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Synthesize 3-hexanone from propanal showlng tne mechanismtor each Step pointsnecessan reagents anc5| Shorathe mechanisnproduct of the followlng reactlon DqntsExcess...

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Synthesize 3-hexanone from propanal showlng tne mechanismtor each Step pointsnecessan reagents anc5| Shorathe mechanisnproduct of the followlng reactlon DqntsExcess H,o"

Synthesize 3-hexanone from propanal showlng tne mechanismtor each Step points necessan reagents anc 5| Shorathe mechanisn product of the followlng reactlon Dqnts Excess H,o"



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Devise a synthesis of each compound from $CH_3CH_2OH$ as the only organic starting material: (a) $CH_3CH_2C$= $CCH_2CH_2OH$; (b) $CH_3CH_2C$ = $CCH_2CH_20CH_2CH3$. You may use any other needed reagents.

Taking a look at general reactivity off our kids and all kinds in this podcast. So these sort of bonds are possible if we utilize the extra two p orbital's that we have present on our carbon atoms and so on. All keen is a double bond on an Al Qaeda is a triple bond. And here we're taking a look of some chemical transformations using an alky in structure. So our first chemical transformation we have h 30 plus in H 20 We generate alcohol structure. Next we have HBR hydrogen bromine. We have the edition about Brahman atom. Next, we have a L to h 20 generate the following product. Lastly, we have one more chemical transformation where, firstly, we treat with BH three and th and then our second start is H 202 on HR minus. What does yield is he following structure the primary alcohol

All right, So this is the the answer to Chapter twelve. Number eight, fromthe smith Organic chemistry textbook. Um, and so we're asked to, uh, draw the products when starting, try asshole cholesterol, eh? Which I've drawn up here. Ah, and labeled eh is treated with either excess hydrogen gas and palladium own carbon to give B or only one equivalent of palladium of hydrogen gas and palladium on carbon. Uh, give product. See? So, um, for for ease of looking at this, I've admitted the two other Esther side chains and I've only included the central Esther side chain, which is the one with the al Canes. And so, which is the only one that's going to react, Teo, to this hydrogenation reaction and the key part of this side chain, the part that's going to react is here. I'm underlining it in red. Right. So remember hydrogenation eyes going to add two hydrogen sze to an al keen bond on deduce that al ki ng to Al Kane. And so to get the product be with an excess of hydrogen gas, both of these Al Keane's, because again, remember this number to tells us that there there, too Ah, And so when treated with excess hydrogen gas, both of these al keens are reduced. And so we have completely saturated side chain here. And that's B um, and then for si ah, with only one equivalent of hydrogen gas on ly, one of the two possible elkins is going to react. And so, no, you I could get this product or you have the number six here and the number seven here. So this would be this would be your your first Al Keen of the two Alcan's was hydrogenated, and the second was not Andi. In reality, what you're actually going to get is a mixture of that, uh, and of the product where you would get sorry. Let me erase this. You get a make sure of that product on of this product where you have nine. We have nine C H two's here. Ah, and you have four. Foresee? Age two's here. Ah, and you you should get an even mixture of those two. Ah, because again, you're only using one equivalent of hydrogen gas and so only one Al Kane is going to be hydrogenated. The second part of this question asks us to rank thes products in terms of their melting point from low to high. And so the way to arrive at this answer. Ah, a starting try. Smokeless ride has to double bonds. Um, and so it has four fewer Hodgins ah, than any of these other two molecules. And so it's going to have the lowest melting point. A molecule C has one double bond, so its melting point is going to be intermediate. Teo and B Ah, and then my like you will be with no double bonds. Is thie heaviest molecule. And as the most hydrogen sze on DH, Therefore, it's going to have the highest melting point of the story molecules.

No.

Going on with the reactivity off Elkins and all kinds. So we have a few different examples to take a look at, so we'll jump straight into the first example that we have. So what we have is this starting material and then in the presence off P C I five, there are degrees south CIA. We found the following what we have ch three c c i to ch three. Let me have three equivalents of any NH two mineral oil and heat on what we form is an al kind. You have ch three C triple bond C H to have SP hybridized carbons associated with that triple bond. Next, what we have is ch three stage two c h be off to so again the same re agents of mineral oil Heat two equivalent of NH four plus we then generate our al kind against. We have C H three see triple bond C H without SP hybridized carbons while we're using all of those pill bottles. Now for our sad reaction, we have ch three c h v r c h two. We are using the same the agents that's have used all along to form or al kind, which is reminding ourselves or triple bond used with our SP hybridization. It's moving onto the final example. What we have is ch three c h double bond, C H two. Then we have the off to that gives us ch three c h p r ch to be off, have the addition off Burr mean We then have the same regents that we've used all along informing our al kind bond ch three c triple bond C H.


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