5

Complete and balance the chemical equationPb(NO3)ziaalKzCrOalaa}Write the balance molecular equation and indicate whether it is (s), (IJ, (g) or (aq)Write the ionic...

Question

Complete and balance the chemical equationPb(NO3)ziaalKzCrOalaa}Write the balance molecular equation and indicate whether it is (s), (IJ, (g) or (aq)Write the ionic equationWrite the net-Ionlc equatlonWhat are your spectator ions?

Complete and balance the chemical equation Pb(NO3)ziaal KzCrOalaa} Write the balance molecular equation and indicate whether it is (s), (IJ, (g) or (aq) Write the ionic equation Write the net-Ionlc equatlon What are your spectator ions?



Answers

Complete and balance the following equations. For each, write the molecular, ionic, and net ionic equations. (All of the products are soluble in water.) (a) $\mathrm{HC}_{2} \mathrm{H}_{3} \mathrm{O}_{2}(a q)+\mathrm{Mg}(\mathrm{OH})_{2}(s) \longrightarrow$ (b) $\mathrm{HClO}_{4}(a q)+\mathrm{NH}_{3}(a q) \longrightarrow$ (c) $\mathrm{H}_{2} \mathrm{CO}_{3}(a q)+\mathrm{NH}_{3}(a q) \longrightarrow$

So for this problem, we're gonna want to look at the diagrams in the book. But we do it. We want to write some balance equations am find what the Net ionic equations are so that we can identify any spectator ions. So let's start with a so first looking at the different Adams and compounds we have in this diagram, we're going to write a balanced chemical equation. So we know this to be see you is so fine, that is Equis. And we're just adding the states so that we can a little bit better see what the different components are that we're working with. So now that we have this falling balanced equation, we can look at the different parts and see what can be split into different ions. So we know that you split this up. He's put this up. You can't split this up, but we can also split this up, which means that we're going to see the this component cross out with this component and are so Diem's cross out in this component. So that being said, we can go ahead and write or net Ionic equation now going to do so in a different color student read. So we know, based on what we had left after we crossed now and expect Peter ions is our solid product. I am base on what we know that we crossed out. We know that we crossed out for Spectators. We crossed out in sodium, then in s 04 tu minus. And based on the corresponding colors, we know that the spheres for sodium or gray and the color spheres for this one are blue. Okay, so we're gonna work on our next problem now. And in order to do so, we're gonna look at the diagrams again because this is gonna be what we're balancing our equation off of and how writing the equation. So we're gonna go down a little bit so much so we have room to do be And four b looking at the diagram, we could make the following chemical equation Cool boat, chlorine. Aquarius. You know, show how I balance this as well, so you can understand what we're doing. Just kind of write it out so that we can see regard. So you know, chloride, which is just a table salt and is Aquarius. Okay? So when looking at balancing this. I knew that we were going to need a two because not only do we have to all Christians here and the products we also have to hydrogen and the O. H is together in sodium hydroxide or reactions. So by adding a coefficient of to here to match the O. H. On the product side, I had to Sodium is on the reactive side and only one on the product side. So that's where this second to came in from. So now that we have more fully balanced equation, what we can do next is go ahead and look at doing see net Ionic equation. So we know we have a seal on this side and on this side we have two on each side. So that means that the chlorine is going to inspect your eye on that. We can across out, and the sodium is going to be the same. We have two on each side. It's gonna be what we cross out. So writing what we haven't crossed out, we have cobalt two plus plus two hydroxide, and then we're gonna leave are solid because we couldn't break that up into ions and that's what stays. So we found our Spectators to be sodium again and the Corina, and based on the colors we know the sodium is gray Claure is going to be green First fears And now we can we want to do the last down a little bit more so much. Okay, so we're gonna look again of the diagrams so we can make our fully balanced equation Gonna right. The suasion itself equally is Tess, you IOD i e quiz and then looking, we have so her eye nine. And this is a solid which is important when we're looking at our net Ionic a second my Casio tricked And this is a quiz, and this is the three. So if we look, we know we're gonna be able to cross out Not only are nitrogen is but our oxygen's. So these are gonna be spectator ions, and then our potassium is also gonna be Spectators. So that means we can go ahead and do silver. It's the dine is gonna give us our solid product that we couldn't break up into its ions. And so when we're looking at spectator for this one, we saw that it was that potassium that we talked about talking out that are no. Three months. And we find that the past, um, is red and then we have blue here.

To write the balanced formula and that Ionic equation. The first thing you need to do is I is right, the balanced formula equation and then from there, identify the spectator ions. Eliminate them and what's left is theme net ionic equation. So if we have a beaker with sodium sulfide and a beaker with sodium sulfate and we mix them together, I'm sorry. Sodium sulfide and copper to sulfate, and we mix them together. The copper to sulfate and sodium sulfide will potentially react with each other, forming a precipitate if there is an insoluble product. The insoluble product according to sell ability rules, is copper to sulfide, while sodium sulfate is still soluble. So the complete Ionic equation is where we take everything that's soluble. That's not a solid and separated into their corresponding ions. When we do this, we still have the calcium. I'm sorry. The copper to sulfide together is a solid. We find sodium on both sides to sodium zahn both sides of the equation. This is one of the spectator ions, and in the figure it's gray in color, and sulfate is another spectator ion, which in the figure is green. Once eliminating the spectator ions. What's left is the Net Ionic equation. Copper two plus reacts with sulfide producing copper to sulfide. The next problem shows a beaker with sodium hydroxide and copper to sorry. Cobalt to glow ride so cobalt to chloride and sodium hydroxide. Servas the reactant. When the cat ion switch places, we end up with cobalt to hydroxide, which, according to sell ability rules, is insoluble, so it's a solid and sodium chloride. To balance it, we need to put a two in front of the sodium hydroxide and a two in front of the sodium chloride. Then, to get the complete Ionic equation will separate everything that is soluble into its ions. Cobalt to chloride will produce one cobalt two plus and two chlorides to sodium hydroxide will produce to sodium XYZ and to hydroxide. The copper to hydroxide will stay together is a solid, and the two sodium chlorides will produce to sodium zand to chlorides. We see the sodium XYZ. Two of them are comment herbal sides, these air spectator ions, which in the picture are gray, and then the chlorides are spectator ions, which in the picture are green, removing thes spectator ions. We have copper two plus reacting with two hydroxide is producing. Like I said, copper again. Cobalt two plus reacted with two hydroxide producing cobalt to hydroxide solid for the next one, we have silver nitrate and potassium iodide. If we were to mix the contents of these two beakers together the silver nitrate and the potassium iodide could servas react INTs when the cat ion switch places will potentially produce potassium nitrate and silver iodide. If one of these is insoluble and according to the soluble ity rules, silver iodide is insoluble. So this is our solid precipitate Well, then separate everything that is soluble into its ions and get one potassium. When I died, one silver, one nitrate and then on the product side one potassium, one nitrate and then our silver iodide solid so you can see that potassium is common to both sides. This is a spectator ion, which in the picture is red and then the nitrates, which are common to both sides in the picture. They are blue, eliminating the spectator ions, then gives us the balance net Ionic equation of one silver acquis reacting with one iodide, acquis producing, producing silver iodide. It's solid

From each beaker. Let's right, the balanced equation and the formula or the Net Ionic equation that results and also indicate the color of the spectator ions. For a are balanced equation, we have first speakers copper sulfate. Second beaker is sodium sulfide, and this would produce a precipitate of copper sulfide and sodium sulfate, and this is balanced as it is. Our Net Ionic equation will be copper two plus so five to minus, producing a precipitate of copper sulfide and our spectator irons will be any plus, which is a gray color and s 04 to minus, which is a blue green color. For the beakers and be way have cobalt chloride mixed with sodium hydroxide. This will form a precipitate of Cobalts hydroxide and sodium chloride. Balancing this to in front of the H two in front of the CLN. There's are balanced chemical equation. Our Net Ionic equation is Cobalts. You plus 20 H minus to produce cobalt hydroxide, and our spectator ions will be any plus, which is the grace fears and C l minus, which would be the green spheres. Okay, where the beakers in reaction. See, we have silver nitrates in the first speaker with potassium iodide in the second beaker, the sort producer precipitate of silver iodide. And we have potassium nitrates. This is balanced net. Ionic equation will be a B plus by minus, producing a precipitate of silver iodide and our spectator ions, or B potassium iron, which is red, uh, in color, the red spheres and the N 03 minus ions, which are the blue spheres.

Balancing the molecule Immigration for option A. So it is be to itch br les c A Which two give me C A br two plus two moles off water on dhe. The Net Ionic equation will be ej positive unless which negative wouldn't give me. It's true. Secondly, option B the balanced, more legal immigration fortune be will be to ej c l 04 Give this See you seal or for two, unless toe edge to go on the net I nick aggression will be. See you. Which two plus two h positive. Give me Cooper to positive less two molds off water or Option C. It is you. Which three plus three moles off a journal. Three leaving us you and no. Three Three Yes, three h 20 and find it. The net Ionic equation. Really be hell. Which three less? Three h positive. Well, give us aluminum tree for the divine along with three. Mold off. What


Similar Solved Questions

5 answers
The one-to-one function } is defined below_fW) = Vsr -Find,(r), wherethe inverse 0f /.Ai 3 F a A
The one-to-one function } is defined below_ fW) = Vsr - Find, (r), where the inverse 0f /. Ai 3 F a A...
5 answers
1. BH;: TH? Tenet 7 eeen 2 Om.H,0.H0b83;CKC}P#C
1. BH;: TH? Tenet 7 eeen 2 Om.H,0.H0 b 83; CKC} P#C...
5 answers
8 612 [ dx +3 4x + 5
8 612 [ dx +3 4x + 5...
5 answers
DetailsConsider the following function_ F(t) 235 _ Sc3 Find the derivatve the functon_ Ft) 1544 1522answers as comma separated list.) the critical numbers of the function (Enter your Find(If a answer does not exist, ente relative minima if any, of the function. Find the relative maxima andrelative maximum(x,Y)relative minimum(x, Y)Viewing Saved Work Revert to Last Response Submit Answer
Details Consider the following function_ F(t) 235 _ Sc3 Find the derivatve the functon_ Ft) 1544 1522 answers as comma separated list.) the critical numbers of the function (Enter your Find (If a answer does not exist, ente relative minima if any, of the function. Find the relative maxima and relati...
5 answers
Find the Laplace transform of each of the following:fo, a) f() = {2t,t < 2 t22b) f(t) = sin t , cos tt < 41 t 2 4Tc) f(t) = ezt sin Zt
Find the Laplace transform of each of the following: fo, a) f() = {2t, t < 2 t22 b) f(t) = sin t , cos t t < 41 t 2 4T c) f(t) = ezt sin Zt...
5 answers
4enmnent Score:43.19Ru-Duc GheckamJeslion8 04 10Frole si hxuseball pitchetx celiser pilehc > Uhat Kt plui = smedof A(U mph (mik M rnuuh az Hmal ~RLIL-cming Ielt-hiutkd pitcler #lo can esistcnly pitch 41557 ms (4],() url 4asuminz pircte | bul and hus this ~cd jusblone baller Iike" CNU:k | with Iix Much Aueric LIktgy trU: ball have"KtalKecnll that Uic accelerution due Ert Ite Sm- mach #luthc enetit did xhzn pilche l (eglect Tesnncchdnntn ImnFMNwunGDALL
4enmnent Score: 43.19 Ru-Duc Gheckam Jeslion8 04 10 Frole si hxuseball pitchetx celiser pilehc > Uhat Kt plui = smedof A(U mph (mik M rnuuh az Hmal ~RLIL-cming Ielt-hiutkd pitcler #lo can esistcnly pitch 41557 ms (4],() url 4asuminz pircte | bul and hus this ~cd jusblone baller Iike" CNU:k ...
5 answers
0/2 points Previous Answers WaneAC7 3.4.013.Calculate the averagechange the glvon function over the qiven Interval. Wnero appropriate; specify the units measurememk [5, 8]HannnHTele u EiTubot
0/2 points Previous Answers WaneAC7 3.4.013. Calculate the average change the glvon function over the qiven Interval. Wnero appropriate; specify the units measurememk [5, 8] Hannn HTele u EiTubot...
5 answers
Use the definition to show that the 3 sin(n) sequence Xn = + converges to n n +1 zero_
Use the definition to show that the 3 sin(n) sequence Xn = + converges to n n +1 zero_...
5 answers
Complete the equatkn for the piccewise functlon erected belowM-0<2< 3m-0<<202 <7 <6
Complete the equatkn for the piccewise functlon erected below M-0<2< 3 m-0<<2 02 <7 <6...
5 answers
Computing gradients Compute the gradient of the following functions and evaluate it at the given point $P$.$$g(x, y)=x^{2}-4 x^{2} y-8 x y^{2} ; P(-1,2)$$
Computing gradients Compute the gradient of the following functions and evaluate it at the given point $P$. $$g(x, y)=x^{2}-4 x^{2} y-8 x y^{2} ; P(-1,2)$$...
5 answers
Untlled GraphdesmosLoainS9n UpJ=I5T=3025)" + 8J=[HAvZJ= 2 sinr + [1X(0,11)X"vrX1=15
Untlled Graph desmos Loain S9n Up J=I5 T=30 25)" + 8 J=[ HAvZ J= 2 sinr + [1 X (0,11) X "vr X 1=15...
4 answers
The following nonlinear Equation: f(X)= e^x + x + Cvalue of C=-42a) Plot the function Using MATLAB software and find from the graph the approximated value ofthe root.b) Determine the root (in the domain x[0,4]) and the approximate percent relative errors for your solutions, using: Bisection method (four iterations) and Newton-Raphson method (two iterations Xo-2)
The following nonlinear Equation: f(X)= e^x + x + C value of C=-42 a) Plot the function Using MATLAB software and find from the graph the approximated value of the root. b) Determine the root (in the domain x[0,4]) and the approximate percent relative errors for your solutions, using: Bisection meth...
5 answers
Absorbs 20905 J of energy what is its final {75.0 g of water at 15.0oC in OC? Water has a specific heat of 4.2 Jlg"C. temperature140
absorbs 20905 J of energy what is its final {75.0 g of water at 15.0oC in OC? Water has a specific heat of 4.2 Jlg"C. temperature 140...
5 answers
Light is incident from water (n=1.33) at an angle of incident of30 degrees onto the glass (n=1.52). After traveling thru the glassto the opposite parallel side, the light emerges into the air(n=1.00). What is the angle of refraction, with which the light istransmitted into the air at the second surface?
Light is incident from water (n=1.33) at an angle of incident of 30 degrees onto the glass (n=1.52). After traveling thru the glass to the opposite parallel side, the light emerges into the air (n=1.00). What is the angle of refraction, with which the light is transmitted into the air at the second ...
5 answers
Study the convergence ofIn(r) Jo 3572 dz,and If the integral is convergent give its value. A1) The integral is Click for ListA.2) Assuming it is convergent; its exact value is Write 333 if the integral is divergent: B) Study the convergence of In (r) dz, 25/2 and if the integral is convergent give its value_ B.1) The integral is Click tor ListB.2) In the hypothesis where it is convergent; its exact value is Write 333 if the integral is divergent:
Study the convergence of In(r) Jo 3572 dz, and If the integral is convergent give its value. A1) The integral is Click for List A.2) Assuming it is convergent; its exact value is Write 333 if the integral is divergent: B) Study the convergence of In (r) dz, 25/2 and if the integral is convergent giv...

-- 0.024441--