer Onbwerad #onplete theffollowing equation by writing the mojorproduct #ored Duliom NH; Wag Dueaor...
1 answers
Answers are given at the end of these exercises. If you get a wrong answer, read the pages listed in red. The point that is symmetric with respect to the $y$ -axis to the point $(-2,5)$ is $.(\mathrm{pp} .)$
Answers are given at the end of these exercises. If you get a wrong answer, read the pages listed in red. The point that is symmetric with respect to the $y$ -axis to the point $(-2,5)$ is $.(\mathrm{pp} .)$...
5 answers
Determine the dissociation constants for the acids. Express the answers in preper scientific notation where appropriateAcid A: pX, 5.00.OI XI0-3Acid B; pK, 8.503,0 xiO-8IncottcctAcid C: pPX, -20incottcciWhich is the strongest acid?X10-?
Determine the dissociation constants for the acids. Express the answers in preper scientific notation where appropriate Acid A: pX, 5.0 0.OI XI0-3 Acid B; pK, 8.50 3,0 xiO-8 Incottcct Acid C: pPX, -20 incottcci Which is the strongest acid? X10-?...
5 answers
Use the vertex and intercepts to sketch the graph of each quadratic function. Give the equation of the parabola's axis of symmetry. Use the graph to determine the function's domain and range.$$f(x)=x^{2}+6 x+3$$
Use the vertex and intercepts to sketch the graph of each quadratic function. Give the equation of the parabola's axis of symmetry. Use the graph to determine the function's domain and range. $$ f(x)=x^{2}+6 x+3 $$...
5 answers
Cannler denetmalctFtaenemenes Faroosumolercarcipatedcnemica rengtnn DaculatMa55Euartnnt penoatteeaen SenentVout enskerhas the Contc Numbersign fcant d3t5040
cannler denetmalct Ftaenemenes Faroosumoler carcipated cnemica rengtnn Daculat Ma55 Euartnnt penoatt eeaen Senent Vout enskerhas the Contc Number sign fcant d3t5 040...
5 answers
How do plants control the direction of auxin movement?Group of answer choicesAuxin travels in the xylem and is actively transported in thedirection the plant needs it to goAuxin is produced at the top of a plant and moves in onedirection because of gravityTransport proteins for auxin are only located on the basal sideof the cellAuxin becomes positively charged and bonds to negatively chargedsugars in the phloem, travelling with them
How do plants control the direction of auxin movement? Group of answer choices Auxin travels in the xylem and is actively transported in the direction the plant needs it to go Auxin is produced at the top of a plant and moves in one direction because of gravity Transport proteins for auxin are only ...
5 answers
AADbCcx MaBbeclx AaBbCAABbCcl Aab nuubCcc tnnt Uut SubintChuptet 1? ond 1: ( $t A Murd %n Oo Eukla Judvuao # 4i Hum1 Rumn |Shosimu cAlcu #unu
AADbCcx MaBbeclx AaBbCAABbCcl Aab nuubCcc tnnt Uut Subint Chuptet 1? ond 1: ( $t A Murd %n Oo Eukla Judvuao # 4i Hum1 Rumn | Shosimu cAlcu #unu...

-- 0.020340--