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Question

Acon ? X diided into two pars Section and Secion Tre plaintits lawsuia cainadthat Aile Dolentnltcnlca tere slclred seclicn while EYac * renlers were steered Isuction Fn dinavs [7? ocalion; Ol recunuy tunlcd apartm tnis Dovou Ihink thor ovidence ol & racal Leemd corcttona ntenence ASe Conplote (ntoutnRer Renters blackWhlleSection SectionROTE: With rosEuct Ini: dala @n con: durcd sansibve some Individua : butneinleni Gltslion beterindeestand some 2rdect relevani socal iSsU€ society ihrouqh t

Acon ? X diided into two pars Section and Secion Tre plaintits lawsuia cainadthat Aile Dolentnltcnlca tere slclred seclicn while EYac * renlers were steered Isuction Fn dinavs [7? ocalion; Ol recunuy tunlcd apartm tnis Dovou Ihink thor ovidence ol & racal Leemd corcttona ntenence ASe Conplote (ntoutn Rer Renters black Whlle Section Section ROTE: With rosEuct Ini: dala @n con: durcd sansibve some Individua : butneinleni Gltslion beterindeestand some 2rdect relevani socal iSsU€ society ihrouqh tu UsC Snenco hi; Catn Haliaeta analyts Plnase kann Ihls mind you conslolo Ie q uoston Periomm cn-scuare *es ton oqenelly datarmoe Mhara Ioat slatailo /72 efcence tnat black$ are less Ikely rente sachon (han secilon Ahnt Tan Unlun MRaun" Decrnapincun neu dutda Knal O-Vel 0l Ine ch-square hononunoil ( pzalue (Round three declmal placos nuedude



Answers

1. Encuentra la inclinación de la línea.
2x - 5y +5 = 0
2. Encuentra el ángulo entre las líneas y
3x + 2y -4=0 y 4x -y +6 =0
3. Calcula la distancia entre el punto (7,5)y la
línea y= 5 -x.
En los Ejercicios 4 a 7, clasificar la cónica y
escribir la ecuación en forma estándar. Identifica
el centro, vértices, focos y asíntotas (si
corresponde). Luego dibuja la gráfica de la
cónica.
4. y2 – 2x + 2 = 0
5. 02 – 4y2 - 4x = 0
6. 9x2 + 16y2 + 54x – 32y – 47 = 0
7. 2x2 + 2y2 – 8x – 4y = 9 = 0
8. Encuentra la forma estándar de la ecuación de
la parábola con vértice con (2,-3) eje vertical, y
pasando por el punto (4,0).

So here in this problem we are given that three identical point charges with magnitude plus Q. Having placed at three corners of a square of side L. Now we have to calculate the magnitude and the direction of the net focus on a point charge minus three Q. And this charge is placed at two positions. Basically there are two parts in the first part. This minus three Q charges placed at the center of the square. So at the center of the square. Now in the B part, the service charge minus trick, you is placed at the wakened corner of the square. So in both the part we have to calculate the magnitude and the direction of net force. So first of all, I will be drawing the Free world diagram for the case of one for the first case. So this is the Free World magnum for the first part and these are the three point judges plus Q plus Q and plus Q, not minus three Q charges placed at the center of the square. Then we have to calculate the net force and the direction unit force on the point charge trick. You know? Here we see that the force F one and F two are identical. So we can write that F one plus F two. It should be called to zero because these forces are identical and they're up there acting in the opposite direction. So their net some would be called to zero. So the left force, the net force would be called to. In this case it should be equal to the force F. Two. Now we have we can calculate this forced by using the column slope, which says that the force between two charges equals to one hour four pi epsilon nought Q one Q two over our square. So you can use this formula. So from her F net will be equal to 1/4 pi epsilon. Not times Cuban. We have Q. And Q. Two. We have three Q. We're just taking the magnitude. So no need to take negative sign here, divide by our square. So here are would be cool to this. Listen that is L over root two. So this distance would be L over route and it's squared. Now can simplify this and we will get our answer to be six Q square over four pi epsilon. Not elsewhere. So this is the net fall is a basic the magnitude of the net force acting on the point charge minus three Q. And its direction we can see from the free body diagram, its direction is towards the site. So this was the answer for the airport. The next day will be solving the B. Part. So this is a freeware program for the case be where this point minus three Q charges placed at the vacant position. Now we have to calculate the net force acting on this charge. Its net force would be the combination of F one, F three and F two. Now from the symmetry city of the figure, we can say that the force F one would be equal to F three and it should be close to here. Also we can use the same formula. So it will be cool too. 1/4 pi. Absolutely not times. Now here Cuban is Q only and Q. Do we have treat you divided by R squared R squared the distance between the discharge and discharges L. And head on to. The the reason is L. So it would be cool to elsewhere. And we're going to simplify this and we'll get our the result to be 3/4 Q square divide by pie. Absolutely not elsewhere. Next we can calculate this force F two so forth after is between the charge minus trick you and discharge plus you. So it would be called to 1/4 pi epsilon. Not Q times three Q divided by our square are square. In this case it would be cool to this distance. So this distances route to ill. So route to L and X squared. So from here we'll get the expression too weak. Three Q square divide by four pi epsilon not times to elsewhere. So this is the expression for F two. Now from here we can calculate the net force F net acting on the minus trickle charge. It would be called to no uh this F two plus. Now the since the force F one and F three are perpendicular to each other. So the combination let it be a country that have shown in the figure also. So if 13 would be calls to under route F 01 square plus F three square. And since a fun enough three hour same are equal so we can write this value as under route to. This is under route to. If one. Now we can add both these forces. If two plus infantry and F 13 we have under route to F one. So it would be called sooner F two. We have this much this value, cervical, plug it here. This is three Q square over four pi epsilon nought times to l square plus under route to. Now everyone we have this much. Where is this is a fun. So you can pack it here. This is 3/4 times Q square divide by by absolute not elsewhere. Now can simplify this and we'll get our answer to be three Q square divided by four pi, absolute note elsewhere. Times under route to plus or 1/2. So this is a net force magnitude of net force acting on the minus trick. You charge. Now, if you want to find the direction you can refer to, the figure direction would be acting like this. There's a there's a direction for the net force, so I hope you have understood the problem. Thank you.

So here in this problem we are given that three identical point charges with magnitude plus Q. Having placed at three corners of a square of side L. Now we have to calculate the magnitude and the direction of the net focus on a point charge minus three Q. And this charge is placed at two positions. Basically there are two parts in the first part. This minus three Q charges placed at the center of the square. So at the center of the square. Now in the B part, the service charge minus trick, you is placed at the wakened corner of the square. So in both the part we have to calculate the magnitude and the direction of net force. So first of all, I will be drawing the Free world diagram for the case of one for the first case. So this is the Free World magnum for the first part and these are the three point judges plus Q plus Q and plus Q, not minus three Q charges placed at the center of the square. Then we have to calculate the net force and the direction unit force on the point charge trick. You know? Here we see that the force F one and F two are identical. So we can write that F one plus F two. It should be called to zero because these forces are identical and they're up there acting in the opposite direction. So their net some would be called to zero. So the left force, the net force would be called to. In this case it should be equal to the force F. Two. Now we have we can calculate this forced by using the column slope, which says that the force between two charges equals to one hour four pi epsilon nought Q one Q two over our square. So you can use this formula. So from her F net will be equal to 1/4 pi epsilon. Not times Cuban. We have Q. And Q. Two. We have three Q. We're just taking the magnitude. So no need to take negative sign here, divide by our square. So here are would be cool to this. Listen that is L over root two. So this distance would be L over route and it's squared. Now can simplify this and we will get our answer to be six Q square over four pi epsilon. Not elsewhere. So this is the net fall is a basic the magnitude of the net force acting on the point charge minus three Q. And its direction we can see from the free body diagram, its direction is towards the site. So this was the answer for the airport. The next day will be solving the B. Part. So this is a freeware program for the case be where this point minus three Q charges placed at the vacant position. Now we have to calculate the net force acting on this charge. Its net force would be the combination of F one, F three and F two. Now from the symmetry city of the figure, we can say that the force F one would be equal to F three and it should be close to here. Also we can use the same formula. So it will be cool too. 1/4 pi. Absolutely not times. Now here Cuban is Q only and Q. Do we have treat you divided by R squared R squared the distance between the discharge and discharges L. And head on to. The the reason is L. So it would be cool to elsewhere. And we're going to simplify this and we'll get our the result to be 3/4 Q square divide by pie. Absolutely not elsewhere. Next we can calculate this force F two so forth after is between the charge minus trick you and discharge plus you. So it would be called to 1/4 pi epsilon. Not Q times three Q divided by our square are square. In this case it would be cool to this distance. So this distances route to ill. So route to L and X squared. So from here we'll get the expression too weak. Three Q square divide by four pi epsilon not times to elsewhere. So this is the expression for F two. Now from here we can calculate the net force F net acting on the minus trickle charge. It would be called to no uh this F two plus. Now the since the force F one and F three are perpendicular to each other. So the combination let it be a country that have shown in the figure also. So if 13 would be calls to under route F 01 square plus F three square. And since a fun enough three hour same are equal so we can write this value as under route to. This is under route to. If one. Now we can add both these forces. If two plus infantry and F 13 we have under route to F one. So it would be called sooner F two. We have this much this value, cervical, plug it here. This is three Q square over four pi epsilon nought times to l square plus under route to. Now everyone we have this much. Where is this is a fun. So you can pack it here. This is 3/4 times Q square divide by by absolute not elsewhere. Now can simplify this and we'll get our answer to be three Q square divided by four pi, absolute note elsewhere. Times under route to plus or 1/2. So this is a net force magnitude of net force acting on the minus trick. You charge. Now, if you want to find the direction you can refer to, the figure direction would be acting like this. There's a there's a direction for the net force, so I hope you have understood the problem. Thank you.

So here in this problem we are given that three identical point charges with magnitude plus Q. Having placed at three corners of a square of side L. Now we have to calculate the magnitude and the direction of the net focus on a point charge minus three Q. And this charge is placed at two positions. Basically there are two parts in the first part. This minus three Q charges placed at the center of the square. So at the center of the square. Now in the B part, the service charge minus trick, you is placed at the wakened corner of the square. So in both the part we have to calculate the magnitude and the direction of net force. So first of all, I will be drawing the Free world diagram for the case of one for the first case. So this is the Free World magnum for the first part and these are the three point judges plus Q plus Q and plus Q, not minus three Q charges placed at the center of the square. Then we have to calculate the net force and the direction unit force on the point charge trick. You know? Here we see that the force F one and F two are identical. So we can write that F one plus F two. It should be called to zero because these forces are identical and they're up there acting in the opposite direction. So their net some would be called to zero. So the left force, the net force would be called to. In this case it should be equal to the force F. Two. Now we have we can calculate this forced by using the column slope, which says that the force between two charges equals to one hour four pi epsilon nought Q one Q two over our square. So you can use this formula. So from her F net will be equal to 1/4 pi epsilon. Not times Cuban. We have Q. And Q. Two. We have three Q. We're just taking the magnitude. So no need to take negative sign here, divide by our square. So here are would be cool to this. Listen that is L over root two. So this distance would be L over route and it's squared. Now can simplify this and we will get our answer to be six Q square over four pi epsilon. Not elsewhere. So this is the net fall is a basic the magnitude of the net force acting on the point charge minus three Q. And its direction we can see from the free body diagram, its direction is towards the site. So this was the answer for the airport. The next day will be solving the B. Part. So this is a freeware program for the case be where this point minus three Q charges placed at the vacant position. Now we have to calculate the net force acting on this charge. Its net force would be the combination of F one, F three and F two. Now from the symmetry city of the figure, we can say that the force F one would be equal to F three and it should be close to here. Also we can use the same formula. So it will be cool too. 1/4 pi. Absolutely not times. Now here Cuban is Q only and Q. Do we have treat you divided by R squared R squared the distance between the discharge and discharges L. And head on to. The the reason is L. So it would be cool to elsewhere. And we're going to simplify this and we'll get our the result to be 3/4 Q square divide by pie. Absolutely not elsewhere. Next we can calculate this force F two so forth after is between the charge minus trick you and discharge plus you. So it would be called to 1/4 pi epsilon. Not Q times three Q divided by our square are square. In this case it would be cool to this distance. So this distances route to ill. So route to L and X squared. So from here we'll get the expression too weak. Three Q square divide by four pi epsilon not times to elsewhere. So this is the expression for F two. Now from here we can calculate the net force F net acting on the minus trickle charge. It would be called to no uh this F two plus. Now the since the force F one and F three are perpendicular to each other. So the combination let it be a country that have shown in the figure also. So if 13 would be calls to under route F 01 square plus F three square. And since a fun enough three hour same are equal so we can write this value as under route to. This is under route to. If one. Now we can add both these forces. If two plus infantry and F 13 we have under route to F one. So it would be called sooner F two. We have this much this value, cervical, plug it here. This is three Q square over four pi epsilon nought times to l square plus under route to. Now everyone we have this much. Where is this is a fun. So you can pack it here. This is 3/4 times Q square divide by by absolute not elsewhere. Now can simplify this and we'll get our answer to be three Q square divided by four pi, absolute note elsewhere. Times under route to plus or 1/2. So this is a net force magnitude of net force acting on the minus trick. You charge. Now, if you want to find the direction you can refer to, the figure direction would be acting like this. There's a there's a direction for the net force, so I hope you have understood the problem. Thank you.

We have questions are a lot of questions. Okay, so let us get started. This is where these questions are from the chapter of coordinate geometry. So let us disturb even in the slope of the line, we have to find slope of the line to work minus 51 five while plus five equal to what is it to? Okay, so we have to find the anger. No, I'm out of Oh it is zero. Yes. So we have to find the slope of the line. So let us write this in the form of white people too. Mm max you'll see that. It's slogan, just have fun. It would get very easy. It will become very easy. So my wife went to two X plus five. Let us divide both sides by five. We will be getting So I controlled by five X. Yes 555 So why would they call to to wear five X plus one? He compared these two. Mm becomes frequent to buy five. So slow equal to too bad side. Okay, so problem number two, we have to find the angle between the lines. The express two m minus four. Equal to zero and four x minus y. Let's fix the qualities you know. Okay, so let us right it's slope So its slope will become equal to just like in trouble. Number one slope will become equal to minus three by two. And I am too because but the slope has four. We have to find a go between this. We have to use formula that can take two models of uh and one minus and two by one place and one and two. So then Pita will be equal to one minus them too minus three by two minus four divided by one. Last minus three by two and four. So 10 to will be equal to minus 11 by two. Well, when my nest 12 by two Dante town will become it into this is minus 11 by two divided by mine is fine. 11 by dan more. We can just let it be like this to get there to dangle. Okay, so it is like modern a problem. So 10 3 there will be equal to plus minus 11 by 10, 11 by 10 minus 11 by 10. So you can easily see that there would be too angles. So one is acute angle wanted obtuse angle. So if you take positive, that is 11 by 10 and they were taken to peter the universe 1.1 that is 47.7 degrees, approximately 47 point seven degrees. This is a good angle and if you take minus one point when it will become, it will become 180 minus this. So 130.132 points 17 So anyone can dance? This is this was question number 32 No question number three is okay. We have to find distance between 0.7 point five. And like this uh manage y equal to five minus six. It described it as X plus y minus five equals to zero. And we appoint 7.5. So we have to be collected. Formula does this line in the X plus B, Y U c 1 to 0. And the point is alphabet to. So the distance formula the formula to find particular distance it is alpha the baby to plus the divide by a squared plus B squared with models. Well it is again just plugging in the values. It is one, B is one, so one into this is alpha. This is 0 to 1 into 77 plus one in +255 and ch minus five. The venue is where that is one squared plus months. But the route the model of science these two billion cancel out they will be equal to 700 to and if you displays by sliding factors to be getting deep into 702 by two. Okay. This is the answer for question number three. Okay. No question number four we have to classify the chronic and right exists in their farm only. Just All right question. Which is why square minus two X plus 24 to 0. Let us write it as was quite equal to two. An X line is too Okay. This is in the form of why minus. Okay, what's critical to for a x minus X. Which is a parabola with vertex at karma K. That is at his too and K is zero. You can okay. Its focus will be you have to find focus also and this Parabola will be writing Parabola. Okay, so before trying the focus we should destroy it. This is X. This is why we're texas two comma zero so X equal to equal to zero and can committed is like this. So focus will be business sense, that is to and focuses in common zero. So four years to equals to two. So he's one by two. Focus will be to class one by two. Common zero five by two. Armadillo. Okay. And uh but actually all they found out center, it doesn't have centers. Okay, no problem. This completes our a problem in the fourth now, problem number five. Okay, right. But remember frank is in that period. Okay, well since this is not clear what it is probably one birth six. Number five of the problem number five this is mhm Y square minus four Y squared minus four acceptable to 04 letters is u minus four. Y squared minus x minus four Y squared minus products. Let us assume minus four X. But a great family please. Okay got it. This is number five days access squared minus four Y squared minus four X equal to zero. So let us write it as four wives choir equal to access but I haven't minus 40. Okay. Okay but we should original like this. This is economic ellipse. That's where I'm sorry Hyper Ebola square minus four X minus four virus particle to zero. So x minus two. We're completing the square minus four minus four by spike 20 which means x minus school hold square minus four was quite equal to four and it is divided four. We'll be having ex minds to hold squared by four minus weiss but equal to one. So this is uh wanna spend in this situation. It is in the form of x minus that whole square by is burn. Why men scare hold square by square equal to one? This is happen bola. This is the standard form. Okay, so center will be at the Mackay. That is true camera zero. Okay. And what all things we need to find. So let's first financing told to find the same to let us equity is equal to zero. So why square by there will be able to x minus stool by two foursquare. Okay so why squaring equal to x minus two balls? But by 14 to 12 few times. So the equation of the sum total will be white. 12 to plus minus that would be x minus two. Okay. Okay. For he we need to find the focus first. Let us draw it and then we're finding a good thing busy. The vortexes. The center is two comma zero. So latest rights until two comma zero. Okay, sometimes two comma zero and being uh if centers do comma zero so its verdict will lie on X axis. Why should be equal to zero? If y becomes equal to zero we would be able to find the vertex easily. Oh in a standard education or given a question that explaining why it fell to zero access choir minus four X will be equal to zero. X equals 504 Okay, this is bull. This is zero. Hyper bowler would look like this and the bar pieces are what is his er two comma zero? Sorry, this is not a verdict. This isn't what? This is a, this is zero comma zero and four comma zero, zero comma zero. And for common these are the these are the partisans. Okay. And now we have follow number seven. Yes. Um This is problem number seven is. Mhm. To access where? Mhm. Just two wives choir minus eight X minus four. What? Bless nine ar minus nine. Yeah. People to zero. So this looks like a circle. Yeah. Uh huh. Religious. Take these to let subscribe minus a death. Let us collect these two blessed to I square minus four while minus 94 to 0. We can easily see that this is happening because coefficient of accessible and widespread at the same and there is no terms containing X. Y. But to write in a central fund let us stay to his comment, express quiet or minus four X. Place to my spine minus four Y minus nine equal to zero. So this will become two X. Minds tools square mines forward less too Y minus two was birth uh minus four minus nine equal to zero. If you divide both sides by two, you'll be getting x minus two whole square minus four. Yes. Why am I still hold square minus school minus nine by two weeks till 20 So basically x minus two holes. Where here's why minus two holes were equal to. And if I parent. Yeah. So this is circle for the question is excellent. Such full square plus y minus K hole square equal to ask. So in this case center at com A. K. That is to camera two. So this is the center them. We have to find. If you find variants, radius will be into this five. Fire under two or after a civilization. It will be 502 by two. These are the two things in the second. Okay, now we have we have to draw the circle to comment with the center. This is X. This is right. Let us support this thing to come out to to come into and radio says 502 or five or to buy 25 to 33.53 Oh thanks. Has to be like this. Okay. Okay. Number eight. Follow Number eight is we have to find the standard form of the equation of a Parabola with vertex. This word, sex, age two comma minus three and excessive vertical and passing through for common zero. Let us drive first, Vortex. Look on on minus three. This is X. This is why two comma minus tape. So this is two comma minus three vertex article minus three and it is passing through four comma zero. Oh, okay. And excess in particular it is given. So Parabola. Well, look like this. Okay, so let us get started this form of the parable level building at x minus X was equal to for a y minus. Okay, let's plug in the values where taxes to color minus three. Access to wise minus three X minus two. Or spirit clinton or a. Why? Bless the. Well we have to find this value for 14 for this. It is passing through four comma zero. So that is plugging X equal to four. And why pull 20? So for a will become equal to basic four pi three. Okay for battery. So let us play in here. You'll be getting the standard equations at minus two holds political too four by three. White. Bless you. These are the answers. Thank you.


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points) What starting materials will undergo Diels-Alder cycloaddition give the following? OH points) Provide the structures the major products complete each transtormation. enantiopure (contradipolar)...
5 answers
2 Sketch f"(x) of the above function and determine equation_f"(x)
2 Sketch f"(x) of the above function and determine equation_ f"(x)...

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