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Hezyr akd Jueneta 3HA Ienlnleas netd Ke-Jan oH941214X4 1/+ 3 |2 4431 ~-3<Xn0Am Lzuez 7x7 E(1+ dd)...

Question

Hezyr akd Jueneta 3HA Ienlnleas netd Ke-Jan oH941214X4 1/+ 3 |2 4431 ~-3<Xn0Am Lzuez 7x7 E(1+ dd)

Hezyr akd Jueneta 3HA Ienlnleas netd Ke-Jan o H941214X4 1/+ 3 | 2 4431 ~-3<Xn0 Am Lzuez 7x7 E(1+ dd)



Answers

The $K_{\mathrm{sp}}$ of $\mathrm{Cu}\left(\mathrm{IO}_{3}\right)_{2}$ is $1.4 \times 10^{-7} .$ Calculate the $E^{\circ}$ for $\mathrm{Cu}\left(\mathrm{IO}_{3}\right)_{2}(\mathrm{~s})+2 \mathrm{e}^{-} \longrightarrow \mathrm{Cu}(\mathrm{s})+2 \mathrm{IO}_{3}^{-}(\mathrm{aq})$

Yeah We need to find one by one into three plus one by three into five Plus one x 5 into seven. This daughters into don't think that it is decimal. It's not 1.33.5 it is into so on. One by two and -1 into 2 1 plus one. This is a simple quick This I can write it as half of 1 -1 biting. And the next time the second write it as half of one by G -1 x five. And the next time I can write it as half of one by five minus one by seven. So on and so forth. Till half of the last time I can write it has won by two in minus one minus one by to one person. Half is common everywhere. Swag get 1 -1 x three Plus one by the -1 x five plus one by five minus one by seven so on and so forth. One by two N minus one minus one by two N plus one. Now if you can see all the terms gets cancelled like this, Even this gets cancer. So what remains is one line? This is the answer is half of 1 -1 by 20 plus one. Now, taking them inside becomes to end by 20 plus one, so the final answer is N by To win plus one.

In this problem, just look at it carefully. BB I too, will react in pageants of BSE here, too. ECU was to give compound Are we change which aid 80 cl here, which it A d c L. Here? So this is white PPT. They said white PPT. Therefore, according to the option option, age, correct and said for this problem, A d c l a will be the white PPT in this problem.

Chinese solution when directed with stool and avoided give some right sector own additional access this compound. So could you inform general which hard place here's the correct terms.


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